{"id":17788,"date":"2023-01-05T12:18:54","date_gmt":"2023-01-05T12:18:54","guid":{"rendered":"https:\/\/www.splashlearn.com\/math-vocabulary\/?page_id=17788"},"modified":"2023-08-15T16:41:26","modified_gmt":"2023-08-15T16:41:26","slug":"volume-of-a-sphere","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/measurement\/volume-of-sphere","title":{"rendered":"Volume of a Sphere"},"content":{"rendered":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-0e61cbec-dce0-498c-9861-39e66a393dbc\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/measurement\/volume-of-sphere#1-what-is-the-volume-of-a-sphere>What Is the Volume of a Sphere?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/measurement\/volume-of-sphere#4-volume-of-solid-sphere>Volume of Solid Sphere<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/measurement\/volume-of-sphere#8-solved-examples>Solved Examples<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/measurement\/volume-of-sphere#9-practice-problems>Practice Problems<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/measurement\/volume-of-sphere#10-frequently-asked-questions>Frequently Asked Questions<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"0-volume-of-a-sphere-introduction-\"><strong>Volume of a Sphere &#8211; Introduction<\/strong><\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Have you ever wondered, \u201cI can draw a circle, but I cannot draw a sphere? Why?\u201d This is because a circle is a two-dimensional figure and does not have volume, whereas a sphere is a three-dimensional shape with no edges or vertices. That means its points lie in space. Hence, you cannot draw it. This is the reason we always find the volume of a sphere to calculate the amount of space it occupies.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Scroll ahead to learn about the volume of a sphere formula, the derivation of the sphere volume formula, some solved examples, facts, and more.<\/p>\n\n\n\n<div id=\"recommended-games-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Games<\/h4><div class=\"recommended-games-container-slides\"><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/estimate-the-volume-of-a-given-shape\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_estimate_vol_1_pt.png\" alt=\"Estimate the Volume of a Given Shape Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Estimate the Volume of a Given Shape Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-volume-of-the-3d-shape-by-iterating\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_iterate_vol_1_pt.png\" alt=\"Find the Volume of the 3D Shape by Iterating Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Volume of the 3D Shape by Iterating Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-volume-using-unit-cubes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_unit_cubes_2_pt.png\" alt=\"Find the Volume using Unit Cubes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Volume using Unit Cubes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-volume-using-the-formula\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_formula_pt.png\" alt=\"Find Volume using the Formula Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Volume using the Formula Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/identify-cylinders-and-spheres\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geometry_cylinders_spheres_pt.png\" alt=\"Identify Cylinders and Spheres Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Identify Cylinders and Spheres Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/introduction-to-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_unit_cubes_1_pt.png\" alt=\"Introduction to Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Introduction to Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/iterate-and-find-the-total-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_iterate_vol_2_pt.png\" alt=\"Iterate and Find the Total Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Iterate and Find the Total Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/solve-the-word-problems-related-to-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_word_prob_pt.png\" alt=\"Solve the Word Problems Related to Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Solve the Word Problems Related to Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/use-the-3d-shapes-to-estimate-the-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_estimate_vol_2_pt.png\" alt=\"Use the 3D Shapes to Estimate the Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Use the 3D Shapes to Estimate the Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/games\">More Games<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-games-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".game-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading eplus-wrapper\" id=\"1-what-is-the-volume-of-a-sphere\">What Is the Volume of a Sphere?<\/h2>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"500\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/volume-and-surface-area-of-a-sphere-and-a-hemisphere.webp\" alt=\"Volume and surface area of a sphere and a hemisphere\" class=\"wp-image-33051\" title=\"Volume and surface area of a sphere and a hemisphere\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/volume-and-surface-area-of-a-sphere-and-a-hemisphere.webp 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/volume-and-surface-area-of-a-sphere-and-a-hemisphere-300x242.webp 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Wondering how we can find the volume of a sphere? Hold on, we will get to that, but first, understand what the volume of a sphere means. The volume of a sphere<strong> <\/strong>is the measure of three-dimensional space occupied by a sphere. It depends on the sphere\u2019s radius, which is half the diameter (the longest line inside the sphere that passes through the center of the sphere).&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">That means if the radius of the sphere changes, its volume changes too!<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of a sphere<strong> <\/strong>is measured in cubic units, such as $m^3$, $cm^3$, and so on.<\/p>\n\n\n\n<div id=\"recommended-worksheets-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Worksheets<\/h4><div class=\"recommended-games-container-slides\"><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/cones-and-spheres\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/cones-and-spheres.jpeg\" alt=\"Cones and Spheres Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/identify-the-unit-of-measurement\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/identify-the-unit-of-measurement.jpeg\" alt=\"Identify the Unit of Measurement Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/solve-word-problems-on-measurement\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/solve-word-problems-on-measurement.jpeg\" alt=\"Solve Word Problems on Measurement Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/word-problems-on-measurement\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/word-problems-on-measurement.jpeg\" alt=\"Word Problems on Measurement Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/worksheets\">More Worksheets<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-worksheets-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".worksheet-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading eplus-wrapper\" id=\"2-what-is-the-formula-to-find-the-volume-of-a-sphere\">What Is the Formula to Find the Volume of a Sphere?<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">How do you find the volume of a sphere given that \u201cr\u201d is the radius of the sphere? The volume of a sphere equation is<strong> <\/strong>as follows:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of a sphere $= \\frac{4}{3} \\pi r^3$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"3-how-to-calculate-the-volume-of-a-sphere\">How to Calculate the Volume of a Sphere?<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Suppose the radius of the sphere is 6 cm, then its volume will be:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">As we know, the volume of the sphere, V $= \\frac{4}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Here, $r = 6$ cm<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Thus, volume of sphere, V $= \\frac{4}{3} \\pi r^3 = \\frac{4}{3} \\times 3.14 \\times 6 \\times 6 \\times 6$&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$\\Rightarrow$ V $= 904.32 cm^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Therefore, the volume of a sphere is 904.32 cm3<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"4-volume-of-solid-sphere\">Volume of Solid Sphere<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">If the radius of the solid sphere is r, the volume of the sphere is given by:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Volume of Sphere, V $= \\frac{4}{3} \\pi r^3$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"5-volume-of-hollow-sphere\">Volume of Hollow Sphere<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Sphere that has a cavity or space inside is called a hollow sphere.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Let the radius of the outer sphere is R and the radius of the inner sphere is r.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of the sphere, V is given by:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Volume of Sphere, V = Volume of Outer Sphere &#8211; Volume of Inner Sphere&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$= \\frac{4}{3} \\pi R^3 &#8211; \\frac{4}{3} r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$= \\frac{4}{3} \\pi (R^3 &#8211; r^3)$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"6-fun-facts-about-spheres\">Fun Facts about Spheres<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">How about some fun and interesting facts about the sphere? Let\u2019s take a look!<\/p>\n\n\n\n<ol class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">A sphere is symmetrical and round. It does not have any faces, corners, or edges.<\/li>\n\n\n\n<li class=\"eplus-wrapper\">Balls, marbles, and even Earth are shaped like spheres.<\/li>\n\n\n\n<li class=\"eplus-wrapper\">A hemisphere is an exact half of a sphere.<\/li>\n\n\n\n<li class=\"eplus-wrapper\">All the sphere\u2019s surface points are the same distance \u201cr\u201d from the center.<\/li>\n\n\n\n<li class=\"eplus-wrapper\">The sphere appears in nature when a surface wants to be as small as possible. For example, if you blow up a balloon, it naturally forms a sphere!<\/li>\n<\/ol>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"7-conclusion\">Conclusion<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">So, how was the lesson? We hope you have got a clear understanding of the volume of spheres. Stay tuned with <a href=\"https:\/\/www.splashlearn.com\/\">SplashLearn<\/a> for more useful math lessons like these.<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"8-solved-examples\">Solved Examples<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>1. What is the volume of a sphere with a radius of 12 units?<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong> To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The equation for the volume of a sphere<strong> <\/strong>is:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">If the radius of the sphere is 12, then you plug that in for r and solve:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3 = \\frac{4}{3} \\times 3.14 \\times 12 \\times 12 \\times 12 = 7234.56$ cubic units&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>2. Find the volume of the sphere whose diameter is 28 cm.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution: <\/strong>Given, diameter $= 28 cm$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">So, radius $= \\frac{Diameter}{2} = \\frac{28}{2} = 14 cm$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">From there, we can use the formula, which is<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3 = \\frac{4}{3} \\times 3.14 \\times 14 \\times 14 \\times 14 = 11488.23 cm^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>3. Find the volume of a spherical tank whose radius is 3 inches.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The equation for the volume of a sphere<strong> <\/strong>is:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">If the radius of the sphere is 3 inches, then you plug that in for r and solve:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3 = \\frac{4}{3} \\times 3.14 \\times 3 \\times 3 \\times 3 = 113.04$ cubic inches&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>4. Nina created a spherical ball of radius 5 cm using clay. She then cut the sphere into two equal parts. What will be the volume of each part?<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The equation for the volume of a sphere is:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">If the radius of the sphere is 5 cm, then you plug that in for r and solve:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3 = 43 3.14 5 5 5 = 523.33$ $cm^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Hence volume of each cut part $= \\frac{523.33}{2} = 261.66$ $cm^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>5.&nbsp; Sam wants to create a sphere of radius 7 cm using some clay. What will be the volume of the sphere formed?<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The equation for the volume of a sphere is:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">If the radius of the sphere is 7 cm, then you plug that in for r and solve:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">V $= \\frac{4}{3} \\pi r^3 = \\frac{4}{3} \\times 3.14 \\times 7 \\times 7 \\times 7 = 1436.02$ $cm^3$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"9-practice-problems\">Practice Problems<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><div class=\"spq_wrapper\"><h2 style=\"display:none;\">Volume of a Sphere<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">What is the volume of the sphere, whose radius is 4 units?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$88.3\\pi$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$77.3\\pi$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$85.3\\pi$<\/div><div class=\"spq_answer_block\" data-value=\"3\">$90\\pi$<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $85.3\\pi$<br\/>To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.\r\nThe equation is V $= \\frac{4}{3} \\pi r^3$\r\nThen plug the radius into the equation for r, yielding \r\nV $= \\frac{4}{3} \\times \\pi \\times 4 \\times 4 \\times 4 = 85.3\\pi$<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">Find the volume of a sphere of radius 10 cm.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$4186.66 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$2186.66 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$4189.66 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"3\">$41.66 cm^3$<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $4186.66 cm^3$<br\/>The volume of the sphere $=$ V $= \\frac{4}{3} \\pi r^3 = \\frac{4}{3} \\times 3.14 \\times 10 \\times 10 \\times 10 = 4186.66 cm^3$<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">A spherical-shaped tank has a radius of 21 m. Now find the capacity of it in liters to store water in it.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">28,808,000 liters<\/div><div class=\"spq_answer_block\" data-value=\"1\">38,808,000 liters<\/div><div class=\"spq_answer_block\" data-value=\"2\">38,888,000 liters<\/div><div class=\"spq_answer_block\" data-value=\"3\">30,808,000 liters<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 38,808,000 liters<br\/>The given values are,<br>\r\nr $= 21$ m<br>\r\nNow the volume of a sphere,<br>\r\nV $= \\frac{4}{3} \\times \\pi \\times r^3$<br>\r\nV $= \\frac{4}{3} \\times 21 \\times 21 \\times 21$<br>\r\nV $= 4 \\times 22 \\times 21 \\times 21$<br>\r\nV $= 38808$ $m^3$<br>\r\nSince,<br>\r\n$1 m^3 = 1000$ liter<br>\r\nThen the capacity of the tank,<br>\r\n$= 38,808 m^3 \\times 1000$<br>\r\n$= 38,808,000$ liter<br>\r\nSo, 38,808,000 liters of water can be stored in the tank.<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">4<\/span><h3 class=\"sqp_question_text\">The volume of the sphere is $2100 cm^3$. What is the radius of the hemisphere formed by cutting the sphere into two equal parts?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$1200 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$1100 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$1050 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"3\">$2100 cm^3$<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $1050 cm^3$<br\/>Volume of hemisphere $= \\frac{Volume of sphere}{2} = 1050 cm^3$<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"3\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">5<\/span><h3 class=\"sqp_question_text\">What is the volume of a sphere with a radius of 18 cm?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$8004.78 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$9304.88 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$3908.78 cm^3$<\/div><div class=\"spq_answer_block\" data-value=\"3\">$3052.08 cm^3$<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $3052.08 cm^3$<br\/>Diameter of the sphere $= 18 cm$<br>\r\nRadius of the sphere $= \\frac{18}{2} = 9 cm$<br>\r\nThe volume of the sphere $=$ V $= \\frac{4}{3} \\pi r^3 = \\frac{4}{3} \\times 3.14 \\times 9 \\times 9 \\times 9 = 3052.08 cm^3$<\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  \"beginner\",\n        \"assesses\" : 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must first know the equation for the volume of a sphere.\r\nThe equation is V $$= \\\\frac{4}{3} \\\\pi r^3$$\r\nThen plug the radius into the equation for r, yielding \r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times 4 \\\\times 4 \\\\times 4 = 85.3\\\\pi$$\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$88.3\\\\pi$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.\r\nThe equation is V $$= \\\\frac{4}{3} \\\\pi r^3$$\r\nThen plug the radius into the equation for r, yielding \r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times 4 \\\\times 4 \\\\times 4 = 85.3\\\\pi$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$77.3\\\\pi$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.\r\nThe equation is V $$= \\\\frac{4}{3} \\\\pi r^3$$\r\nThen plug the radius into the equation for r, yielding \r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times 4 \\\\times 4 \\\\times 4 = 85.3\\\\pi$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$90\\\\pi$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.\r\nThe equation is V $$= \\\\frac{4}{3} \\\\pi r^3$$\r\nThen plug the radius into the equation for r, yielding \r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times 4 \\\\times 4 \\\\times 4 = 85.3\\\\pi$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$85.3\\\\pi$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.\r\nThe equation is V $$= \\\\frac{4}{3} \\\\pi r^3$$\r\nThen plug the radius into the equation for r, yielding \r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times 4 \\\\times 4 \\\\times 4 = 85.3\\\\pi$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"To solve for the volume of a sphere, you must first know the equation for the volume of a sphere.\r\nThe equation is V $$= \\\\frac{4}{3} \\\\pi r^3$$\r\nThen plug the radius into the equation for r, yielding \r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times 4 \\\\times 4 \\\\times 4 = 85.3\\\\pi$$\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    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\"@type\": \"Comment\",\n                                    \"text\": \"The volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 10 \\\\times 10 \\\\times 10 = 4186.66 cm^3$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$4189.66 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 10 \\\\times 10 \\\\times 10 = 4186.66 cm^3$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$41.66 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 10 \\\\times 10 \\\\times 10 = 4186.66 cm^3$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$4186.66 cm^3$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 10 \\\\times 10 \\\\times 10 = 4186.66 cm^3$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 10 \\\\times 10 \\\\times 10 = 4186.66 cm^3$$\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"A spherical-shaped tank has a radius of 21 m. Now find the capacity of it in liters to store water in it.\",\n                    \"text\": \"A spherical-shaped tank has a radius of 21 m. Now find the capacity of it in liters to store water in it.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The given values are,<br>\r\nr $$= 21$$ m<br>\r\nNow the volume of a sphere,<br>\r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times r^3$$<br>\r\nV $$= \\\\frac{4}{3} \\\\times 21 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 4 \\\\times 22 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 38808$$ $$m^3$$<br>\r\nSince,<br>\r\n$$1 m^3 = 1000$$ liter<br>\r\nThen the capacity of the tank,<br>\r\n$$= 38,808 m^3 \\\\times 1000$$<br>\r\n$$= 38,808,000$$ liter<br>\r\nSo, 38,808,000 liters of water can be stored in the tank.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"28,808,000 liters\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The given values are,<br>\r\nr $$= 21$$ m<br>\r\nNow the volume of a sphere,<br>\r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times r^3$$<br>\r\nV $$= \\\\frac{4}{3} \\\\times 21 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 4 \\\\times 22 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 38808$$ $$m^3$$<br>\r\nSince,<br>\r\n$$1 m^3 = 1000$$ liter<br>\r\nThen the capacity of the tank,<br>\r\n$$= 38,808 m^3 \\\\times 1000$$<br>\r\n$$= 38,808,000$$ liter<br>\r\nSo, 38,808,000 liters of water can be stored in the tank.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"38,888,000 liters\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The given values are,<br>\r\nr $$= 21$$ m<br>\r\nNow the volume of a sphere,<br>\r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times r^3$$<br>\r\nV $$= \\\\frac{4}{3} \\\\times 21 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 4 \\\\times 22 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 38808$$ $$m^3$$<br>\r\nSince,<br>\r\n$$1 m^3 = 1000$$ liter<br>\r\nThen the capacity of the tank,<br>\r\n$$= 38,808 m^3 \\\\times 1000$$<br>\r\n$$= 38,808,000$$ liter<br>\r\nSo, 38,808,000 liters of water can be stored in the tank.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"30,808,000 liters\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The given values are,<br>\r\nr $$= 21$$ m<br>\r\nNow the volume of a sphere,<br>\r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times r^3$$<br>\r\nV $$= \\\\frac{4}{3} \\\\times 21 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 4 \\\\times 22 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 38808$$ $$m^3$$<br>\r\nSince,<br>\r\n$$1 m^3 = 1000$$ liter<br>\r\nThen the capacity of the tank,<br>\r\n$$= 38,808 m^3 \\\\times 1000$$<br>\r\n$$= 38,808,000$$ liter<br>\r\nSo, 38,808,000 liters of water can be stored in the tank.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"38,808,000 liters\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The given values are,<br>\r\nr $$= 21$$ m<br>\r\nNow the volume of a sphere,<br>\r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times r^3$$<br>\r\nV $$= \\\\frac{4}{3} \\\\times 21 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 4 \\\\times 22 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 38808$$ $$m^3$$<br>\r\nSince,<br>\r\n$$1 m^3 = 1000$$ liter<br>\r\nThen the capacity of the tank,<br>\r\n$$= 38,808 m^3 \\\\times 1000$$<br>\r\n$$= 38,808,000$$ liter<br>\r\nSo, 38,808,000 liters of water can be stored in the tank.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The given values are,<br>\r\nr $$= 21$$ m<br>\r\nNow the volume of a sphere,<br>\r\nV $$= \\\\frac{4}{3} \\\\times \\\\pi \\\\times r^3$$<br>\r\nV $$= \\\\frac{4}{3} \\\\times 21 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 4 \\\\times 22 \\\\times 21 \\\\times 21$$<br>\r\nV $$= 38808$$ $$m^3$$<br>\r\nSince,<br>\r\n$$1 m^3 = 1000$$ liter<br>\r\nThen the capacity of the tank,<br>\r\n$$= 38,808 m^3 \\\\times 1000$$<br>\r\n$$= 38,808,000$$ liter<br>\r\nSo, 38,808,000 liters of water can be stored in the tank.\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The volume of the sphere is $$2100 cm^3$$. What is the radius of the hemisphere formed by cutting the sphere into two equal parts?\",\n                    \"text\": \"The volume of the sphere is $$2100 cm^3$$. What is the radius of the hemisphere formed by cutting the sphere into two equal parts?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Volume of hemisphere $$= \\\\frac{Volume of sphere}{2} = 1050 cm^3$$\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$1200 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Volume of hemisphere $$= \\\\frac{Volume of sphere}{2} = 1050 cm^3$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$1100 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Volume of hemisphere $$= \\\\frac{Volume of sphere}{2} = 1050 cm^3$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$2100 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Volume of hemisphere $$= \\\\frac{Volume of sphere}{2} = 1050 cm^3$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$1050 cm^3$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Volume of hemisphere $$= \\\\frac{Volume of sphere}{2} = 1050 cm^3$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Volume of hemisphere $$= \\\\frac{Volume of sphere}{2} = 1050 cm^3$$\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"What is the volume of a sphere with a radius of 18 cm?\",\n                    \"text\": \"What is the volume of a sphere with a radius of 18 cm?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Diameter of the sphere $$= 18 cm$$<br>\r\nRadius of the sphere $$= \\\\frac{18}{2} = 9 cm$$<br>\r\nThe volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 9 \\\\times 9 \\\\times 9 = 3052.08 cm^3$$\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$8004.78 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter of the sphere $$= 18 cm$$<br>\r\nRadius of the sphere $$= \\\\frac{18}{2} = 9 cm$$<br>\r\nThe volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 9 \\\\times 9 \\\\times 9 = 3052.08 cm^3$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$9304.88 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter of the sphere $$= 18 cm$$<br>\r\nRadius of the sphere $$= \\\\frac{18}{2} = 9 cm$$<br>\r\nThe volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 9 \\\\times 9 \\\\times 9 = 3052.08 cm^3$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$3908.78 cm^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter of the sphere $$= 18 cm$$<br>\r\nRadius of the sphere $$= \\\\frac{18}{2} = 9 cm$$<br>\r\nThe volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 9 \\\\times 9 \\\\times 9 = 3052.08 cm^3$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 3,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$3052.08 cm^3$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Diameter of the sphere $$= 18 cm$$<br>\r\nRadius of the sphere $$= \\\\frac{18}{2} = 9 cm$$<br>\r\nThe volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 9 \\\\times 9 \\\\times 9 = 3052.08 cm^3$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Diameter of the sphere $$= 18 cm$$<br>\r\nRadius of the sphere $$= \\\\frac{18}{2} = 9 cm$$<br>\r\nThe volume of the sphere $$=$$ V $$= \\\\frac{4}{3} \\\\pi r^3 = \\\\frac{4}{3} \\\\times 3.14 \\\\times 9 \\\\times 9 \\\\times 9 = 3052.08 cm^3$$\"\n                      }\n                    } \n\n                    }]}<\/script><\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"10-frequently-asked-questions\">Frequently Asked Questions<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\"><strong>What is the relation between the volume of a sphere and the volume of a cylinder?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The relation between the volume of a sphere<strong> <\/strong>and a cylinder is that the volume of the sphere is two-thirds of the magnitude of the cylinder with a height equal to the sphere&#8217;s diameter and the same radius.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\"><strong>How do you calculate the volume of a sphere when the diameter is given<\/strong>?<\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The general formula for the volume of a sphere is given as V $= \\frac{4}{3} \\pi r^3$ . Let\u2019s say \u201cd\u201d is its diameter. According to the definition of diameter, we have d $= 2r$. From this, we get the value of radius $= \\frac{d}{2}$. Substituting this in the formula, the volume of a sphere can be found.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\"><strong>How do you find the ratio of surface area and volume of spheres?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">For a sphere, the surface area is S $=$ 4*\u03c0*R*R, where R is the sphere\u2019s radius, and \u03c0 is 3.1415&#8230; The volume of a sphere<strong> <\/strong>is V $= \\frac{4 \\times R \\times R \\times R}{3}$. So for a sphere, the surface area to volume ratio is given by: $\\frac{S}{V}=\\frac{3}{R}$.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-3-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\"><strong>What is the unit of measurement for the volume of a sphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-3-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of a sphere<strong> <\/strong>is measured in cubic units, such as $m^3, cm^3,$ etc.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-4-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\"><strong>What are some real-life examples of a sphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-4-d32a24a1-01a1-4ef9-b7ac-687d6d31f33e\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Balls, balloons, globes, marbles, and lollipops are some real-life examples of a sphere.<\/p>\n\n<\/div><\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>Volume of a Sphere &#8211; Introduction Have you ever wondered, \u201cI can draw a circle, but I cannot draw a sphere? Why?\u201d This is because a circle is a two-dimensional figure and does not have volume, whereas a sphere is a three-dimensional shape with no edges or vertices. That means its points lie in space. &#8230; <a title=\"Volume of a Sphere\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/measurement\/volume-of-sphere\" aria-label=\"More on Volume of a Sphere\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-17788","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/17788","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=17788"}],"version-history":[{"count":22,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/17788\/revisions"}],"predecessor-version":[{"id":33052,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/17788\/revisions\/33052"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=17788"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=17788"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=17788"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}