{"id":13049,"date":"2022-10-27T13:33:45","date_gmt":"2022-10-27T13:33:45","guid":{"rendered":"https:\/\/www.splashlearn.com\/math-vocabulary\/?page_id=13049"},"modified":"2024-01-01T16:04:04","modified_gmt":"2024-01-01T16:04:04","slug":"circumference-of-a-circle","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle","title":{"rendered":"Circumference of a Circle"},"content":{"rendered":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-d01d9fb9-b3c0-4482-a53d-4b408ace14f7\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle#0-what-is-the-circumference-of-a-circle>What is the Circumference of a Circle?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle#2-diameter-of-the-circle>Diameter of the Circle<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle#3-radius-of-the-circle>Radius of the Circle<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle#8-solved-examples>Solved Examples<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle#9-practice-problems>Practice Problems<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle#10-frequently-asked-questions>Frequently Asked Questions<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"0-what-is-the-circumference-of-a-circle\">What is the Circumference of a Circle?<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We see many circular objects daily, such as coins, buttons, wall clocks, wheels, etc. The boundary of any circular object has great significance in math.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"424\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/examples-of-circles-around-us.png\" alt=\"Examples of circles around us\" class=\"wp-image-37083\" title=\"Examples of circles around us\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/examples-of-circles-around-us.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/examples-of-circles-around-us-300x205.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Let\u2019s learn the meaning of circumference of a circle using a real-life example. Suppose a boy walks around a circular park and completes one round. The distance covered by him is the circumference of the circular park.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"393\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circular-park.png\" alt=\"Circumference of a circular park\" class=\"wp-image-37084\" title=\"Circumference of a circular park\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circular-park.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circular-park-300x190.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<div id=\"recommended-games-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Games<\/h4><div class=\"recommended-games-container-slides\"><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/count-upto-10-objects-in-circle\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/count_comp_hide_and_seek_10_gm.png\" alt=\"Count upto 10 Objects in Circle Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Count upto 10 Objects in Circle Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/identify-circles-and-rectangles\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geometry_circles_rectangles_pt.png\" alt=\"Identify Circles and Rectangles Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Identify Circles and Rectangles Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/match-rectangles-and-circles\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geometry_amusement_park_3_6_gm.png\" alt=\"Match Rectangles and Circles Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Match Rectangles and Circles Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/games\">More Games<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-games-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".game-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading eplus-wrapper\" id=\"1-circumference-of-a-circle-definition\">Circumference of a Circle: Definition<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The circumference is the length of the boundary of a circle. It is also known as the \u201cperimeter\u201d of a circle. Since it represents length, it is measured in units of lengths such as feet, inches, centimeters, meters, miles, or kilometers.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"635\" height=\"328\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circle.png\" alt=\"Circumference of a circle\" class=\"wp-image-37086\" title=\"Circumference of a circle\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circle.png 635w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circle-300x155.png 300w\" sizes=\"auto, (max-width: 635px) 100vw, 635px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">If we cut open a circle and make a straight line, the length of the line would give us the circle\u2019s circumference.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"635\" height=\"320\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circle-equals-the-length-of-its-boundary.png\" alt=\"Circumference of a circle equals the length of its boundary\" class=\"wp-image-37085\" title=\"Circumference of a circle equals the length of its boundary\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circle-equals-the-length-of-its-boundary.png 635w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/circumference-of-a-circle-equals-the-length-of-its-boundary-300x151.png 300w\" sizes=\"auto, (max-width: 635px) 100vw, 635px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Let\u2019s revise a few important terms related to circles to understand how to calculate the circumference of a circle.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"635\" height=\"320\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/radius-diameter-and-center-of-a-circle.png\" alt=\"Radius, diameter and center of a circle\" class=\"wp-image-37087\" title=\"Radius, diameter and center of a circle\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/radius-diameter-and-center-of-a-circle.png 635w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/radius-diameter-and-center-of-a-circle-300x151.png 300w\" sizes=\"auto, (max-width: 635px) 100vw, 635px\" \/><\/figure>\n\n\n\n<div id=\"recommended-worksheets-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Worksheets<\/h4><div class=\"recommended-games-container-slides\"><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/circle-equivalent-fractions\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/circle-equivalent-fractions.jpeg\" alt=\"Circle Equivalent Fractions Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/squares-and-circles\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/squares-and-circles.jpeg\" alt=\"Squares and Circles Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/worksheets\">More Worksheets<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-worksheets-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".worksheet-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading eplus-wrapper\" id=\"2-diameter-of-the-circle\">Diameter of the Circle<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The <strong>diameter <\/strong>is a straight line passing through the center that cuts the circle in half. Both its endpoints lie on the circumference of the circle.<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"3-radius-of-the-circle\">Radius of the Circle<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">All points on the boundary of a circle are at an equal distance from its center. The<strong> radius<\/strong> is the distance from the center of the circle to any point on the <strong>circumference of the circle<\/strong>. It is half the length of the diameter.<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"4-how-to-find-the-circumference-of-a-circle-using-a-thread\">How to Find the Circumference of a Circle Using a Thread?<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Generally, the outer length of polygons (square, triangle, rectangle, etc.) can be calculated using a scale or ruler, but the same cannot be done for circles because of their curved shape.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"317\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/finding-circumference-of-a-circle-using-a-thread.png\" alt=\"Finding circumference of a circle using a thread\" class=\"wp-image-37088\" title=\"Finding circumference of a circle using a thread\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/finding-circumference-of-a-circle-using-a-thread.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/finding-circumference-of-a-circle-using-a-thread-300x153.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Then <strong>how can we find the circumference of a circle or how to find the perimeter of a circle<\/strong>? One way is to use a thread. Note that calculating the perimeter of a circle is the same as calculating its circumference.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Step 1:<\/strong> Take a thread and revolve it around the circular object you want to measure.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Step 2: <\/strong>Mark the initial and final point on the thread.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Step 3:<\/strong> Measure the length of the thread from the initial to the final point using a ruler. That would give you the circumference of the circle.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">While this method gives us only an estimate, we need to use the circumference <strong>formula<\/strong>&nbsp;for more accurate results. The same is discussed in the next section.&nbsp;<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"5-what-is-the-circumference-to-diameter-ratio\">What is the Circumference to Diameter Ratio?<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The ratio of the circumference to the diameter of any circle is a constant. The constant value is called pi (denoted by \u03c0). Let C be the circumference of a circle, and let d be its diameter. Then,<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">C\/d $=$ \u03c0<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">For all circles, regardless of small or big, this ratio remains constant. The approximate value of \u03c0 is 3.14 or 227.<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"6-formula-for-the-circumference-of-a-circle\">Formula for the Circumference of a Circle<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We just learned that:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circumference (C) \/ Diameter (d) $= 3.14159$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Or,<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">C\/d $=$ \u03c0<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">If we shift the diameter to the other side, we get:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>C <\/strong>$=$<strong> \u03c0d  <\/strong>\u2026 circumference of a circle using diameter<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">This gives us the <strong>formula for the circumference of a circle<\/strong> when the diameter is given.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Also, we know that the diameter of the circle is twice the radius<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">or, d $= 2$r<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">So, replacing the value of d in the above formula, we get:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>C <\/strong>$=$<strong> \u03c0(2r)<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>or C <\/strong>$= 2$<strong>\u03c0r  <\/strong>\u2026 circumference of a circle using radius<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Therefore, the<strong> circumference circle equation <\/strong>is C $= 2$\u03c0r.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Example 1:<\/strong> If the radius of a circle is 7 units, then the circumference of the circle will be&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$2 \\times$ \u03c0 $\\times 7 = 2 \\times 3.14159 \\times 7$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= 43.98$ units&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Example 2: <\/strong>Suppose that the diameter of the circle is 12 feet. Then, we can use the formula \u03c0d to calculate the circumference.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circumference $=$ \u03c0d $= 3.14159 \\times 12 = 37.69$ feet<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"7-conclusion\">Conclusion<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Now you know <strong>how to calculate the circumference of a circle<\/strong> if you know its radius or diameter!<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Since the circumference gives the length of the circle\u2019s boundary, it serves many practical purposes. Solving the practical problems given will help you better grasp the concept of the circumference of the circle. Good luck!<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"8-solved-examples\">Solved Examples<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>1. What is the circumference of a circle with a diameter of 14 feet? Use \u03c0 <\/strong>$= 3.14$<strong>.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Given, diameter (d) = 14 feet<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circumference of the circle = \u03c0d<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">= 3.14 \u00d7 14 feet<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">= 43.96 feet<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>2. The<\/strong> <strong>radius of a circle is 6 inches. What is the circumference of the circle? Use \u03c0 = 3.14.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Given, radius (r)$= 6$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circumference (c)$= 2$\u03c0r<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$= 2 \\times 3.14 \\times 6$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$= 37.68$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>3. The circumference of a circle is 100 feet. Find its diameter<\/strong>. <strong>Use \u03c0 <\/strong>$= 3.14$<strong>.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Applying the formula:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circumference (C)$=$ \u03c0d<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">100 feet $= 3.14 \\times$ d<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">d $= 100$ feet \/ 3.14<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">d $= 31.85$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Therefore, d $= 31.85$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>4. The circumference of a circle is 120 m. Find its radius. Use \u03c0 <\/strong>$= 3.14$<strong>.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We know that<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circumference (C) $= 2$\u03c0r<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$120 =$ 2\u03c0r<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$1202 = 3.14 \\times$ r<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$60 = 3.14 \\times$ r<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">r $= 603.14$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Therefore, r $= 19.11$ m<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>5. If the diameter of a circle is 15 miles, what will be the length of its boundary?<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The length of the boundary of a circle is the circle&#8217;s circumference.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Hence, let\u2019s find the circumference first.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Given, diameter (d) $= 15$ cm<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circumference (C) $=$ \u03c0d $= 3.14 \\times 15$ cm $= 47.1$ cm<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"9-practice-problems\">Practice Problems<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><div class=\"spq_wrapper\"><h2 style=\"display:none;\">Circumference of a Circle\ufffc<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">The perimeter of a square wire is 25 inches. The same wire is bent to form a circle. Find the radius of the circle thus formed.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">2.55 inches<\/div><div class=\"spq_answer_block\" data-value=\"1\">3.98 inches<\/div><div class=\"spq_answer_block\" data-value=\"2\">4.51 inches<\/div><div class=\"spq_answer_block\" data-value=\"3\">5.25 inches<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 3.98 inches<br\/>The perimeter of the square = total length of the wire $=$ circumference of the circle.<br>\r\nHence, the circumference of the circle (C) $=$ 25 inches.<br>\r\nApplying the formula:<br>\r\nC $=$ $2\u03c0r$<br>\r\n25 inches $= 2 \\times 3.14 \\times$ r<br>\r\n25 inches $= 6.28 \\times$ r<br>\r\nr $= 25\/6.28$<br>\r\nr $= 3.98$ inches<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"3\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">The diameter of a cycle wheel is 7 inches. How many times must the wheel rotate to cover a distance of 110 feet? Take \u03c0 $=\\frac{22}{7}$<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">500 times<\/div><div class=\"spq_answer_block\" data-value=\"1\">600 times<\/div><div class=\"spq_answer_block\" data-value=\"2\">5 times<\/div><div class=\"spq_answer_block\" data-value=\"3\">60 times<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 60 times<br\/>The circumference of the wheel will give us the distance covered by the wheel in one rotation.\r\nSo, let us calculate the circumference first.<br>\r\nGiven, diameter (d) $=$ 7 inches<br>\r\nCircumference $=$ \u03c0d<br>\r\n            $= 22\/7 \\times 7$ <br>\r\n            $= 22$ inches<br>\r\nSo, the distance covered by the wheel in one rotation $= 22$ inches<br>\r\nTotal distance to be covered $= 110$ feet $= (110 \\times 12)$ inches $= 1320$ inches<br>\r\nHence, no. of rotations required$= 1320\/22 = 60$<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">A circular flowerbed has a diameter of 20 feet. Find the cost of fencing the flowerbed at the rate of $10$ per feet. Take $\\pi$ = 3.14.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$\\$$228<\/div><div class=\"spq_answer_block\" data-value=\"1\">$\\$$528<\/div><div class=\"spq_answer_block\" data-value=\"2\">$\\$$628<\/div><div class=\"spq_answer_block\" data-value=\"3\">$\\$$728<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $\\$$628<br\/>Diameter of the flowerbed (d) $=$ 20 feet<br>\r\nFencing the circular flowerbed refers to the boundary of the circle, i.e., the circumference of the circle.<br>\r\nCircumference of the flowerbed $=$ \u03c0d<br>\r\n$= 3.14 \\times 20$ m $= 62.8$ feet<br>\r\nNow, the cost of fencing $=$ $\\$$10 per ft<br>\r\nSo, the cost of fencing $62.8$ feet $= 62.8 \\times$ $\\$$10 $=$ $\\$$628<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">4<\/span><h3 class=\"sqp_question_text\">The difference between a circle's circumference and diameter is 10 feet. Find its radius. Take \u03c0 $= 3.14$.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">1.33 feet<\/div><div class=\"spq_answer_block\" data-value=\"1\">2.33 feet<\/div><div class=\"spq_answer_block\" data-value=\"2\">3.33 feet<\/div><div class=\"spq_answer_block\" data-value=\"3\">4.33 feet<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 2.33 feet<br\/>Given: Circumference \u2013 Diameter $=$ 10 feet<br>\r\nWe know that:<br>\r\nCircumference $= 2$\u03c0r<br>\r\nDiameter $= 2$r<br>\r\nSo, $2$\u03c0r $-$ $2$r $= 10$ feet<br>\r\n$2$r$(\\text{\u03c0}$ $-$ $1) = 10$ feet<br>\r\n$2$r $(3.14$ $-$ $1) = 10$ feet<br>\r\n$2$r $\\times 2.14 = 10$ feet<br>\r\nr = 10 \/ 4.28<br>\r\nr = 2.33 feet<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">5<\/span><h3 class=\"sqp_question_text\">The ratio of the circumference of two circles is 4:5. Find the ratio of their radius.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">4:5<\/div><div class=\"spq_answer_block\" data-value=\"1\">5:4<\/div><div class=\"spq_answer_block\" data-value=\"2\">2:3<\/div><div class=\"spq_answer_block\" data-value=\"3\">3:2<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 4:5<br\/>We know that the circumference of a circle is $2$\u03c0r.<br>\r\nLet us consider the radius of the first circle to be R\u2081 and that of the second circle to be R\u2082.<br>\r\nSo,\r\nCircumference of 1st circle $= 2$\u03c0R\u2081<br>\r\nCircumference of 1st circle $= 2$\u03c0R\u2082<br>\r\n<br>\r\nRatio $= \\frac{2\u03c0R_1}{2\u03c0R_2} = \\frac{4}{5}$<br>\r\n<br>\r\nCanceling $2$\u03c0 from both the ratios,<br>\r\n$\\frac{R_1}{R_2}= \\frac{4}{5}$<br>\r\nTherefore, the ratio of the two radii is 4:5.<\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  \"beginner\",\n        \"assesses\" : \"Attend this quiz & Test your knowledge.\",\n        \"educationalAlignment\": [\n              {\n                \"@type\": \"AlignmentObject\",\n                \"alignmentType\": \"educationalSubject\",\n                \"targetName\": \"Math\"\n              }] ,\n        \"name\": \"Circumference of a Circle\ufffc\",        \n        \"about\": {\n                \"@type\": \"Thing\",\n                \"name\": \"Circumference of a Circle\"\n        },  \n        \"hasPart\": [{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The perimeter of a square wire is 25 inches. The same wire is bent to form a circle. Find the radius of the circle thus formed.\",\n                    \"text\": \"The perimeter of a square wire is 25 inches. The same wire is bent to form a circle. Find the radius of the circle thus formed.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The perimeter of the square = total length of the wire $$=$$ circumference of the circle.<br>\r\nHence, the circumference of the circle (C) $$=$$ 25 inches.<br>\r\nApplying the formula:<br>\r\nC $$=$$ $$2\u03c0r$$<br>\r\n25 inches $$= 2 \\\\times 3.14 \\\\times$$ r<br>\r\n25 inches $$= 6.28 \\\\times$$ r<br>\r\nr $$= 25\/6.28$$<br>\r\nr $$= 3.98$$ inches\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"2.55 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The perimeter of the square = total length of the wire $$=$$ circumference of the circle.<br>\r\nHence, the circumference of the circle (C) $$=$$ 25 inches.<br>\r\nApplying the formula:<br>\r\nC $$=$$ $$2\u03c0r$$<br>\r\n25 inches $$= 2 \\\\times 3.14 \\\\times$$ r<br>\r\n25 inches $$= 6.28 \\\\times$$ r<br>\r\nr $$= 25\/6.28$$<br>\r\nr $$= 3.98$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"4.51 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The perimeter of the square = total length of the wire $$=$$ circumference of the circle.<br>\r\nHence, the circumference of the circle (C) $$=$$ 25 inches.<br>\r\nApplying the formula:<br>\r\nC $$=$$ $$2\u03c0r$$<br>\r\n25 inches $$= 2 \\\\times 3.14 \\\\times$$ r<br>\r\n25 inches $$= 6.28 \\\\times$$ r<br>\r\nr $$= 25\/6.28$$<br>\r\nr $$= 3.98$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"5.25 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The perimeter of the square = total length of the wire $$=$$ circumference of the circle.<br>\r\nHence, the circumference of the circle (C) $$=$$ 25 inches.<br>\r\nApplying the formula:<br>\r\nC $$=$$ $$2\u03c0r$$<br>\r\n25 inches $$= 2 \\\\times 3.14 \\\\times$$ r<br>\r\n25 inches $$= 6.28 \\\\times$$ r<br>\r\nr $$= 25\/6.28$$<br>\r\nr $$= 3.98$$ inches\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"3.98 inches\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The perimeter of the square = total length of the wire $$=$$ circumference of the circle.<br>\r\nHence, the circumference of the circle (C) $$=$$ 25 inches.<br>\r\nApplying the formula:<br>\r\nC $$=$$ $$2\u03c0r$$<br>\r\n25 inches $$= 2 \\\\times 3.14 \\\\times$$ r<br>\r\n25 inches $$= 6.28 \\\\times$$ r<br>\r\nr $$= 25\/6.28$$<br>\r\nr $$= 3.98$$ inches\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The perimeter of the square = total length of the wire $$=$$ circumference of the circle.<br>\r\nHence, the circumference of the circle (C) $$=$$ 25 inches.<br>\r\nApplying the formula:<br>\r\nC $$=$$ $$2\u03c0r$$<br>\r\n25 inches $$= 2 \\\\times 3.14 \\\\times$$ r<br>\r\n25 inches $$= 6.28 \\\\times$$ r<br>\r\nr $$= 25\/6.28$$<br>\r\nr $$= 3.98$$ inches\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The diameter of a cycle wheel is 7 inches. How many times must the wheel rotate to cover a distance of 110 feet? Take \u03c0 $$=\\\\frac{22}{7}$$\",\n                    \"text\": \"The diameter of a cycle wheel is 7 inches. How many times must the wheel rotate to cover a distance of 110 feet? Take \u03c0 $$=\\\\frac{22}{7}$$\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The circumference of the wheel will give us the distance covered by the wheel in one rotation.\r\nSo, let us calculate the circumference first.<br>\r\nGiven, diameter (d) $$=$$ 7 inches<br>\r\nCircumference $$=$$ \u03c0d<br>\r\n            $$= 22\/7 \\\\times 7$$ <br>\r\n            $$= 22$$ inches<br>\r\nSo, the distance covered by the wheel in one rotation $$= 22$$ inches<br>\r\nTotal distance to be covered $$= 110$$ feet $$= (110 \\\\times 12)$$ inches $$= 1320$$ inches<br>\r\nHence, no. of rotations required$$= 1320\/22 = 60$$\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"500 times\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The circumference of the wheel will give us the distance covered by the wheel in one rotation.\r\nSo, let us calculate the circumference first.<br>\r\nGiven, diameter (d) $$=$$ 7 inches<br>\r\nCircumference $$=$$ \u03c0d<br>\r\n            $$= 22\/7 \\\\times 7$$ <br>\r\n            $$= 22$$ inches<br>\r\nSo, the distance covered by the wheel in one rotation $$= 22$$ inches<br>\r\nTotal distance to be covered $$= 110$$ feet $$= (110 \\\\times 12)$$ inches $$= 1320$$ inches<br>\r\nHence, no. of rotations required$$= 1320\/22 = 60$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"600 times\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The circumference of the wheel will give us the distance covered by the wheel in one rotation.\r\nSo, let us calculate the circumference first.<br>\r\nGiven, diameter (d) $$=$$ 7 inches<br>\r\nCircumference $$=$$ \u03c0d<br>\r\n            $$= 22\/7 \\\\times 7$$ <br>\r\n            $$= 22$$ inches<br>\r\nSo, the distance covered by the wheel in one rotation $$= 22$$ inches<br>\r\nTotal distance to be covered $$= 110$$ feet $$= (110 \\\\times 12)$$ inches $$= 1320$$ inches<br>\r\nHence, no. of rotations required$$= 1320\/22 = 60$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"5 times\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The circumference of the wheel will give us the distance covered by the wheel in one rotation.\r\nSo, let us calculate the circumference first.<br>\r\nGiven, diameter (d) $$=$$ 7 inches<br>\r\nCircumference $$=$$ \u03c0d<br>\r\n            $$= 22\/7 \\\\times 7$$ <br>\r\n            $$= 22$$ inches<br>\r\nSo, the distance covered by the wheel in one rotation $$= 22$$ inches<br>\r\nTotal distance to be covered $$= 110$$ feet $$= (110 \\\\times 12)$$ inches $$= 1320$$ inches<br>\r\nHence, no. of rotations required$$= 1320\/22 = 60$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 3,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"60 times\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The circumference of the wheel will give us the distance covered by the wheel in one rotation.\r\nSo, let us calculate the circumference first.<br>\r\nGiven, diameter (d) $$=$$ 7 inches<br>\r\nCircumference $$=$$ \u03c0d<br>\r\n            $$= 22\/7 \\\\times 7$$ <br>\r\n            $$= 22$$ inches<br>\r\nSo, the distance covered by the wheel in one rotation $$= 22$$ inches<br>\r\nTotal distance to be covered $$= 110$$ feet $$= (110 \\\\times 12)$$ inches $$= 1320$$ inches<br>\r\nHence, no. of rotations required$$= 1320\/22 = 60$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The circumference of the wheel will give us the distance covered by the wheel in one rotation.\r\nSo, let us calculate the circumference first.<br>\r\nGiven, diameter (d) $$=$$ 7 inches<br>\r\nCircumference $$=$$ \u03c0d<br>\r\n            $$= 22\/7 \\\\times 7$$ <br>\r\n            $$= 22$$ inches<br>\r\nSo, the distance covered by the wheel in one rotation $$= 22$$ inches<br>\r\nTotal distance to be covered $$= 110$$ feet $$= (110 \\\\times 12)$$ inches $$= 1320$$ inches<br>\r\nHence, no. of rotations required$$= 1320\/22 = 60$$\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"A circular flowerbed has a diameter of 20 feet. Find the cost of fencing the flowerbed at the rate of $$10$$ per feet. Take $$\\\\pi$$ = 3.14.\",\n                    \"text\": \"A circular flowerbed has a diameter of 20 feet. Find the cost of fencing the flowerbed at the rate of $$10$$ per feet. Take $$\\\\pi$$ = 3.14.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Diameter of the flowerbed (d) $$=$$ 20 feet<br>\r\nFencing the circular flowerbed refers to the boundary of the circle, i.e., the circumference of the circle.<br>\r\nCircumference of the flowerbed $$=$$ \u03c0d<br>\r\n$$= 3.14 \\\\times 20$$ m $$= 62.8$$ feet<br>\r\nNow, the cost of fencing $$=$$ $$\\\\$$$$10 per ft<br>\r\nSo, the cost of fencing $$62.8$$ feet $$= 62.8 \\\\times$$ $$\\\\$$$$10 $$=$$ $$\\\\$$$$628\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\$$$$228\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter of the flowerbed (d) $$=$$ 20 feet<br>\r\nFencing the circular flowerbed refers to the boundary of the circle, i.e., the circumference of the circle.<br>\r\nCircumference of the flowerbed $$=$$ \u03c0d<br>\r\n$$= 3.14 \\\\times 20$$ m $$= 62.8$$ feet<br>\r\nNow, the cost of fencing $$=$$ $$\\\\$$$$10 per ft<br>\r\nSo, the cost of fencing $$62.8$$ feet $$= 62.8 \\\\times$$ $$\\\\$$$$10 $$=$$ $$\\\\$$$$628\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\$$$$528\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter of the flowerbed (d) $$=$$ 20 feet<br>\r\nFencing the circular flowerbed refers to the boundary of the circle, i.e., the circumference of the circle.<br>\r\nCircumference of the flowerbed $$=$$ \u03c0d<br>\r\n$$= 3.14 \\\\times 20$$ m $$= 62.8$$ feet<br>\r\nNow, the cost of fencing $$=$$ $$\\\\$$$$10 per ft<br>\r\nSo, the cost of fencing $$62.8$$ feet $$= 62.8 \\\\times$$ $$\\\\$$$$10 $$=$$ $$\\\\$$$$628\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\$$$$728\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter of the flowerbed (d) $$=$$ 20 feet<br>\r\nFencing the circular flowerbed refers to the boundary of the circle, i.e., the circumference of the circle.<br>\r\nCircumference of the flowerbed $$=$$ \u03c0d<br>\r\n$$= 3.14 \\\\times 20$$ m $$= 62.8$$ feet<br>\r\nNow, the cost of fencing $$=$$ $$\\\\$$$$10 per ft<br>\r\nSo, the cost of fencing $$62.8$$ feet $$= 62.8 \\\\times$$ $$\\\\$$$$10 $$=$$ $$\\\\$$$$628\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$\\\\$$$$628\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Diameter of the flowerbed (d) $$=$$ 20 feet<br>\r\nFencing the circular flowerbed refers to the boundary of the circle, i.e., the circumference of the circle.<br>\r\nCircumference of the flowerbed $$=$$ \u03c0d<br>\r\n$$= 3.14 \\\\times 20$$ m $$= 62.8$$ feet<br>\r\nNow, the cost of fencing $$=$$ $$\\\\$$$$10 per ft<br>\r\nSo, the cost of fencing $$62.8$$ feet $$= 62.8 \\\\times$$ $$\\\\$$$$10 $$=$$ $$\\\\$$$$628\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Diameter of the flowerbed (d) $$=$$ 20 feet<br>\r\nFencing the circular flowerbed refers to the boundary of the circle, i.e., the circumference of the circle.<br>\r\nCircumference of the flowerbed $$=$$ \u03c0d<br>\r\n$$= 3.14 \\\\times 20$$ m $$= 62.8$$ feet<br>\r\nNow, the cost of fencing $$=$$ $$\\\\$$$$10 per ft<br>\r\nSo, the cost of fencing $$62.8$$ feet $$= 62.8 \\\\times$$ $$\\\\$$$$10 $$=$$ $$\\\\$$$$628\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The difference between a circle's circumference and diameter is 10 feet. Find its radius. Take \u03c0 $$= 3.14$$.\",\n                    \"text\": \"The difference between a circle's circumference and diameter is 10 feet. Find its radius. Take \u03c0 $$= 3.14$$.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Given: Circumference \u2013 Diameter $$=$$ 10 feet<br>\r\nWe know that:<br>\r\nCircumference $$= 2$$\u03c0r<br>\r\nDiameter $$= 2$$r<br>\r\nSo, $$2$$\u03c0r $$-$$ $$2$$r $$= 10$$ feet<br>\r\n$$2$$r$$(\\\\text{\u03c0}$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$(3.14$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$\\\\times 2.14 = 10$$ feet<br>\r\nr = 10 \/ 4.28<br>\r\nr = 2.33 feet\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"1.33 feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Given: Circumference \u2013 Diameter $$=$$ 10 feet<br>\r\nWe know that:<br>\r\nCircumference $$= 2$$\u03c0r<br>\r\nDiameter $$= 2$$r<br>\r\nSo, $$2$$\u03c0r $$-$$ $$2$$r $$= 10$$ feet<br>\r\n$$2$$r$$(\\\\text{\u03c0}$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$(3.14$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$\\\\times 2.14 = 10$$ feet<br>\r\nr = 10 \/ 4.28<br>\r\nr = 2.33 feet\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"3.33 feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Given: Circumference \u2013 Diameter $$=$$ 10 feet<br>\r\nWe know that:<br>\r\nCircumference $$= 2$$\u03c0r<br>\r\nDiameter $$= 2$$r<br>\r\nSo, $$2$$\u03c0r $$-$$ $$2$$r $$= 10$$ feet<br>\r\n$$2$$r$$(\\\\text{\u03c0}$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$(3.14$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$\\\\times 2.14 = 10$$ feet<br>\r\nr = 10 \/ 4.28<br>\r\nr = 2.33 feet\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"4.33 feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Given: Circumference \u2013 Diameter $$=$$ 10 feet<br>\r\nWe know that:<br>\r\nCircumference $$= 2$$\u03c0r<br>\r\nDiameter $$= 2$$r<br>\r\nSo, $$2$$\u03c0r $$-$$ $$2$$r $$= 10$$ feet<br>\r\n$$2$$r$$(\\\\text{\u03c0}$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$(3.14$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$\\\\times 2.14 = 10$$ feet<br>\r\nr = 10 \/ 4.28<br>\r\nr = 2.33 feet\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"2.33 feet\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Given: Circumference \u2013 Diameter $$=$$ 10 feet<br>\r\nWe know that:<br>\r\nCircumference $$= 2$$\u03c0r<br>\r\nDiameter $$= 2$$r<br>\r\nSo, $$2$$\u03c0r $$-$$ $$2$$r $$= 10$$ feet<br>\r\n$$2$$r$$(\\\\text{\u03c0}$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$(3.14$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$\\\\times 2.14 = 10$$ feet<br>\r\nr = 10 \/ 4.28<br>\r\nr = 2.33 feet\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Given: Circumference \u2013 Diameter $$=$$ 10 feet<br>\r\nWe know that:<br>\r\nCircumference $$= 2$$\u03c0r<br>\r\nDiameter $$= 2$$r<br>\r\nSo, $$2$$\u03c0r $$-$$ $$2$$r $$= 10$$ feet<br>\r\n$$2$$r$$(\\\\text{\u03c0}$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$(3.14$$ $$-$$ $$1) = 10$$ feet<br>\r\n$$2$$r $$\\\\times 2.14 = 10$$ feet<br>\r\nr = 10 \/ 4.28<br>\r\nr = 2.33 feet\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The ratio of the circumference of two circles is 4:5. Find the ratio of their radius.\",\n                    \"text\": \"The ratio of the circumference of two circles is 4:5. Find the ratio of their radius.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"We know that the circumference of a circle is $$2$$\u03c0r.<br>\r\nLet us consider the radius of the first circle to be R\u2081 and that of the second circle to be R\u2082.<br>\r\nSo,\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2081<br>\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2082<br>\r\n<br>\r\nRatio $$= \\\\frac{2\u03c0R_1}{2\u03c0R_2} = \\\\frac{4}{5}$$<br>\r\n<br>\r\nCanceling $$2$$\u03c0 from both the ratios,<br>\r\n$$\\\\frac{R_1}{R_2}= \\\\frac{4}{5}$$<br>\r\nTherefore, the ratio of the two radii is 4:5.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"5:4\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the circumference of a circle is $$2$$\u03c0r.<br>\r\nLet us consider the radius of the first circle to be R\u2081 and that of the second circle to be R\u2082.<br>\r\nSo,\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2081<br>\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2082<br>\r\n<br>\r\nRatio $$= \\\\frac{2\u03c0R_1}{2\u03c0R_2} = \\\\frac{4}{5}$$<br>\r\n<br>\r\nCanceling $$2$$\u03c0 from both the ratios,<br>\r\n$$\\\\frac{R_1}{R_2}= \\\\frac{4}{5}$$<br>\r\nTherefore, the ratio of the two radii is 4:5.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"2:3\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the circumference of a circle is $$2$$\u03c0r.<br>\r\nLet us consider the radius of the first circle to be R\u2081 and that of the second circle to be R\u2082.<br>\r\nSo,\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2081<br>\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2082<br>\r\n<br>\r\nRatio $$= \\\\frac{2\u03c0R_1}{2\u03c0R_2} = \\\\frac{4}{5}$$<br>\r\n<br>\r\nCanceling $$2$$\u03c0 from both the ratios,<br>\r\n$$\\\\frac{R_1}{R_2}= \\\\frac{4}{5}$$<br>\r\nTherefore, the ratio of the two radii is 4:5.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"3:2\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the circumference of a circle is $$2$$\u03c0r.<br>\r\nLet us consider the radius of the first circle to be R\u2081 and that of the second circle to be R\u2082.<br>\r\nSo,\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2081<br>\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2082<br>\r\n<br>\r\nRatio $$= \\\\frac{2\u03c0R_1}{2\u03c0R_2} = \\\\frac{4}{5}$$<br>\r\n<br>\r\nCanceling $$2$$\u03c0 from both the ratios,<br>\r\n$$\\\\frac{R_1}{R_2}= \\\\frac{4}{5}$$<br>\r\nTherefore, the ratio of the two radii is 4:5.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"4:5\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"We know that the circumference of a circle is $$2$$\u03c0r.<br>\r\nLet us consider the radius of the first circle to be R\u2081 and that of the second circle to be R\u2082.<br>\r\nSo,\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2081<br>\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2082<br>\r\n<br>\r\nRatio $$= \\\\frac{2\u03c0R_1}{2\u03c0R_2} = \\\\frac{4}{5}$$<br>\r\n<br>\r\nCanceling $$2$$\u03c0 from both the ratios,<br>\r\n$$\\\\frac{R_1}{R_2}= \\\\frac{4}{5}$$<br>\r\nTherefore, the ratio of the two radii is 4:5.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"We know that the circumference of a circle is $$2$$\u03c0r.<br>\r\nLet us consider the radius of the first circle to be R\u2081 and that of the second circle to be R\u2082.<br>\r\nSo,\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2081<br>\r\nCircumference of 1st circle $$= 2$$\u03c0R\u2082<br>\r\n<br>\r\nRatio $$= \\\\frac{2\u03c0R_1}{2\u03c0R_2} = \\\\frac{4}{5}$$<br>\r\n<br>\r\nCanceling $$2$$\u03c0 from both the ratios,<br>\r\n$$\\\\frac{R_1}{R_2}= \\\\frac{4}{5}$$<br>\r\nTherefore, the ratio of the two radii is 4:5.\"\n                      }\n                    } \n\n                    }]}<\/script><\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"10-frequently-asked-questions\">Frequently Asked Questions<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\"><strong>What is the difference between a sphere and a circle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\">\n\n<p class=\"wp-block-paragraph\">A circle is a two-dimensional figure, whereas a sphere is a three-dimensional solid object. Hence, a circle does not have a volume, but a sphere does.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\"><strong>What is the circumference of Earth?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\">\n\n<p class=\"wp-block-paragraph\">The circumference of the earth is about 24,901 miles.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\"><strong>What is the area of a circle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\">\n\n<p class=\"wp-block-paragraph\">The area of the circle is the space occupied by the boundary of the circle.&nbsp;It is given by<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-3-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\"><strong>What is the formula to calculate the circumference of a semicircle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-3-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\">\n\n<p class=\"wp-block-paragraph\">The circumference of a semi-circle can be calculated as C $=$ \u03c0r $+$ d.&nbsp;<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-4-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\"><strong>What is the difference between the circumference and area of a circle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-4-a563d9b1-3d16-4974-ae0a-d658b65cbe9c\">\n\n<p class=\"wp-block-paragraph\">The circumference is the length of the outer boundary of a circle, while the area is the total space enclosed by the boundary.<\/p>\n\n<\/div><\/div>\n<\/div>\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Related Articles Link<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/circle\"><strong>Circle<\/strong><\/a><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere#:~:text=The%20formula%20for%20the%20circumference,given%20by%202%20%CF%80%20r.\"><strong>Sphere<\/strong><\/a><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/perimeter\"><strong>Perimeter<\/strong><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the Circumference of a Circle? We see many circular objects daily, such as coins, buttons, wall clocks, wheels, etc. The boundary of any circular object has great significance in math. Let\u2019s learn the meaning of circumference of a circle using a real-life example. Suppose a boy walks around a circular park and completes &#8230; <a title=\"Circumference of a Circle\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle\" aria-label=\"More on Circumference of a Circle\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-13049","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/13049","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=13049"}],"version-history":[{"count":12,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/13049\/revisions"}],"predecessor-version":[{"id":37089,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/13049\/revisions\/37089"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=13049"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=13049"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=13049"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}