{"id":26828,"date":"2023-03-24T18:54:28","date_gmt":"2023-03-24T18:54:28","guid":{"rendered":"https:\/\/www.splashlearn.com\/math-vocabulary\/?page_id=26828"},"modified":"2024-01-10T17:39:52","modified_gmt":"2024-01-10T17:39:52","slug":"volume-of-hemisphere-definition-formula-examples","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere","title":{"rendered":"Volume of Hemisphere: Definition, Formula, Examples"},"content":{"rendered":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-3267072c-6f5e-4888-b515-581e1a4b8712\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere#0-what-is-a-hemisphere>What is a Hemisphere?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere#2-hemisphere-volume-formula>Hemisphere Volume: Formula<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere#3-how-to-find-the-volume-of-a-hemisphere>How to Find the Volume of a Hemisphere<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere#6-solved-examples-on-the-volume-of-a-hemisphere>Solved Examples on the Volume of a Hemisphere<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere#7-practice-problems-on-the-volume-of-a-hemisphere>Practice Problems on the Volume of a Hemisphere<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere#8-frequently-asked-questions-on-the-volume-of-a-hemisphere>Frequently Asked Questions on the Volume of a Hemisphere<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"0-what-is-a-hemisphere\">What is a Hemisphere?<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The prefix \u201chemi\u201d has a Greek origin and it means \u201chalf.\u201d Thus, a <strong>hemisphere simply refers to the half of the sphere<\/strong>. If a sphere is divided into two equal parts, we will get two hemispheres.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">You may have come across the word hemisphere in the real life context of planet Earth. For example, if you cut the Earth right on its equator, you\u2019d have two halves: the northern and southern hemispheres.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"477\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/hemisphere-real-life-examples.png\" alt=\"Hemisphere: real-life examples\" class=\"wp-image-37353\" title=\"Hemisphere: real-life examples\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/hemisphere-real-life-examples.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/hemisphere-real-life-examples-300x231.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading eplus-wrapper\" id=\"1-hemisphere-definition\">Hemisphere: Definition<\/h3>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>In geometry, the hemisphere is a 3D solid figure that is exactly half of the sphere. When a sphere is cut into two equal parts at the center then the hemisphere is formed. It has 1 flat circular base and 1 curved surface.<\/strong>&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"404\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/hemispheres-formed-by-cutting-a-sphere-into-two-equal-parts.png\" alt=\"Hemispheres formed by cutting a sphere into two equal parts\" class=\"wp-image-37355\" title=\"Hemispheres formed by cutting a sphere into two equal parts\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/hemispheres-formed-by-cutting-a-sphere-into-two-equal-parts.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/hemispheres-formed-by-cutting-a-sphere-into-two-equal-parts-300x195.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<div id=\"recommended-games-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Games<\/h4><div class=\"recommended-games-container-slides\"><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/estimate-the-volume-of-a-given-shape\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_estimate_vol_1_pt.png\" alt=\"Estimate the Volume of a Given Shape Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Estimate the Volume of a Given Shape Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-volume-of-the-3d-shape-by-iterating\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_iterate_vol_1_pt.png\" alt=\"Find the Volume of the 3D Shape by Iterating Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Volume of the 3D Shape by Iterating Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-volume-using-unit-cubes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_unit_cubes_2_pt.png\" alt=\"Find the Volume using Unit Cubes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Volume using Unit Cubes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-volume-using-the-formula\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_formula_pt.png\" alt=\"Find Volume using the Formula Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Volume using the Formula Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/introduction-to-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_unit_cubes_1_pt.png\" alt=\"Introduction to Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Introduction to Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/iterate-and-find-the-total-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_iterate_vol_2_pt.png\" alt=\"Iterate and Find the Total Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Iterate and Find the Total Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/solve-the-word-problems-related-to-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_word_prob_pt.png\" alt=\"Solve the Word Problems Related to Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Solve the Word Problems Related to Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/use-the-3d-shapes-to-estimate-the-volume\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_estimate_vol_2_pt.png\" alt=\"Use the 3D Shapes to Estimate the Volume Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Use the 3D Shapes to Estimate the Volume Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/games\">More Games<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-games-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".game-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading eplus-wrapper\" id=\"2-hemisphere-volume-formula\">Hemisphere Volume: Formula<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>The volume of a hemisphere is the total capacity of the hemisphere. The volume of hemisphere is measured in terms of cubic units, such as <\/strong>$in^3,\\; ft^3$<strong>, etc.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of sphere is calculated using the formula $V = \\frac{4}{3} \\pi r^3$.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">So, what is the volume of a hemisphere?&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"348\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/volume-of-hemisphere-formula.png\" alt=\"Volume of hemisphere: formula\" class=\"wp-image-37356\" title=\"Volume of hemisphere: formula\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/volume-of-hemisphere-formula.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2024\/01\/volume-of-hemisphere-formula-300x168.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We know the hemisphere is simply half of the sphere. The volume of the hemisphere is also half the volume of the sphere.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Thus, the formula for volume of a hemisphere $= \\frac{2}{3} \\pi r^3$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"3-how-to-find-the-volume-of-a-hemisphere\">How to Find the Volume of a Hemisphere<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume is the amount of space that a 3D shape takes up.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Let us recall the formula of the volume of the hemisphere first.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Volume of Hemisphere <\/strong>$= \\frac{2}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Here, the symbol stands for pi. We use the value of as 3.14 or $\\frac{22}{7}$.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The r stands for radius, and it is the distance from the center point of the sphere.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We simply have to put the values in the above formula and find the volume of the hemisphere.<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"4-facts-about-volume-of-hemisphere\">Facts about Volume of Hemisphere<\/h2>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">A hemisphere consists of only one curved surface area.<\/li>\n<\/ul>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">The volume of the hemisphere is given as $\\frac{2}{3} \\pi r^3$ cubic units, where \u201cr\u201d is the radius of the hemisphere and &nbsp; is equal to $\\frac{22}{7}$ or 3.14 approximately.<\/li>\n<\/ul>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">A hemisphere has two surface areas, i.e., curved surface area and the total surface area. The curved surface area of a hemisphere is only the area covered by the curved surface, while the surface area of a hemisphere is the sum of the curved surface area and the base area of the hemisphere.<\/li>\n<\/ul>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">As volume is a 3D concept including length, width, and height, volume of the hemisphere is measured in cubic units.&nbsp;<\/li>\n<\/ul>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">The spherical coordinates of the hemisphere are $x = r \\; cos \\theta sin\\; \\Phi ,\\; y = r sin \\theta cos\\; \\Phi$, and $z = r\\; cos\\; \\Phi$.<\/li>\n<\/ul>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">Hemisphere Equation<\/li>\n<\/ul>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">When the radius \u201cR\u201d is centered at the origin, the equation of hemisphere is given by<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$x^2 + y^2 + z^2 = R^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $(x_0,\\; y_0,\\; z_0)$ is written as follows:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$(x\\;-\\;x_0)^2 + (y\\;-\\;y_0)^2 + (z\\;-\\;z_0)^2 = R^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The spherical coordinates of the hemisphere are given as follows:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$x = r\\; cos\\; \\theta sin\\; \\Phi$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$y = r\\; sin\\; \\theta cos\\; \\Phi$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">$z = r\\; cos\\; \\Phi$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"5-conclusion\">Conclusion<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of a hemisphere is the total capacity of the hemisphere. In this article, we learnt in detail about the volume of the hemisphere formula, definition, and facts. Let\u2019s solve some examples and practice problems to understand the concept better.<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"6-solved-examples-on-the-volume-of-a-hemisphere\">Solved Examples on the Volume of a Hemisphere<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>1.<\/strong> <strong>The diameter of a hemisphere is 6 ft. Calculate the volume.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Given data,<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Diameter of hemisphere $= 6$ ft.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Radius of hemisphere $= 3$ ft.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We know that, volume of hemisphere $= \\frac{2}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{2}{3} \\times 3.14 \\times 3^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{2}{3} \\times 3.14 \\times 27$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= 2 \\times 3.14 \\times 9$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= 56.52\\; ft^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of the hemisphere is $56.52\\; ft^3$.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>2. A hemispherical bowl has an inner radius of 4 inches. How much water can it contain?<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Radius of hemispherical bowl $= 4$ in.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We know that, volume of hemisphere $= \\frac{2}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{2}{3} \\times 3.14 \\times 4^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{2}{3} \\times 3.14 \\times 64$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{401.92}{3}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= 133.97\\; in^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Thus, the hemispherical bowl can contain $133.97\\; in^3$ of water.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>3. Find the radius of the hemispherical bowl if the area of its base is 154 unit square. <\/strong>$( \\pi = \\frac{22}{7})$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Area of the base $= 154$ unit square.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We know that the area of the base of the hemisphere $=&nbsp;\\pi r^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">So, substituting value in the above formula the equation becomes:&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;$154 = \\frac{22}{7} \\times r^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;$r^2&nbsp; = 154 \\times \\frac{7}{22}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;$r^2&nbsp; = \\frac{1078}{22}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;$r^2&nbsp; =&nbsp; 49$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;$r &nbsp; = \\sqrt{49}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;$r &nbsp; = 7$ units.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The radius of the hemispherical bowl is 7 units.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>4. Find the volume of the hemisphere when its area of the circular base is 616 sq. units.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Given data:&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Area of circular base $= 616$ sq.units.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We know that:<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The formula for the area of the circular base $= \\pi r^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">So, substituting value in the above formula the equation becomes,<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;$616 = \\frac{22}{7} \\times r^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;$r^2&nbsp; =&nbsp; 616 \\times \\frac{7}{22}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;$r^2&nbsp; = \\frac{4312}{22}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;$r^2&nbsp; =&nbsp;196$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp; $r &nbsp; = \\sqrt{196}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;$r &nbsp; = 14$ units.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Thus, the volume of the hemisphere equation can be written as<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Volume of hemisphere $= \\frac{2}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{2}{3} \\times 3.14 \\times 14^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$&nbsp;= \\frac{2}{3} \\times 3.14 \\times 2744$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{17232.32}{3}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; $= 5744.10\\; unit^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of the hemisphere is $5744.10\\; unit^3$.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>5. A sphere with a radius of 5 inches is divided into two equal halves. Calculate the volume of each produced hemisphere.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Given data,&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Radius of sphere $= 5$ inch.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">We know that the sphere and hemisphere have the same radius.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Thus, radius of hemisphere $= 5$ inch<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Volume of each hemisphere $= V = \\frac{2}{3} \\pi r^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$=&nbsp; \\frac{2}{3} \\times 3.14 \\times 5^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{2}{3} \\times 3.14 \\times 125$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= \\frac{785}{3}$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$= 261.66\\; in^3$<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The volume of each hemisphere is $261.66\\; in^3$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"7-practice-problems-on-the-volume-of-a-hemisphere\">Practice Problems on the Volume of a Hemisphere<\/h2>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\"><div class=\"spq_wrapper\"><h2 style=\"display:none;\">Volume of Hemisphere: Definition, Formula, Examples<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">The hemisphere is  __________  of the sphere.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$\\frac{1}{2}$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$\\frac{1}{4}$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$\\frac{3}{4}$<\/div><div class=\"spq_answer_block\" data-value=\"3\">None of these<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $\\frac{1}{2}$<br\/>The prefix hemi means \u201chalf.\u201d Thus, a hemisphere is simply half of the sphere.<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">The volume of the hemisphere is calculated using the formula __________.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$\\pi r^2$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$\\frac{4}{3} \\pi r^3$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$\\frac{2}{3} \\pi r^3$<\/div><div class=\"spq_answer_block\" data-value=\"3\">None of these.<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $\\frac{2}{3} \\pi r^3$<br\/>$\\pi r^2$ is the formula for the area of the circle. $\\frac{4}{3} \\pi r^3$ is the formula to derive the volume of the sphere. The volume of the hemisphere is half the volume of the sphere. So, the volume of the hemisphere is $\\frac{2}{3} \\pi r^3$.<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $(x_0,\\; y_0,\\; z_0)$ is written as __________.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$(x_0\\;-\\;x )^2 + (y_0\\;-\\;y )^2 + (z_0 \\;-\\;z )^2 = R^2$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$(x\\;-\\;x_0 )^2 + (y\\;-\\;y_0)^2 + (z\\;-\\;z_0 )^2 = R^2$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$(x + x_0 )^2 + (y + y_0 )^2 + (z + z_0)^2 = R^2$<\/div><div class=\"spq_answer_block\" data-value=\"3\">$(x\\;-\\;x_0 )^2 \\;-\\; (y\\;-\\;y_0 )^2 \\;-\\; (z\\;-\\;z_0 )^2 = R^2$<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $(x\\;-\\;x_0 )^2 + (y\\;-\\;y_0)^2 + (z\\;-\\;z_0 )^2 = R^2$<br\/>The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $(x_0,\\; y_0,\\; z_0)$ is written as $(x\\;-\\;x_0 )^2 + (y\\;-\\;y_0) 2 + (z\\;-\\;z_0 )^2 = R^2$<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">4<\/span><h3 class=\"sqp_question_text\">Which of the following statements about hemispheres is NOT TRUE ?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">The volume of hemisphere is measured in terms of cubic units<\/div><div class=\"spq_answer_block\" data-value=\"1\">The hemisphere is exactly half of the sphere.<\/div><div class=\"spq_answer_block\" data-value=\"2\">Hemisphere is a 2D figure.<\/div><div class=\"spq_answer_block\" data-value=\"3\">It has one flat circular base and one curved surface.<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: Hemisphere is a 2D figure.<br\/>Hemisphere is a 3D figure.<\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  \"beginner\",\n        \"assesses\" : \"Attend this quiz & Test your knowledge.\",\n        \"educationalAlignment\": [\n              {\n                \"@type\": \"AlignmentObject\",\n                \"alignmentType\": \"educationalSubject\",\n                \"targetName\": \"Math\"\n              }] ,\n        \"name\": \"Volume of Hemisphere: Definition, Formula, Examples\",        \n        \"about\": {\n                \"@type\": \"Thing\",\n                \"name\": \"Volume of Hemisphere\"\n        },  \n        \"hasPart\": [{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The hemisphere is  __________  of the sphere.\",\n                    \"text\": \"The hemisphere is  __________  of the sphere.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The prefix hemi means \u201chalf.\u201d Thus, a hemisphere is simply half of the sphere.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\frac{1}{4}$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The prefix hemi means \u201chalf.\u201d Thus, a hemisphere is simply half of the sphere.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\frac{3}{4}$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The prefix hemi means \u201chalf.\u201d Thus, a hemisphere is simply half of the sphere.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"None of these\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The prefix hemi means \u201chalf.\u201d Thus, a hemisphere is simply half of the sphere.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$\\\\frac{1}{2}$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The prefix hemi means \u201chalf.\u201d Thus, a hemisphere is simply half of the sphere.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The prefix hemi means \u201chalf.\u201d Thus, a hemisphere is simply half of the sphere.\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The volume of the hemisphere is calculated using the formula __________.\",\n                    \"text\": \"The volume of the hemisphere is calculated using the formula __________.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"$$\\\\pi r^2$$ is the formula for the area of the circle. $$\\\\frac{4}{3} \\\\pi r^3$$ is the formula to derive the volume of the sphere. The volume of the hemisphere is half the volume of the sphere. So, the volume of the hemisphere is $$\\\\frac{2}{3} \\\\pi r^3$$.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\pi r^2$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$\\\\pi r^2$$ is the formula for the area of the circle. $$\\\\frac{4}{3} \\\\pi r^3$$ is the formula to derive the volume of the sphere. The volume of the hemisphere is half the volume of the sphere. So, the volume of the hemisphere is $$\\\\frac{2}{3} \\\\pi r^3$$.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\frac{4}{3} \\\\pi r^3$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$\\\\pi r^2$$ is the formula for the area of the circle. $$\\\\frac{4}{3} \\\\pi r^3$$ is the formula to derive the volume of the sphere. The volume of the hemisphere is half the volume of the sphere. So, the volume of the hemisphere is $$\\\\frac{2}{3} \\\\pi r^3$$.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"None of these.\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$\\\\pi r^2$$ is the formula for the area of the circle. $$\\\\frac{4}{3} \\\\pi r^3$$ is the formula to derive the volume of the sphere. The volume of the hemisphere is half the volume of the sphere. So, the volume of the hemisphere is $$\\\\frac{2}{3} \\\\pi r^3$$.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$\\\\frac{2}{3} \\\\pi r^3$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"$$\\\\pi r^2$$ is the formula for the area of the circle. $$\\\\frac{4}{3} \\\\pi r^3$$ is the formula to derive the volume of the sphere. The volume of the hemisphere is half the volume of the sphere. So, the volume of the hemisphere is $$\\\\frac{2}{3} \\\\pi r^3$$.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"$$\\\\pi r^2$$ is the formula for the area of the circle. $$\\\\frac{4}{3} \\\\pi r^3$$ is the formula to derive the volume of the sphere. The volume of the hemisphere is half the volume of the sphere. So, the volume of the hemisphere is $$\\\\frac{2}{3} \\\\pi r^3$$.\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as __________.\",\n                    \"text\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as __________.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as $$(x\\\\;-\\\\;x_0 )^2 + (y\\\\;-\\\\;y_0) 2 + (z\\\\;-\\\\;z_0 )^2 = R^2$$\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$(x_0\\\\;-\\\\;x )^2 + (y_0\\\\;-\\\\;y )^2 + (z_0 \\\\;-\\\\;z )^2 = R^2$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as $$(x\\\\;-\\\\;x_0 )^2 + (y\\\\;-\\\\;y_0) 2 + (z\\\\;-\\\\;z_0 )^2 = R^2$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$(x + x_0 )^2 + (y + y_0 )^2 + (z + z_0)^2 = R^2$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as $$(x\\\\;-\\\\;x_0 )^2 + (y\\\\;-\\\\;y_0) 2 + (z\\\\;-\\\\;z_0 )^2 = R^2$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$(x\\\\;-\\\\;x_0 )^2 \\\\;-\\\\; (y\\\\;-\\\\;y_0 )^2 \\\\;-\\\\; (z\\\\;-\\\\;z_0 )^2 = R^2$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as $$(x\\\\;-\\\\;x_0 )^2 + (y\\\\;-\\\\;y_0) 2 + (z\\\\;-\\\\;z_0 )^2 = R^2$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$(x\\\\;-\\\\;x_0 )^2 + (y\\\\;-\\\\;y_0)^2 + (z\\\\;-\\\\;z_0 )^2 = R^2$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as $$(x\\\\;-\\\\;x_0 )^2 + (y\\\\;-\\\\;y_0) 2 + (z\\\\;-\\\\;z_0 )^2 = R^2$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"The Cartesian form or equation of a hemisphere with the radius \u201cR\u201d at the point $$(x_0,\\\\; y_0,\\\\; z_0)$$ is written as $$(x\\\\;-\\\\;x_0 )^2 + (y\\\\;-\\\\;y_0) 2 + (z\\\\;-\\\\;z_0 )^2 = R^2$$\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"Which of the following statements about hemispheres is NOT TRUE ?\",\n                    \"text\": \"Which of the following statements about hemispheres is NOT TRUE ?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Hemisphere is a 3D figure.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"The volume of hemisphere is measured in terms of cubic units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Hemisphere is a 3D figure.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"The hemisphere is exactly half of the sphere.\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Hemisphere is a 3D figure.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"It has one flat circular base and one curved surface.\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Hemisphere is a 3D figure.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"Hemisphere is a 2D figure.\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Hemisphere is a 3D figure.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Hemisphere is a 3D figure.\"\n                      }\n                    } \n\n                    }]}<\/script><\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"8-frequently-asked-questions-on-the-volume-of-a-hemisphere\">Frequently Asked Questions on the Volume of a Hemisphere<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-6356cd88-5f1e-4654-8269-1600a868915b\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-6356cd88-5f1e-4654-8269-1600a868915b\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-6356cd88-5f1e-4654-8269-1600a868915b\"><strong>What are some real-life examples of a hemisphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-6356cd88-5f1e-4654-8269-1600a868915b\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The examples of hemispheres can be seen in everyday life. Some examples are as follows:<\/p>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">An igloo: The top of the igloo makes up the curved face of the hemisphere, while the base forms its flat face.<\/li>\n\n\n\n<li class=\"eplus-wrapper\">Bowl: If you look at the bowl kept in the utensil cabinet of your kitchen, you can easily observe the hemisphere geometric shape.&nbsp;<\/li>\n\n\n\n<li class=\"eplus-wrapper\">Fruits: If you cut a lemon or an orange exactly in half, you will get two hemispheres.&nbsp;<\/li>\n<\/ul>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"537\" height=\"118\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/03\/Frequently-Asked-Questions_-1.png\" alt=\"Real-life examples of hemispheres\" class=\"wp-image-26832\" title=\"Real-life examples of hemispheres\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/03\/Frequently-Asked-Questions_-1.png 537w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/03\/Frequently-Asked-Questions_-1-300x66.png 300w\" sizes=\"auto, (max-width: 537px) 100vw, 537px\" \/><\/figure>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-6356cd88-5f1e-4654-8269-1600a868915b\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-6356cd88-5f1e-4654-8269-1600a868915b\"><strong>What are the differences between a circle and a sphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-6356cd88-5f1e-4654-8269-1600a868915b\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Circle: A circle is a 2D shape. It refers to a closed curved line. A circle does not have any volume.<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Sphere: A sphere has a 3D shape. It is a round object. A sphere has volume.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-6356cd88-5f1e-4654-8269-1600a868915b\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-6356cd88-5f1e-4654-8269-1600a868915b\"><strong>How do you find the base area of a hemisphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-6356cd88-5f1e-4654-8269-1600a868915b\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The base of the hemisphere is in a circular shape, and therefore, the formula for the base area of the hemisphere is equal to the area of a circle.Thus, the base area of a hemisphere $= \\p r^2$<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-3-6356cd88-5f1e-4654-8269-1600a868915b\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-6356cd88-5f1e-4654-8269-1600a868915b\"><strong>What is the difference between the curved surface area of a hemisphere and the total surface area of a hemisphere?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-3-6356cd88-5f1e-4654-8269-1600a868915b\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Take a look at the image given below:<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"301\" height=\"226\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/03\/Frequently-Asked-Questions_-4.png\" alt=\"Surface area and curved surface area of a hemisphere\" class=\"wp-image-26833\" title=\"Surface area and curved surface area of a hemisphere\"\/><\/figure>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">The curved surface area of the hemisphere is only the area covered by the curved surface. The formula for curved surface area of hemisphere is $2\\pi r^2$. While the surface area of a hemisphere is the sum of the curved surface area and the base area of the hemisphere.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper wp-block-paragraph\">Thus, the total surface area of hemisphere $= 2 \\pi r^2 + \\pi r^2 = 3\\pi r^2$<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-4-6356cd88-5f1e-4654-8269-1600a868915b\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-6356cd88-5f1e-4654-8269-1600a868915b\"><strong>What is a polyhedron? Is the hemisphere a polyhedron?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-4-6356cd88-5f1e-4654-8269-1600a868915b\">\n\n<p class=\"eplus-wrapper wp-block-paragraph\">A three-dimensional shape with flat polygonal faces, straight edges, and sharp corners or vertices is called a polyhedron. Common examples are cubes, prisms, pyramids. A hemisphere is not made up of polygons, so it is not a polyhedron.<\/p>\n\n<\/div><\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>What is a Hemisphere? The prefix \u201chemi\u201d has a Greek origin and it means \u201chalf.\u201d Thus, a hemisphere simply refers to the half of the sphere. If a sphere is divided into two equal parts, we will get two hemispheres. You may have come across the word hemisphere in the real life context of planet &#8230; <a title=\"Volume of Hemisphere: Definition, Formula, Examples\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/volume-of-hemisphere\" aria-label=\"More on Volume of Hemisphere: Definition, Formula, Examples\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-26828","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/26828","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=26828"}],"version-history":[{"count":9,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/26828\/revisions"}],"predecessor-version":[{"id":37357,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/26828\/revisions\/37357"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=26828"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=26828"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=26828"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}