{"id":1806,"date":"2022-04-22T12:02:25","date_gmt":"2022-04-22T12:02:25","guid":{"rendered":"https:\/\/www.splashlearn.com\/article-test-new\/?page_id=1806"},"modified":"2023-02-20T07:27:45","modified_gmt":"2023-02-20T07:27:45","slug":"sphere-definition-with-examples","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere","title":{"rendered":"Sphere \u2013 Definition with Examples"},"content":{"rendered":"\n<div class=\"wp-block-columns eplus-wrapper is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column eplus-wrapper is-layout-flow wp-block-column-is-layout-flow\" style=\"flex-basis:100%\"><div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-de87c496-4975-428c-949e-ce1eb98afa41\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere#0-what-is-sphere>What is Sphere?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere#1-how-is-the-sphere-different-from-other-three-dimensional-objects->How Is the Sphere Different From Other Three-Dimensional Objects?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere#2-important-elements-of-a-sphere-shape->Important Elements of a Sphere Shape<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere#3-solved-examples->Solved Examples<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere#4-practice-problems>Practice Problems<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere#5-frequently-asked-questions>Frequently Asked Questions<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"eplus-wrapper wp-block-heading\" id=\"0-what-is-sphere\">What is Sphere?<\/h2>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"487\" height=\"513\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere1.png\" alt=\"Sphere shape\" class=\"wp-image-11623\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere1.png 487w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere1-285x300.png 285w\" sizes=\"auto, (max-width: 487px) 100vw, 487px\" \/><\/figure>\n\n\n\n<p class=\" eplus-wrapper\">The sphere is a three-dimensional shape, also called the second cousin of a circle. A sphere is round, has no edges, and is a solid shape. The playing ball, balloon, and even light bulbs are examples of sphere shape.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"485\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_02.png\" alt=\"Real-life examples of spherical shape\" class=\"wp-image-11626\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_02.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_02-300x235.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<div id=\"recommended-games-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Games<\/h4><div class=\"recommended-games-container-slides\"><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/identify-cylinders-and-spheres\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geometry_cylinders_spheres_pt.png\" alt=\"Identify Cylinders and Spheres Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Identify Cylinders and Spheres Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/games\">More Games<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-games-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".game-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"eplus-wrapper wp-block-heading\" id=\"1-how-is-the-sphere-different-from-other-three-dimensional-objects-\"><strong>How Is the Sphere Different From Other Three-Dimensional Objects?<\/strong><\/h2>\n\n\n\n<p class=\" eplus-wrapper\">Unlike other three-dimensional objects, such as the cube, cone, and cylinder, the <strong>sphere shape<\/strong> does not have any flat surface, vertex, or edge. It only has a rolling surface.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"444\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_03.png\" alt=\"Three-dimeensional shapes\" class=\"wp-image-11627\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_03.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_03-300x215.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<div id=\"recommended-worksheets-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Worksheets<\/h4><div class=\"recommended-games-container-slides\"><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/cones-and-spheres\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/cones-and-spheres.jpeg\" alt=\"Cones and Spheres Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/worksheets\">More Worksheets<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-worksheets-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".worksheet-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"eplus-wrapper wp-block-heading\" id=\"2-important-elements-of-a-sphere-shape-\"><strong>Important Elements of a Sphere Shape<\/strong><\/h2>\n\n\n\n<p class=\" eplus-wrapper\">&nbsp;The important elements of a <strong>sphere<\/strong> are the following:<\/p>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\" eplus-wrapper\"><strong>Radius:<\/strong> The distance between the center of a <strong>sphere<\/strong> and its surface is called the radius. It is denoted by the letter <em>r<\/em>.<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"485\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_04.png\" alt=\"Radius of a sphere\" class=\"wp-image-11628\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_04.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_04-300x235.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Diameter: <\/strong>Think of the diameter as the longest straight line you can put inside a sphere. The diameter passes through the center and joins two opposite points on the surface of a sphere. Its value is always twice that of the radius. It is denoted by the letter <em>d<\/em>.<em> <\/em>The formula to calculate the diameter of a <strong>sphere<\/strong> is 2<em>r<\/em>.<em>&nbsp;<\/em><\/p>\n\n\n\n<p class=\" eplus-wrapper\"><em>d <\/em>$=$<em> 2r<\/em><\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"429\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_05.png\" alt=\"Diameter of a sphere\" class=\"wp-image-11629\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_05.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_05-300x208.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Circumference: <\/strong>The circumference of a sphere can be defined as the greatest cross-section of a circle that we can cut from a sphere. The formula for the circumference of a sphere is given by 2 $\\times$ \u03c0 $\\times$<em> r.<\/em><\/p>\n\n\n\n<p class=\" eplus-wrapper\"><em>C<\/em>$=$<em> <\/em>2 \u03c0<em> r, <\/em>where r is the radius of the circle and \u03c0 (pi) is approximately 3.14.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"650\" height=\"343\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_06.png\" alt=\"Elements of a sphere\" class=\"wp-image-11624\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_06.png 650w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_06-300x158.png 300w\" sizes=\"auto, (max-width: 650px) 100vw, 650px\" \/><\/figure>\n\n\n\n<p class=\" eplus-wrapper\"><em>Did you know that the equator is one of Earth\u2019s great circles? If you were to cut into the Earth right on its equator, you\u2019d have two halves: the northern and southern hemispheres.<\/em><\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Surface Area: <\/strong>The surface area of a sphere is the total area of its rolling surface. The formula to calculate the surface area of a sphere is given by,<\/p>\n\n\n\n<p class=\" eplus-wrapper\"><em>SA <\/em>$=$<em> 4 r2 <\/em><strong>, <\/strong>where r is the radius of the circle and \u03c0(pi) is approximately 3.14.<\/p>\n\n\n\n<p class=\" eplus-wrapper\">It is measured in square units.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"335\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_07.png\" alt=\"Surface area of a sphere\" class=\"wp-image-11630\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_07.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_07-300x162.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Volume: <\/strong>The volume of a sphere can be defined as the capacity of a liquid that the sphere would hold if it were completely hollow. For example, the amount of water you can fill in an earthen pot defines its volume as a spherical object. The formula to calculate the volume of a sphere is given by,<\/p>\n\n\n\n<p class=\" eplus-wrapper\"><em>V <\/em>$= &nbsp;\\frac{4}{3} r^3$. It is measured in cubic units.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"619\" height=\"467\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_08.png\" alt=\"Volume of a sphere\" class=\"wp-image-11625\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_08.png 619w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2022\/04\/sphere-shape_08-300x226.png 300w\" sizes=\"auto, (max-width: 619px) 100vw, 619px\" \/><\/figure>\n\n\n\n<h2 class=\"eplus-wrapper wp-block-heading\" id=\"3-solved-examples-\"><strong>Solved Examples<\/strong><\/h2>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Example 1: If the radius of a sphere is 5 cm, find its circumference.<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\">We know that the circumference of a sphere is given by&nbsp;<\/p>\n\n\n\n<p class=\" eplus-wrapper\">C $= 2 \\times$ \u03c0 $\\times$<em> r.<\/em><\/p>\n\n\n\n<p class=\" eplus-wrapper\">For the given sphere, r $= 5$ cm.<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Therefore, circumference of the given sphere $= 2 \\times 3.14 \\times 5 = 31.4$ cm.<\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Example 2: If the radius of a sphere is 10 cm, find its surface area.<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\">We know that the surface area of a sphere is given by&nbsp;<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Surface Area $= 4$<em> r2<\/em><\/p>\n\n\n\n<p class=\" eplus-wrapper\">For the given sphere, r $= 10$ cm.<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Substituting the value of \u201c<em>r<\/em>\u201d in the formula, we get,<\/p>\n\n\n\n<p class=\" eplus-wrapper\">SA $= 4 \\times 3.14 \\times 10 \\times 10$<\/p>\n\n\n\n<p class=\" eplus-wrapper\">SA $= 4 \\times 3.14 \\times 100$<\/p>\n\n\n\n<p class=\" eplus-wrapper\">SA $= 1256$ cm\u00b2&nbsp;<\/p>\n\n\n\n<p class=\" eplus-wrapper\">Therefore, the surface area<strong> <\/strong>of this<strong> <\/strong>sphere is<strong> <\/strong>$1256$ cm\u00b2.<\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Example 3: What is the volume of a sphere of radius 7 cm?<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\" eplus-wrapper\">We know that the volume of a sphere is given by<\/p>\n\n\n\n<p class=\" eplus-wrapper\"><em>V <\/em>$= &nbsp;43$<em> r3<\/em><\/p>\n\n\n\n<p class=\" eplus-wrapper\">For the given sphere, r $= 7$ cm<\/p>\n\n\n\n<p class=\" eplus-wrapper\">V $= 43 \\times 3.14 \\times 7 \\times 7 \\times 7$<\/p>\n\n\n\n<p class=\" eplus-wrapper\">V $= 43 \\times 3.14 \\times 343$<\/p>\n\n\n\n<p class=\" eplus-wrapper\">V $= 1436.02$<strong> <\/strong>cm\u00b3&nbsp;Therefore, the volume<strong> <\/strong>of the given sphere is $1436.02$ cm\u00b3<\/p>\n\n\n\n<h2 class=\"eplus-wrapper wp-block-heading\" id=\"4-practice-problems\">Practice Problems<\/h2>\n\n\n\n<p class=\" eplus-wrapper\"><div class=\"spq_wrapper\"><h2 style=\"display:none;\">Sphere -\u00a0 Definition With Examples<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">If the radius of a sphere is 25 cm, find its diameter.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">25 cm<\/div><div class=\"spq_answer_block\" data-value=\"1\">50 cm<\/div><div class=\"spq_answer_block\" data-value=\"2\">5 cm<\/div><div class=\"spq_answer_block\" data-value=\"3\">75 cm<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 50 cm<br\/>We know that the diameter of a sphere is given by d $=$ 2r, where r is the radius.<br>\r\nFor the given sphere, r $= 25$ cm<br>\r\nTherefore, diameter of the given sphere $= 2 \\times 25 = 50$ cm<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">If the diameter of a sphere is 64 cm, find its radius.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">128 cm<\/div><div class=\"spq_answer_block\" data-value=\"1\">104 cm<\/div><div class=\"spq_answer_block\" data-value=\"2\">32 cm<\/div><div class=\"spq_answer_block\" data-value=\"3\">16 cm<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 32 cm<br\/>We know that the diameter of the sphere is given by d $= 2$r.<br>\r\nWhere the radius is r.<br>\r\nTherefore, for the given sphere:<br>\r\n$64 = 2 \\times$r<br>\r\nTherefore, r $= \\frac{64}{2} = 32$ cm.<br>\r\nAnd we get 32 cm as our answer.<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">If the radius of a sphere is 14 cm, find its circumference.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">87.92 cm<\/div><div class=\"spq_answer_block\" data-value=\"1\">50.11 cm<\/div><div class=\"spq_answer_block\" data-value=\"2\">44.05 cm<\/div><div class=\"spq_answer_block\" data-value=\"3\">70.35 cm<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 87.92 cm<br\/>The formula for calculating the circumference of a sphere $= 2$$\u03c0$r<br>\r\nThe radius of the given sphere $= 14$ cm<br>\r\nTherefore, Circumference of the given sphere $= 2 \\times 3.14 \\times 14 = 87.92$ cm<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">4<\/span><h3 class=\"sqp_question_text\">If the radius of a sphere is 20 cm, find its surface area.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">4455 cm\u00b2<\/div><div class=\"spq_answer_block\" data-value=\"1\">5024 cm\u00b2<\/div><div class=\"spq_answer_block\" data-value=\"2\">5045 cm\u00b2<\/div><div class=\"spq_answer_block\" data-value=\"3\">4455 cm\u00b2<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 5024 cm\u00b2<br\/>The radius of the given sphere $= 21$ cm<br>\r\nThe formula for calculating the surface area of a sphere, $4\u03c0r\u00b2$<br>\r\nTherefore,<br>\r\nThe surface area of a given sphere $= 4 \\times 3.14 \\times 20 \\times 20 = 4 \\times 3.14 \\times 400 = 5024$ cm$^{2}$<\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  \"beginner\",\n        \"assesses\" : \"Attend this quiz & Test your knowledge.\",\n        \"educationalAlignment\": [\n              {\n                \"@type\": \"AlignmentObject\",\n                \"alignmentType\": \"educationalSubject\",\n                \"targetName\": \"Math\"\n              }] ,\n        \"name\": \"Sphere -\u00a0 Definition With Examples\",        \n        \"about\": {\n                \"@type\": \"Thing\",\n                \"name\": \"Sphere\"\n        },  \n        \"hasPart\": [{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"If the radius of a sphere is 25 cm, find its diameter.\",\n                    \"text\": \"If the radius of a sphere is 25 cm, find its diameter.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"We know that the diameter of a sphere is given by d $$=$$ 2r, where r is the radius.<br>\r\nFor the given sphere, r $$= 25$$ cm<br>\r\nTherefore, diameter of the given sphere $$= 2 \\\\times 25 = 50$$ cm\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"25 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the diameter of a sphere is given by d $$=$$ 2r, where r is the radius.<br>\r\nFor the given sphere, r $$= 25$$ cm<br>\r\nTherefore, diameter of the given sphere $$= 2 \\\\times 25 = 50$$ cm\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"5 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the diameter of a sphere is given by d $$=$$ 2r, where r is the radius.<br>\r\nFor the given sphere, r $$= 25$$ cm<br>\r\nTherefore, diameter of the given sphere $$= 2 \\\\times 25 = 50$$ cm\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"75 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the diameter of a sphere is given by d $$=$$ 2r, where r is the radius.<br>\r\nFor the given sphere, r $$= 25$$ cm<br>\r\nTherefore, diameter of the given sphere $$= 2 \\\\times 25 = 50$$ cm\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"50 cm\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"We know that the diameter of a sphere is given by d $$=$$ 2r, where r is the radius.<br>\r\nFor the given sphere, r $$= 25$$ cm<br>\r\nTherefore, diameter of the given sphere $$= 2 \\\\times 25 = 50$$ cm\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"We know that the diameter of a sphere is given by d $$=$$ 2r, where r is the radius.<br>\r\nFor the given sphere, r $$= 25$$ cm<br>\r\nTherefore, diameter of the given sphere $$= 2 \\\\times 25 = 50$$ cm\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"If the diameter of a sphere is 64 cm, find its radius.\",\n                    \"text\": \"If the diameter of a sphere is 64 cm, find its radius.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"We know that the diameter of the sphere is given by d $$= 2$$r.<br>\r\nWhere the radius is r.<br>\r\nTherefore, for the given sphere:<br>\r\n$$64 = 2 \\\\times$$r<br>\r\nTherefore, r $$= \\\\frac{64}{2} = 32$$ cm.<br>\r\nAnd we get 32 cm as our answer.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"128 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the diameter of the sphere is given by d $$= 2$$r.<br>\r\nWhere the radius is r.<br>\r\nTherefore, for the given sphere:<br>\r\n$$64 = 2 \\\\times$$r<br>\r\nTherefore, r $$= \\\\frac{64}{2} = 32$$ cm.<br>\r\nAnd we get 32 cm as our answer.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"104 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the diameter of the sphere is given by d $$= 2$$r.<br>\r\nWhere the radius is r.<br>\r\nTherefore, for the given sphere:<br>\r\n$$64 = 2 \\\\times$$r<br>\r\nTherefore, r $$= \\\\frac{64}{2} = 32$$ cm.<br>\r\nAnd we get 32 cm as our answer.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"16 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the diameter of the sphere is given by d $$= 2$$r.<br>\r\nWhere the radius is r.<br>\r\nTherefore, for the given sphere:<br>\r\n$$64 = 2 \\\\times$$r<br>\r\nTherefore, r $$= \\\\frac{64}{2} = 32$$ cm.<br>\r\nAnd we get 32 cm as our answer.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"32 cm\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"We know that the diameter of the sphere is given by d $$= 2$$r.<br>\r\nWhere the radius is r.<br>\r\nTherefore, for the given sphere:<br>\r\n$$64 = 2 \\\\times$$r<br>\r\nTherefore, r $$= \\\\frac{64}{2} = 32$$ cm.<br>\r\nAnd we get 32 cm as our answer.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"We know that the diameter of the sphere is given by d $$= 2$$r.<br>\r\nWhere the radius is r.<br>\r\nTherefore, for the given sphere:<br>\r\n$$64 = 2 \\\\times$$r<br>\r\nTherefore, r $$= \\\\frac{64}{2} = 32$$ cm.<br>\r\nAnd we get 32 cm as our answer.\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"If the radius of a sphere is 14 cm, find its circumference.\",\n                    \"text\": \"If the radius of a sphere is 14 cm, find its circumference.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The formula for calculating the circumference of a sphere $$= 2$$$$\u03c0$$r<br>\r\nThe radius of the given sphere $$= 14$$ cm<br>\r\nTherefore, Circumference of the given sphere $$= 2 \\\\times 3.14 \\\\times 14 = 87.92$$ cm\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"50.11 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The formula for calculating the circumference of a sphere $$= 2$$$$\u03c0$$r<br>\r\nThe radius of the given sphere $$= 14$$ cm<br>\r\nTherefore, Circumference of the given sphere $$= 2 \\\\times 3.14 \\\\times 14 = 87.92$$ cm\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"44.05 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The formula for calculating the circumference of a sphere $$= 2$$$$\u03c0$$r<br>\r\nThe radius of the given sphere $$= 14$$ cm<br>\r\nTherefore, Circumference of the given sphere $$= 2 \\\\times 3.14 \\\\times 14 = 87.92$$ cm\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"70.35 cm\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The formula for calculating the circumference of a sphere $$= 2$$$$\u03c0$$r<br>\r\nThe radius of the given sphere $$= 14$$ cm<br>\r\nTherefore, Circumference of the given sphere $$= 2 \\\\times 3.14 \\\\times 14 = 87.92$$ cm\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"87.92 cm\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The formula for calculating the circumference of a sphere $$= 2$$$$\u03c0$$r<br>\r\nThe radius of the given sphere $$= 14$$ cm<br>\r\nTherefore, Circumference of the given sphere $$= 2 \\\\times 3.14 \\\\times 14 = 87.92$$ cm\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The formula for calculating the circumference of a sphere $$= 2$$$$\u03c0$$r<br>\r\nThe radius of the given sphere $$= 14$$ cm<br>\r\nTherefore, Circumference of the given sphere $$= 2 \\\\times 3.14 \\\\times 14 = 87.92$$ cm\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"If the radius of a sphere is 20 cm, find its surface area.\",\n                    \"text\": \"If the radius of a sphere is 20 cm, find its surface area.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The radius of the given sphere $$= 21$$ cm<br>\r\nThe formula for calculating the surface area of a sphere, $$4\u03c0r\u00b2$$<br>\r\nTherefore,<br>\r\nThe surface area of a given sphere $$= 4 \\\\times 3.14 \\\\times 20 \\\\times 20 = 4 \\\\times 3.14 \\\\times 400 = 5024$$ cm$$^{2}$$\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"4455 cm\u00b2\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The radius of the given sphere $$= 21$$ cm<br>\r\nThe formula for calculating the surface area of a sphere, $$4\u03c0r\u00b2$$<br>\r\nTherefore,<br>\r\nThe surface area of a given sphere $$= 4 \\\\times 3.14 \\\\times 20 \\\\times 20 = 4 \\\\times 3.14 \\\\times 400 = 5024$$ cm$$^{2}$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"5045 cm\u00b2\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The radius of the given sphere $$= 21$$ cm<br>\r\nThe formula for calculating the surface area of a sphere, $$4\u03c0r\u00b2$$<br>\r\nTherefore,<br>\r\nThe surface area of a given sphere $$= 4 \\\\times 3.14 \\\\times 20 \\\\times 20 = 4 \\\\times 3.14 \\\\times 400 = 5024$$ cm$$^{2}$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"4455 cm\u00b2\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The radius of the given sphere $$= 21$$ cm<br>\r\nThe formula for calculating the surface area of a sphere, $$4\u03c0r\u00b2$$<br>\r\nTherefore,<br>\r\nThe surface area of a given sphere $$= 4 \\\\times 3.14 \\\\times 20 \\\\times 20 = 4 \\\\times 3.14 \\\\times 400 = 5024$$ cm$$^{2}$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"5024 cm\u00b2\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The radius of the given sphere $$= 21$$ cm<br>\r\nThe formula for calculating the surface area of a sphere, $$4\u03c0r\u00b2$$<br>\r\nTherefore,<br>\r\nThe surface area of a given sphere $$= 4 \\\\times 3.14 \\\\times 20 \\\\times 20 = 4 \\\\times 3.14 \\\\times 400 = 5024$$ cm$$^{2}$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The radius of the given sphere $$= 21$$ cm<br>\r\nThe formula for calculating the surface area of a sphere, $$4\u03c0r\u00b2$$<br>\r\nTherefore,<br>\r\nThe surface area of a given sphere $$= 4 \\\\times 3.14 \\\\times 20 \\\\times 20 = 4 \\\\times 3.14 \\\\times 400 = 5024$$ cm$$^{2}$$\"\n                      }\n                    } \n\n                    }]}<\/script><\/p>\n\n\n\n<h2 class=\"eplus-wrapper wp-block-heading\" id=\"5-frequently-asked-questions\">Frequently Asked Questions<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-b5140ffc-fd82-4412-8242-c9db087c420e\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-b5140ffc-fd82-4412-8242-c9db087c420e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-b5140ffc-fd82-4412-8242-c9db087c420e\"><strong>What is a hemisphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-b5140ffc-fd82-4412-8242-c9db087c420e\">\n\n<p>Simply put, the hemisphere is half of a <strong>sphere<\/strong>. If you cut a <strong>sphere<\/strong> into exactly two halves, each half would be considered a hemisphere.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-b5140ffc-fd82-4412-8242-c9db087c420e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-b5140ffc-fd82-4412-8242-c9db087c420e\"><strong>What are the differences between a circle and a sphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-b5140ffc-fd82-4412-8242-c9db087c420e\">\n\n<p>To begin with, a circle and a <strong>sphere<\/strong> are different shapes. The following are a few of the main differences between them:<\/p>\n\n\n\n<p><strong>Circle: <\/strong>A circle is a two-dimensional shape. It refers to a closed curved line. A circle does not have any volume.<\/p>\n\n\n\n<p><strong>Sphere: <\/strong>A sphere has a three-dimensional shape. It is a round object. A sphere has volume.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-b5140ffc-fd82-4412-8242-c9db087c420e\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-b5140ffc-fd82-4412-8242-c9db087c420e\"><strong>Give a few common examples of spheres in real life.<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-b5140ffc-fd82-4412-8242-c9db087c420e\">\n\n<p>Marbles, balls, oranges, yarn, and bubbles are a few common examples of sphere shapes in real life.<\/p>\n\n<\/div><\/div>\n<\/div><\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>What is Sphere? The sphere is a three-dimensional shape, also called the second cousin of a circle. A sphere is round, has no edges, and is a solid shape. The playing ball, balloon, and even light bulbs are examples of sphere shape.&nbsp; Recommended Games Identify Cylinders and Spheres Game Play More Games How Is the &#8230; <a title=\"Sphere \u2013 Definition with Examples\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/sphere\" aria-label=\"More on Sphere \u2013 Definition with Examples\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-1806","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/1806","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=1806"}],"version-history":[{"count":12,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/1806\/revisions"}],"predecessor-version":[{"id":24907,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/1806\/revisions\/24907"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=1806"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=1806"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=1806"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}