{"id":23491,"date":"2023-02-03T04:23:13","date_gmt":"2023-02-03T04:23:13","guid":{"rendered":"https:\/\/www.splashlearn.com\/math-vocabulary\/?page_id=23491"},"modified":"2024-02-05T16:07:16","modified_gmt":"2024-02-05T16:07:16","slug":"surface-area-of-sphere","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere","title":{"rendered":"Surface Area of Sphere"},"content":{"rendered":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-a47dd122-1a18-4698-a0cf-0897539e3dc2\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere#0-what-is-the-surface-area-of-a-sphere>What Is the Surface Area of a Sphere?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere#2-derivation-of-surface-area-of-sphere>Derivation of Surface Area of Sphere<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere#3-formula-of-surface-area-of-sphere->Formula of Surface Area of Sphere<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere#8-solved-examples>Solved Examples<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere#9-practice-problems>Practice Problems<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere#10-frequently-asked-questions>Frequently Asked Questions<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"0-what-is-the-surface-area-of-a-sphere\">What Is the Surface Area of a Sphere?<\/h2>\n\n\n\n<p class=\"eplus-wrapper\">The surface area of a sphere is the region or area covered by the outer, curved surface of the sphere.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">A sphere is a three-dimensional solid with every point on the surface at equal distances from the center. In simple words, any solid, round object shaped like a ball is a sphere.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">The radius of a sphere is the distance between the surface and the center of the sphere. While one endpoint of radius is on the surface, the other lies at the center of that sphere.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"623\" height=\"607\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/parts-of-a-sphere.png\" alt=\"Parts of a sphere\" class=\"wp-image-37136\" title=\"Parts of a sphere\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/parts-of-a-sphere.png 623w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/parts-of-a-sphere-300x292.png 300w\" sizes=\"auto, (max-width: 623px) 100vw, 623px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper\">Read on to know the exact definition of the surface area of a sphere,<strong> <\/strong>along with the derivation of the formula.&nbsp;<\/p>\n\n\n\n<div id=\"recommended-games-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Games<\/h4><div class=\"recommended-games-container-slides\"><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/add-to-find-the-area\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_find_area_pt.png\" alt=\"Add to Find the Area Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Add to Find the Area Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/area-of-composite-figure\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_grannys_rescue_10_gm.png\" alt=\"Area of Composite Figure Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Area of Composite Figure Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/area-with-unit-squares-and-side-lengths\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_area_unit_sq_side_length_pt.png\" alt=\"Area with Unit Squares and Side Lengths Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Area with Unit Squares and Side Lengths Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/area-word-problems-on-product-of-fractions\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/fractions_real_life_prob_area_pt.png\" alt=\"Area Word Problems on Product of Fractions Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Area Word Problems on Product of Fractions Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/build-the-area\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_grannys_rescue_3_4_5_gm.png\" alt=\"Build the Area Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Build the Area Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/determine-the-area-of-rectilinear-shapes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_area_rectilinear_shapes_pt.png\" alt=\"Determine the Area of Rectilinear Shapes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Determine the Area of Rectilinear Shapes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-area-by-multiplying-side-lengths\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_area_multi_side_length_1_pt.png\" alt=\"Find Area by Multiplying Side Lengths Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Area by Multiplying Side Lengths Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-area-in-square-units\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_grannys_rescue_1_2_gm.png\" alt=\"Find Area in Square Units Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Area in Square Units Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-area-by-multiplying-the-side-lengths\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_area_multiply_pt.png\" alt=\"Find the Area by Multiplying the Side Lengths Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Area by Multiplying the Side Lengths Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-area-of-shapes-using-unit-shapes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div 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});\n    <\/script><h2 class=\"wp-block-heading eplus-wrapper\" id=\"1-definition-of-the-surface-area-of-a-sphere-\">Definition of the Surface Area of a Sphere&nbsp;<\/h2>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"615\" height=\"554\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere-formula.png\" alt=\"Surface Area of a Sphere Formula\" class=\"wp-image-37138\" title=\"Surface Area of a Sphere Formula\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere-formula.png 615w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere-formula-300x270.png 300w\" sizes=\"auto, (max-width: 615px) 100vw, 615px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper\">The surface area of a sphere is defined as the region covered by the sphere\u2019s outer surface in three-dimensional space. Since the sphere is curved, its curved surface area is the same as the total area of the sphere.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">It is expressed as:<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Surface area $(TSA) =$ Curved Surface Area $(CSA) = 4\\pi r^{2}$ square units<\/p>\n\n\n\n<div id=\"recommended-worksheets-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Worksheets<\/h4><div class=\"recommended-games-container-slides\"><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/add-fractions-using-area-models\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/add-fractions-using-area-models.jpeg\" alt=\"Add Fractions using Area Models Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/add-like-fractions-using-area-models\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/add-like-fractions-using-area-models.jpeg\" alt=\"Add Like Fractions using Area Models Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/add-mixed-numbers-and-fractions-using-area-models\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/add-mixed-numbers-and-fractions-using-area-models.jpeg\" alt=\"Add Mixed Numbers and Fractions using Area Models Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/compare-fractions-using-area-model\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/compare-fractions-using-area-model.jpeg\" alt=\"Compare Fractions Using Area Model Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/complete-the-area-model\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/complete-the-area-model.jpeg\" alt=\"Complete the Area Model Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/complete-the-equation-for-the-area-model\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/complete-the-equation-for-the-area-model.jpeg\" alt=\"Complete the Equation for the Area Model Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/cones-and-spheres\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/cones-and-spheres.jpeg\" alt=\"Cones and Spheres Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/convert-mixed-numbers-using-area-models\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/convert-mixed-numbers-using-area-models.jpeg\" alt=\"Convert Mixed Numbers Using Area Models Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" >\r\n\t\t<\/div><\/a>\r\n<\/div><div class=\"worksheet-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-worksheets\/create-area-models-to-multiply-unit-fractions\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"worksheets_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t    <div class=\"worksheet-card-container-inner-block\">\r\n\t        <img decoding=\"async\" class=\"worksheet-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/cms_assets\/s\/math-worksheets\/create-area-models-to-multiply-unit-fractions.jpeg\" alt=\"Create Area Models to Multiply Unit Fractions Worksheet\">\r\n\t    <\/div>\r\n\t\t<div class=\"worksheet-card-container-inner\" 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to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading eplus-wrapper\" id=\"2-derivation-of-surface-area-of-sphere\">Derivation of Surface Area of Sphere<\/h2>\n\n\n\n<p class=\"eplus-wrapper\">Now that you have understood the surface area of a sphere, it\u2019s time to derive the formula.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">The Greek mathematician Archimedes discovered that the surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder is the same as the diameter of the sphere. According to Archimedes, a sphere can fit into a cylinder so that the height of the cylinder becomes the diameter of the sphere.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"618\" height=\"477\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere-using-the-surface-area-of-a-cylinder.png\" alt=\"Surface area of a sphere using the surface area of a cylinder\" class=\"wp-image-37139\" title=\"Surface area of a sphere using the surface area of a cylinder\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere-using-the-surface-area-of-a-cylinder.png 618w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere-using-the-surface-area-of-a-cylinder-300x232.png 300w\" sizes=\"auto, (max-width: 618px) 100vw, 618px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper\">So, if the radius of a sphere and cylinder is \u201cr,\u201d then<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Surface Area of Sphere $=$ Lateral Surface Area of Cylinder<\/p>\n\n\n\n<p class=\"eplus-wrapper\">We know that the lateral surface area of a cylinder $= 2\\pi r h$,&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">where \u201cr\u201d is the radius and &#8216;h&#8217; is the height of the cylinder.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Now the height of the cylinder = the diameter of the sphere.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">So, $h = 2r$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Substituting the value of \u201ch\u201d as \u201c2r,\u201d the<strong> <\/strong>surface area equation of the sphere<strong> <\/strong>becomes&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$2\\pi r h = 2\\pi r(2r) = 4\\pi r^{2}$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"3-formula-of-surface-area-of-sphere-\"><strong>Formula of Surface Area of Sphere<\/strong><\/h2>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"617\" height=\"433\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere.png\" alt=\"Surface area of a sphere\" class=\"wp-image-37140\" title=\"Surface area of a sphere\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere.png 617w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/surface-area-of-a-sphere-300x211.png 300w\" sizes=\"auto, (max-width: 617px) 100vw, 617px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper\">So, what&#8217;s the surface area of a sphere formula?<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Surface area of the sphere $= 4\\pi r^{2}$, where \u201cr\u201d is the sphere&#8217;s radius.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">In terms of diameter, when \u201cd\u201d is the diameter of the sphere, the surface area of a sphere is expressed as S $= 4\\pi (\\frac{d}{2})^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">There are three types of surface area in solids: lateral surface area (LSA), curved surface area (CSA), and total surface area (TSA).&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading eplus-wrapper\" id=\"4-curved-surface-area-of-sphere\">Curved Surface Area of Sphere<\/h3>\n\n\n\n<p class=\"eplus-wrapper\">The curved surface area is the sum of areas of all the curved regions of the solid.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">The curved surface area of a sphere<strong> <\/strong>is the same as the total surface area of the sphere since the sphere is a completely curved shape. Therefore, the formula for the curved surface area of a sphere is&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">CSA of a sphere $= 4\\pi r^{2}$, where \u201cr\u201d is the sphere\u2019s radius.<\/p>\n\n\n\n<h3 class=\"wp-block-heading eplus-wrapper\" id=\"5-lateral-surface-area-of-sphere\">Lateral Surface Area of Sphere<\/h3>\n\n\n\n<p class=\"eplus-wrapper\">The lateral surface area of a solid figure is the area of all the regions except its top and bottom faces.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">The lateral surface area of a sphere is expressed as $LSA = 4\\pi r^{2}$, where r is the sphere&#8217;s radius.&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading eplus-wrapper\" id=\"6-total-surface-area-of-sphere\">Total Surface Area of Sphere<\/h3>\n\n\n\n<p class=\"eplus-wrapper\">The total surface area of a solid includes the area of all sides, including the top and bottom faces or bases.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Since the sphere has no flat surfaces, there is no difference between its curved surface area and the total surface area.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Therefore, the total surface area of a sphere $=$ the curved surface area of a sphere.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Hence, surface area $(TSA) = CSA = 4\\pi r^{2}$ square units<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"7-how-to-find-the-surface-area-of-a-sphere\">How to Find the Surface Area of a Sphere<\/h2>\n\n\n\n<p class=\"eplus-wrapper\">Let&#8217;s understand how to calculate the surface area of a sphere using an example. If the radius of a sphere is 8 cm. What will be its surface area?<\/p>\n\n\n\n<p class=\"eplus-wrapper\">The steps to find the surface area of the sphere are given below:<\/p>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">Step 1:&nbsp;<\/li>\n<\/ul>\n\n\n\n<p class=\"eplus-wrapper\">Note the radius of the sphere. In the above example, the radius of the sphere is 8 cm. If the diameter is given, divide the diameter by 2 to get the radius.<\/p>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">Step 2:<\/li>\n<\/ul>\n\n\n\n<p class=\"eplus-wrapper\">Now, surface area of sphere<strong> <\/strong>$= 4\\pi r^{2}$, so after substituting the value of $r = 8$, we get, surface area of sphere $= 4\\pi r^{2} = 4 \\times 3.14 \\times 8^{2} = 4 \\times 3.14 \\times 64= 803.84$<\/p>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">Step 3:&nbsp;<\/li>\n<\/ul>\n\n\n\n<p class=\"eplus-wrapper\">Hence, the surface area of the sphere is $803.84$ $cm^{2}$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"8-solved-examples\">Solved Examples<\/h2>\n\n\n\n<p class=\"eplus-wrapper\"><strong>1.&nbsp;Calculate the curved surface area of a sphere having a radius of 3 cm. Use <\/strong>$\\pi = 3.14$<strong>.&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\">We know,<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Curved surface area = Total surface area $= 4 \\pi r^{2}$ square units<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= 4 \\times 3.14 \\times 3 \\times 3$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Therefore, the curved surface area of a sphere$= 113.04$ $cm^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>2. A ball in the shape of a sphere has a surface area of <\/strong>$221.76$ $cm^{2}$<strong>. Calculate its diameter.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:<\/strong>&nbsp;Let the radius of the sphere be r&nbsp;cm.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">We know the surface area of a sphere&nbsp;$=4\\pi r^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$221.76$ $cm^{2} = 4\\pi r^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$r^{2} = 221.76\/4 \\pi$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;$r = \\sqrt{17.64}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;$r = 4.2$cm<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Therefore, the diameter of the sphere $= 4.2 \\times 2= \u200b8.4$ cm.<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>3. A spherical ball has a surface area of 2464 sq. feet. Find the radius of the ball.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:<\/strong> The surface area of a sphere $= 2464$ sq. feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\">We know the surface area of a sphere (SA) $= 4 \\pi r^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$2464$ $cm^{2} = 4 \\pi r^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$2464$ $cm^{2} = 4 \\times \\frac{22}{7} \\times r^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$r = 14$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>4. Find the ratio between the surface areas of two spheres whose radii are in the ratio of 4:3.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\">Given that the ratio between the radii of two spheres $= 4:3$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">We know that,<\/p>\n\n\n\n<p class=\"eplus-wrapper\">The surface area of a sphere $= 4\\pi r^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">From the equation, we can say that the surface area of a sphere is directly proportional to the square of its radius.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$\\Rightarrow \\frac{A_{1}}{A_{2}}&nbsp;= \\frac{r^{2}_{1}}{r^{2}_{2}}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$\\Rightarrow \\frac{A_{1}}{A_{2}}&nbsp;= \\frac{16}{9}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Therefore, the ratio between the two spheres&#8217; total surface areas is 16:9.<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>5. Find the cost required to paint a spherical ball with a radius of 10 feet. The painting cost of the ball is <\/strong>$\\$4$<strong> per square feet.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\">Given that the radius of the ball $= 10$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\">We know that,<\/p>\n\n\n\n<p class=\"eplus-wrapper\">The surface area of a sphere $= 4 \\pi  r^{2}$&nbsp;square units<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$= 4 \\times (3.14) \\times (10)^{2}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$= 1256$ square feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Hence, the total cost to paint the ball $= 4 \\times 1256 = \\$5024$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"9-practice-problems\">Practice Problems<\/h2>\n\n\n\n<p class=\"eplus-wrapper\"><div class=\"spq_wrapper\"><h2 style=\"display:none;\">Surface Area of Sphere<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"3\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">If the diameter of a sphere is 16 units, what is the surface area of the sphere?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">50 square units<\/div><div class=\"spq_answer_block\" data-value=\"1\">4.5 square units<\/div><div class=\"spq_answer_block\" data-value=\"2\">80 square units<\/div><div class=\"spq_answer_block\" data-value=\"3\">804.5 square units<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 804.5 square units<br\/>Diameter $= 16$ units\r\nRadius(r) $= \\frac{16}{2} = 8$ units\r\nSurface area of the sphere $= 4\\pi r^{2}$\r\n$= 4 \\times \\frac{22}{7} \\times 8^{2}$\r\n$\\approx 804.57$ units<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">What's the diameter of a sphere whose surface area is 616 square inches?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">14 inches<\/div><div class=\"spq_answer_block\" data-value=\"1\">16 inches<\/div><div class=\"spq_answer_block\" data-value=\"2\">18 inches<\/div><div class=\"spq_answer_block\" data-value=\"3\">20 inches<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 14 inches<br\/>Given that the curved surface area of the sphere $= 616$ sq. in<br>\r\nWe know that,<br>\r\nThe total surface area of a sphere $= 4 \\pi r^{2}$  square units<br>\r\n$\\Rightarrow 4 \\pi r^{2}  = 616$<br>\r\n$\\Rightarrow 4 \\times \\frac{22}{7} \\times r^{2}  = 616$<br>\r\n$\\Rightarrow r^{2}  = \\frac{(616 \\times 7)}{(4 \\times 22)} = 49$<br>\r\n$\\Rightarrow r = 7$ inches<br>\r\nWe know, diameter $= 2 \\times$ radius $= 2 \\times 7 = 14$ inches<br>\r\nHence, the diameter of the sphere is 14 inches.<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">A solid sphere has a diameter of 28 feet. What is the curved surface area of the sphere?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">2364 sq. feet<\/div><div class=\"spq_answer_block\" data-value=\"1\">2464 sq. feet<\/div><div class=\"spq_answer_block\" data-value=\"2\">2444 sq. feet<\/div><div class=\"spq_answer_block\" data-value=\"3\">2664 sq. feet<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 2464 sq. feet<br\/>We know that the curved surface area of a sphere of radius r is given by<br>\r\nHere, the radius of the sphere is $= 14$ feet<br>\r\n\u2234 The curved surface area of the sphere $= 2464$ sq. feet<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">4<\/span><h3 class=\"sqp_question_text\">The curved surface area of a sphere is $5544$ $cm^{2}$. What will be the diameter of the sphere?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">44<\/div><div class=\"spq_answer_block\" data-value=\"1\">22<\/div><div class=\"spq_answer_block\" data-value=\"2\">42<\/div><div class=\"spq_answer_block\" data-value=\"3\">20<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 42<br\/>The surface area of a sphere $=5544$ $cm^{2}$<br>\r\nSo,$4 \\pi r^{2} = 5544$<br>\r\n$r^{2} = 441$<br>\r\n$r = 21$ cm<br>\r\nDiameter $= 2 \\times 21 = 42$ cm<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"3\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">5<\/span><h3 class=\"sqp_question_text\">The surface area of a sphere equals lateral surface area of ___ with the same radius and with height same as diameter of sphere.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">Cone<\/div><div class=\"spq_answer_block\" data-value=\"1\">Cube<\/div><div class=\"spq_answer_block\" data-value=\"2\">Pyramid<\/div><div class=\"spq_answer_block\" data-value=\"3\">Cylinder<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: Cylinder<br\/>The surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder matches the diameter of the sphere.<\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  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\"@type\": \"Comment\",\n                      \"text\": \"Diameter $$= 16$$ units\r\nRadius(r) $$= \\\\frac{16}{2} = 8$$ units\r\nSurface area of the sphere $$= 4\\\\pi r^{2}$$\r\n$$= 4 \\\\times \\\\frac{22}{7} \\\\times 8^{2}$$\r\n$$\\\\approx 804.57$$ units\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"50 square units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter $$= 16$$ units\r\nRadius(r) $$= \\\\frac{16}{2} = 8$$ units\r\nSurface area of the sphere $$= 4\\\\pi r^{2}$$\r\n$$= 4 \\\\times \\\\frac{22}{7} \\\\times 8^{2}$$\r\n$$\\\\approx 804.57$$ units\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"4.5 square units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter $$= 16$$ units\r\nRadius(r) $$= \\\\frac{16}{2} = 8$$ units\r\nSurface area of the sphere $$= 4\\\\pi r^{2}$$\r\n$$= 4 \\\\times \\\\frac{22}{7} \\\\times 8^{2}$$\r\n$$\\\\approx 804.57$$ units\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"80 square units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter $$= 16$$ units\r\nRadius(r) $$= \\\\frac{16}{2} = 8$$ units\r\nSurface area of the sphere $$= 4\\\\pi r^{2}$$\r\n$$= 4 \\\\times \\\\frac{22}{7} \\\\times 8^{2}$$\r\n$$\\\\approx 804.57$$ units\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 3,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"804.5 square units\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Diameter $$= 16$$ units\r\nRadius(r) $$= \\\\frac{16}{2} = 8$$ units\r\nSurface area of the sphere $$= 4\\\\pi r^{2}$$\r\n$$= 4 \\\\times \\\\frac{22}{7} \\\\times 8^{2}$$\r\n$$\\\\approx 804.57$$ units\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Diameter $$= 16$$ units\r\nRadius(r) $$= \\\\frac{16}{2} = 8$$ units\r\nSurface area of the sphere $$= 4\\\\pi r^{2}$$\r\n$$= 4 \\\\times \\\\frac{22}{7} \\\\times 8^{2}$$\r\n$$\\\\approx 804.57$$ units\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"What's the diameter of a sphere whose surface area is 616 square inches?\",\n                    \"text\": \"What's the diameter of a sphere whose surface area is 616 square inches?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Given that the curved surface area of the sphere $$= 616$$ sq. in<br>\r\nWe know that,<br>\r\nThe total surface area of a sphere $$= 4 \\\\pi r^{2}$$  square units<br>\r\n$$\\\\Rightarrow 4 \\\\pi r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow 4 \\\\times \\\\frac{22}{7} \\\\times r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow r^{2}  = \\\\frac{(616 \\\\times 7)}{(4 \\\\times 22)} = 49$$<br>\r\n$$\\\\Rightarrow r = 7$$ inches<br>\r\nWe know, diameter $$= 2 \\\\times$$ radius $$= 2 \\\\times 7 = 14$$ inches<br>\r\nHence, the diameter of the sphere is 14 inches.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"16 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Given that the curved surface area of the sphere $$= 616$$ sq. in<br>\r\nWe know that,<br>\r\nThe total surface area of a sphere $$= 4 \\\\pi r^{2}$$  square units<br>\r\n$$\\\\Rightarrow 4 \\\\pi r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow 4 \\\\times \\\\frac{22}{7} \\\\times r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow r^{2}  = \\\\frac{(616 \\\\times 7)}{(4 \\\\times 22)} = 49$$<br>\r\n$$\\\\Rightarrow r = 7$$ inches<br>\r\nWe know, diameter $$= 2 \\\\times$$ radius $$= 2 \\\\times 7 = 14$$ inches<br>\r\nHence, the diameter of the sphere is 14 inches.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"18 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Given that the curved surface area of the sphere $$= 616$$ sq. in<br>\r\nWe know that,<br>\r\nThe total surface area of a sphere $$= 4 \\\\pi r^{2}$$  square units<br>\r\n$$\\\\Rightarrow 4 \\\\pi r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow 4 \\\\times \\\\frac{22}{7} \\\\times r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow r^{2}  = \\\\frac{(616 \\\\times 7)}{(4 \\\\times 22)} = 49$$<br>\r\n$$\\\\Rightarrow r = 7$$ inches<br>\r\nWe know, diameter $$= 2 \\\\times$$ radius $$= 2 \\\\times 7 = 14$$ inches<br>\r\nHence, the diameter of the sphere is 14 inches.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"20 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Given that the curved surface area of the sphere $$= 616$$ sq. in<br>\r\nWe know that,<br>\r\nThe total surface area of a sphere $$= 4 \\\\pi r^{2}$$  square units<br>\r\n$$\\\\Rightarrow 4 \\\\pi r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow 4 \\\\times \\\\frac{22}{7} \\\\times r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow r^{2}  = \\\\frac{(616 \\\\times 7)}{(4 \\\\times 22)} = 49$$<br>\r\n$$\\\\Rightarrow r = 7$$ inches<br>\r\nWe know, diameter $$= 2 \\\\times$$ radius $$= 2 \\\\times 7 = 14$$ inches<br>\r\nHence, the diameter of the sphere is 14 inches.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"14 inches\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Given that the curved surface area of the sphere $$= 616$$ sq. in<br>\r\nWe know that,<br>\r\nThe total surface area of a sphere $$= 4 \\\\pi r^{2}$$  square units<br>\r\n$$\\\\Rightarrow 4 \\\\pi r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow 4 \\\\times \\\\frac{22}{7} \\\\times r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow r^{2}  = \\\\frac{(616 \\\\times 7)}{(4 \\\\times 22)} = 49$$<br>\r\n$$\\\\Rightarrow r = 7$$ inches<br>\r\nWe know, diameter $$= 2 \\\\times$$ radius $$= 2 \\\\times 7 = 14$$ inches<br>\r\nHence, the diameter of the sphere is 14 inches.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Given that the curved surface area of the sphere $$= 616$$ sq. in<br>\r\nWe know that,<br>\r\nThe total surface area of a sphere $$= 4 \\\\pi r^{2}$$  square units<br>\r\n$$\\\\Rightarrow 4 \\\\pi r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow 4 \\\\times \\\\frac{22}{7} \\\\times r^{2}  = 616$$<br>\r\n$$\\\\Rightarrow r^{2}  = \\\\frac{(616 \\\\times 7)}{(4 \\\\times 22)} = 49$$<br>\r\n$$\\\\Rightarrow r = 7$$ inches<br>\r\nWe know, diameter $$= 2 \\\\times$$ radius $$= 2 \\\\times 7 = 14$$ inches<br>\r\nHence, the diameter of the sphere is 14 inches.\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"A solid sphere has a diameter of 28 feet. What is the curved surface area of the sphere?\",\n                    \"text\": \"A solid sphere has a diameter of 28 feet. What is the curved surface area of the sphere?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"We know that the curved surface area of a sphere of radius r is given by<br>\r\nHere, the radius of the sphere is $$= 14$$ feet<br>\r\n\u2234 The curved surface area of the sphere $$= 2464$$ sq. feet\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"2364 sq. feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the curved surface area of a sphere of radius r is given by<br>\r\nHere, the radius of the sphere is $$= 14$$ feet<br>\r\n\u2234 The curved surface area of the sphere $$= 2464$$ sq. feet\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"2444 sq. feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the curved surface area of a sphere of radius r is given by<br>\r\nHere, the radius of the sphere is $$= 14$$ feet<br>\r\n\u2234 The curved surface area of the sphere $$= 2464$$ sq. feet\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"2664 sq. feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"We know that the curved surface area of a sphere of radius r is given by<br>\r\nHere, the radius of the sphere is $$= 14$$ feet<br>\r\n\u2234 The curved surface area of the sphere $$= 2464$$ sq. feet\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"2464 sq. feet\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"We know that the curved surface area of a sphere of radius r is given by<br>\r\nHere, the radius of the sphere is $$= 14$$ feet<br>\r\n\u2234 The curved surface area of the sphere $$= 2464$$ sq. feet\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"We know that the curved surface area of a sphere of radius r is given by<br>\r\nHere, the radius of the sphere is $$= 14$$ feet<br>\r\n\u2234 The curved surface area of the sphere $$= 2464$$ sq. feet\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The curved surface area of a sphere is $$5544$$ $$cm^{2}$$. What will be the diameter of the sphere?\",\n                    \"text\": \"The curved surface area of a sphere is $$5544$$ $$cm^{2}$$. What will be the diameter of the sphere?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The surface area of a sphere $$=5544$$ $$cm^{2}$$<br>\r\nSo,$$4 \\\\pi r^{2} = 5544$$<br>\r\n$$r^{2} = 441$$<br>\r\n$$r = 21$$ cm<br>\r\nDiameter $$= 2 \\\\times 21 = 42$$ cm\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"44\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The surface area of a sphere $$=5544$$ $$cm^{2}$$<br>\r\nSo,$$4 \\\\pi r^{2} = 5544$$<br>\r\n$$r^{2} = 441$$<br>\r\n$$r = 21$$ cm<br>\r\nDiameter $$= 2 \\\\times 21 = 42$$ cm\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"22\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The surface area of a sphere $$=5544$$ $$cm^{2}$$<br>\r\nSo,$$4 \\\\pi r^{2} = 5544$$<br>\r\n$$r^{2} = 441$$<br>\r\n$$r = 21$$ cm<br>\r\nDiameter $$= 2 \\\\times 21 = 42$$ cm\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"20\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The surface area of a sphere $$=5544$$ $$cm^{2}$$<br>\r\nSo,$$4 \\\\pi r^{2} = 5544$$<br>\r\n$$r^{2} = 441$$<br>\r\n$$r = 21$$ cm<br>\r\nDiameter $$= 2 \\\\times 21 = 42$$ cm\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"42\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The surface area of a sphere $$=5544$$ $$cm^{2}$$<br>\r\nSo,$$4 \\\\pi r^{2} = 5544$$<br>\r\n$$r^{2} = 441$$<br>\r\n$$r = 21$$ cm<br>\r\nDiameter $$= 2 \\\\times 21 = 42$$ cm\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The surface area of a sphere $$=5544$$ $$cm^{2}$$<br>\r\nSo,$$4 \\\\pi r^{2} = 5544$$<br>\r\n$$r^{2} = 441$$<br>\r\n$$r = 21$$ cm<br>\r\nDiameter $$= 2 \\\\times 21 = 42$$ cm\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The surface area of a sphere equals lateral surface area of ___ with the same radius and with height same as diameter of sphere.\",\n                    \"text\": \"The surface area of a sphere equals lateral surface area of ___ with the same radius and with height same as diameter of sphere.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder matches the diameter of the sphere.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"Cone\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder matches the diameter of the sphere.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"Cube\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder matches the diameter of the sphere.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"Pyramid\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder matches the diameter of the sphere.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 3,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"Cylinder\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder matches the diameter of the sphere.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The surface area of a sphere is the same as the lateral surface area of a cylinder such that the radius of the sphere is the same as the radius of the cylinder and the height of the cylinder matches the diameter of the sphere.\"\n                      }\n                    } \n\n                    }]}<\/script><\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"10-frequently-asked-questions\">Frequently Asked Questions<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-f58bb215-2548-4b66-be50-18f1842ef322\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-f58bb215-2548-4b66-be50-18f1842ef322\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-f58bb215-2548-4b66-be50-18f1842ef322\"><strong>What is the surface area of a hemisphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-f58bb215-2548-4b66-be50-18f1842ef322\">\n\n<p class=\"eplus-wrapper\">The surface area of a hemisphere is equal to the sum of its curved surface area and base area. It is expressed as SA(hemisphere) $= 3 \\pi r^{2}$ square units.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-f58bb215-2548-4b66-be50-18f1842ef322\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-f58bb215-2548-4b66-be50-18f1842ef322\"><strong>What is the surface area of a sphere in terms of diameter?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-f58bb215-2548-4b66-be50-18f1842ef322\">\n\n<p class=\"eplus-wrapper\">The surface area of a sphere formula in terms of diameter is given as $\\pi D^{2}$, where \u201cD\u201d is the sphere&#8217;s diameter.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-f58bb215-2548-4b66-be50-18f1842ef322\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-f58bb215-2548-4b66-be50-18f1842ef322\"><strong>How does the surface area of a sphere change when its radius is halved?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-f58bb215-2548-4b66-be50-18f1842ef322\">\n\n<p class=\"eplus-wrapper\">As the surface area of a sphere $= 4\\pi r^{2}$ . If we replace \u201cr\u201d with $\\frac{r}{2}$, the formula becomes $4\\pi (\\frac{r}{2})^{2} = \\pi r^{2}$, which is one-fourth of the original surface area.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-3-f58bb215-2548-4b66-be50-18f1842ef322\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-f58bb215-2548-4b66-be50-18f1842ef322\"><strong>How does the surface area of a sphere change when its radius is tripled?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-3-f58bb215-2548-4b66-be50-18f1842ef322\">\n\n<p class=\"eplus-wrapper\">As the surface area of a sphere $= 4\\pi r^{2}$, so, if we replace \u201cr\u201d with $3r$, we get the formula, surface area $= 4\\pi (3r)^{2} = 36\\pi r^{2}$.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-4-f58bb215-2548-4b66-be50-18f1842ef322\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-f58bb215-2548-4b66-be50-18f1842ef322\"><strong>How many surfaces does a sphere have?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-4-f58bb215-2548-4b66-be50-18f1842ef322\">\n\n<p class=\"eplus-wrapper\">A sphere has only one face, which is a curved surface. It does not have any flat faces.<\/p>\n\n<\/div><\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>What Is the Surface Area of a Sphere? The surface area of a sphere is the region or area covered by the outer, curved surface of the sphere.&nbsp; A sphere is a three-dimensional solid with every point on the surface at equal distances from the center. In simple words, any solid, round object shaped like &#8230; <a title=\"Surface Area of Sphere\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/surface-area-of-sphere\" aria-label=\"More on Surface Area of Sphere\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-23491","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/23491","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=23491"}],"version-history":[{"count":20,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/23491\/revisions"}],"predecessor-version":[{"id":39954,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/23491\/revisions\/39954"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=23491"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=23491"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=23491"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}