{"id":28365,"date":"2023-05-01T05:43:55","date_gmt":"2023-05-01T05:43:55","guid":{"rendered":"https:\/\/www.splashlearn.com\/math-vocabulary\/?page_id=28365"},"modified":"2024-02-05T09:06:41","modified_gmt":"2024-02-05T09:06:41","slug":"circumference-to-diameter-conversion-formula-meaning-example","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter","title":{"rendered":"Circumference to Diameter: Conversion, Formula, Meaning, Example"},"content":{"rendered":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-92364d20-8941-4a78-93eb-9f1a1266b693\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter#0-what-is-the-circumference-to-diameter-calculator>What Is the Circumference to Diameter Calculator?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter#3-how-to-find-the-diameter-from-circumference>How to Find the Diameter from Circumference<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter#4-how-to-find-the-circumference-from-diameter>How to Find the Circumference from Diameter<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter#7-solved-examples-on-circumference-to-diameter>Solved Examples on Circumference to Diameter<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter#8-practice-problems-on-circumference-to-diameter>Practice Problems on Circumference to Diameter<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter#9-frequently-asked-questions-on-circumference-to-diameter>Frequently Asked Questions on Circumference to Diameter<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"0-what-is-the-circumference-to-diameter-calculator\">What Is the Circumference to Diameter Calculator?<\/h2>\n\n\n\n<p class=\"eplus-wrapper\">The <a href=\"https:\/\/www.easycalculation.com\/measurement\/circumference-to-diameter.php\">circumference to diameter calculator<\/a> is used to find the value of the diameter of a circle for a given value of circumference. To use the calculator, simply enter the measurement of the circumference and click on \u201c<strong>Calculate<\/strong>\u201d to get the result.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">What is the circumference of a circle? <strong>Circumference is the total length of the boundary of the circle<\/strong>. The formula for finding the circumference of the circle is<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = 2\\pi r$ where r is the radius of the circle.<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Diameter is<\/strong><strong> <\/strong><strong>a line segment through the center of a circle with its ends on the circle&#8217;s circumference<\/strong>. In the circle given below, AB is the diameter. Diameter is twice the radius.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = 2r$ where r stands for radius of the circle.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"327\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/11\/diameter-of-a-circle-is-twice-the-radius.png\" alt=\"diameter of a circle is twice the radius\" class=\"wp-image-35807\" title=\"diameter of a circle is twice the radius\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/11\/diameter-of-a-circle-is-twice-the-radius.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/11\/diameter-of-a-circle-is-twice-the-radius-300x158.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\"eplus-wrapper\">Thus, we can write $C = \\pi d$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">where, C is the circumference and d is the diameter.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">To find the diameter, we can rewrite this equation as<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = \\frac{C}{\\pi}$ &nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">So, to find the value of the diameter from circumference, simply divide the circumference by $\\pi$.&nbsp;<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"1-circumference-to-diameter-ratio\">Circumference to Diameter Ratio<\/h2>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Circumference to diameter ratio is the ratio that defines Pi <\/strong>$(\\pi)$<strong>.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\">The radius, diameter, and circumference of a circle are all related through the mathematical constant $\\pi$<strong> (pi)<\/strong>, which is the ratio of a circle&#8217;s circumference to its diameter. \u03c0 is an irrational number. The value of \u03c0 is approximately considered as 3.14159 or $\\frac{22}{7}$.<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Any two circles with different radii are similar as they have the same shape but different size<\/strong>. Thus, the ratio of a circumference of a circle to diameter is always constant for all circles. It never depends on the radius. This value is called pi $(\\pi)$. It is an irrational number.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = 2\\pi r = \\pi d$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Thus, $\\pi = \\frac{C}{d}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">This formula also describes how to find the diameter of a circle with the circumference C. How can we find the diameter of a circle with the circumference C? Divide the circumference value by the number pi $(\\pi)$, or use the formula $d = \\frac{C}{\\pi}$ .<\/p>\n\n\n\n<p class=\"eplus-wrapper\">When the circumference C is placed in a ratio with the diameter d, we get $\\pi$.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full eplus-wrapper\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"408\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/11\/circumference-diameter-and-radius-of-a-circle.png\" alt=\"circumference, diameter, and radius of a circle\" class=\"wp-image-35808\" title=\"circumference, diameter, and radius of a circle\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/11\/circumference-diameter-and-radius-of-a-circle.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/11\/circumference-diameter-and-radius-of-a-circle-300x197.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"2-circumference-to-diameter-formula\">Circumference to Diameter Formula<\/h2>\n\n\n\n<p class=\"eplus-wrapper\">We can find the circumference of a circle either by using the radius or the diameter of the circle. The following are the formulas for finding the circumference of the circle.&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Circumference of circle with radius: <\/strong>$C = 2\\pi r$<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Circumference of circle with diameter:&nbsp; <\/strong>$C = \\pi d$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">where<\/p>\n\n\n\n<ul class=\"eplus-wrapper wp-block-list\">\n<li class=\"eplus-wrapper\">$C =$ Circumference<\/li>\n\n\n\n<li class=\"eplus-wrapper\">$r =$ Radius<\/li>\n\n\n\n<li class=\"eplus-wrapper\">$d =$ Diameter<\/li>\n\n\n\n<li class=\"eplus-wrapper\">$\\pi = \\frac{22}{7}$or $3.14$ (approx)<\/li>\n<\/ul>\n\n\n\n<p class=\"eplus-wrapper\">Thus, the circumference to diameter formula, which is used to find diameter using circumference, can be given as<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Circumference to diameter formula:<\/strong>&nbsp; $d = 2r = \\frac{C}{\\pi}$<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"3-how-to-find-the-diameter-from-circumference\">How to Find the Diameter from Circumference<\/h2>\n\n\n\n<p class=\"eplus-wrapper\"><strong>To find diameter from circumference, simply substitute the value of the diameter in the formula <\/strong>$d = \\frac{C}{\\pi}$ .<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Example: Find the diameter of a circle whose circumference is 6.28 inches.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Here, $C = 6.28$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = \\frac{C}{\\pi} = \\frac{6.28}{3.14} = 2$ in<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"4-how-to-find-the-circumference-from-diameter\">How to Find the Circumference from Diameter<\/h2>\n\n\n\n<p class=\"eplus-wrapper\"><strong>To find circumference from diameter, simply substitute the value of the diameter in the formula <\/strong>C=\u03c0d.<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Example:<\/strong> The diameter of the playground is 70 feet. Find its circumference.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Circumference of the playground $= C= \\pi d$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = \\frac{22}{7}\\times70 = 220$ feet<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"5-how-to-find-the-circumference-of-the-circle-when-area-is-given\">How to Find the Circumference of the Circle When Area Is Given<\/h2>\n\n\n\n<p class=\"eplus-wrapper\">Sometimes, we only know the area of a circle and we have to find the circumference. How to proceed in such cases? Consider an example.<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Example:<\/strong> Area of a circular park is 6.16 square yards. What is the length of the boundary of the park?<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Length of the boundary of circular park $=$ Circumference of the circle&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Area $= 6.16$ square yards<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Area of a circle$ = \\pi r^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$\\frac{22}{7} \\times r^2 = 6.16$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$r^2 = \\frac{6.16 \\times 7}{22} = 1.96$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$r = 1.4$ yards<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = 2 \\times 1.4 = 2.8$ yards<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Circumference of the circular park $= \\pi d = \\frac{22}{7}\\times2.8 = 8.8$ yards<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"6-conclusion\">Conclusion<\/h2>\n\n\n\n<p class=\"eplus-wrapper\">In this article, we learned how to find the diameter of a circle using its circumference. We also explored the important formulas along with examples. Let\u2019s look at some solved examples and practice problems to understand the concepts better.<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"7-solved-examples-on-circumference-to-diameter\">Solved Examples on Circumference to Diameter<\/h2>\n\n\n\n<p class=\"eplus-wrapper\"><strong>1. i) What is the circumference of the circle if the diameter is <\/strong><strong>1.4<\/strong><strong> inches?&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>&nbsp;&nbsp;&nbsp;&nbsp;ii) What is the diameter of a circle if its circumference is <\/strong><strong>1.4<\/strong><strong> inches?<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\">i) Diameter $(d) = 1.4$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;$C = \\pi d$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;$C = \\frac{22}{7}\\times1.4$&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">&nbsp;&nbsp;&nbsp;$C = 22\\times0.2$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = 4.4$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper\">ii) Circumference $= C = 1.4$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = \\frac{C}{pi}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = \\frac{1.4}{3.14}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = 0.4456$ in<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>2. Find the circumference of the circle if the radius is 2.75 inches (Use <\/strong>$\\pi = 3.14$<strong>).<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Radius $(r) = 2.75$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Diameter $= 2r = 2\\times2.75 = 5.5$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = \\pi d = 3.14\\times5.5 = 17.27$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>3. What is the circumference of the circle if the area of the circle is is <\/strong><strong>38.5<\/strong><strong> square feet?<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Area $= \\pi r^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$38.5 = \\frac{22}{7} \\times r^2$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$r^2 = \\frac{38.5\\times7}{22} = 12.25$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$r = 3.5$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Diameter $= 2r = 2\\times3.5 = 7$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = d = \\frac{22}{7}\\times7 = 22$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>4. <\/strong><strong>Find the diameter of a circular garden with circumference 132 feet.<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Circumference $(C) = 132$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Diameter $(d) = \\frac{C}{\\pi}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Diameter $(d) = \\frac{132}{\\pi}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Diameter $(d)= \\frac{132}{1} \\times \\frac{7}{22}$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Diameter $(d)= 42$ feet<\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>5. The circumference of a circle is <\/strong><strong>33<\/strong><strong> inches. Find the diameter of the circle.&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = 33$ inches<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$C = \\pi d$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$33 = \\frac{22}{7} \\times d$<\/p>\n\n\n\n<p class=\"eplus-wrapper\">$d = \\frac{33\\times 7}{22} = 10.5$ inches<\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"8-practice-problems-on-circumference-to-diameter\">Practice Problems on Circumference to Diameter<\/h2>\n\n\n\n<p class=\"eplus-wrapper\"><div class=\"spq_wrapper\"><h2 style=\"display:none;\">Circumference to Diameter: Conversion, Formula, Meaning, Example<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">Find the circumference of painting the circular wall of radius 31.5 yards?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">231 yards<\/div><div class=\"spq_answer_block\" data-value=\"1\">461 yards<\/div><div class=\"spq_answer_block\" data-value=\"2\">462 yards<\/div><div class=\"spq_answer_block\" data-value=\"3\">472 yards<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 462 yards<br\/>Radius $(r) = 31.5$ yards<br>\r\nDiameter $= 2r = 23 \\times 1.5 = 63$ yards<br>\r\n$C = \\pi d = \\frac{22}{7} \\times 63 = 462$ yards<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"3\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">What will be the radius of the circle whose circumference is 242 feet?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">42 feet<\/div><div class=\"spq_answer_block\" data-value=\"1\">63 feet<\/div><div class=\"spq_answer_block\" data-value=\"2\">77 feet<\/div><div class=\"spq_answer_block\" data-value=\"3\">38.5 feet<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 38.5 feet<br\/>$C = 242$ feet<br>\r\n$\\pi d = 242$<br>\r\n$\\frac{22d}{7} = 242$<br>\r\n$d = \\frac{242 \\times 7}{22} = 77$ feet<br>\r\n$r = \\frac{d}{2} = \\frac{77}{2} = 38.5$ feet<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">What will be the area of the circle whose circumference is 44 square inches?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">154 square inches<\/div><div class=\"spq_answer_block\" data-value=\"1\">77 square inches<\/div><div class=\"spq_answer_block\" data-value=\"2\">308 square inches<\/div><div class=\"spq_answer_block\" data-value=\"3\">38.5 square inches<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 154 square inches<br\/>$C = 44$ square inches<br>\r\n$d = 44$<br>\r\n$\\frac{22d}{7} = 44$<br>\r\n$d = \\frac{44 \\times 7}{22} = 14$ inches<br>\r\n$r = \\frac{d}{2} = \\frac{14}{2} = 7$ inches<br>\r\nArea $= \\pi r^2 = \\frac{22}{7}\\times7\\times7 = 154$ square inches<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">4<\/span><h3 class=\"sqp_question_text\">Find the circumference of the circle whose diameter is 8.4 yards?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">27 yards<\/div><div class=\"spq_answer_block\" data-value=\"1\">26.4 yards<\/div><div class=\"spq_answer_block\" data-value=\"2\">25.6 yards<\/div><div class=\"spq_answer_block\" data-value=\"3\">36.2 yards<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 26.4 yards<br\/>$d = 8.4$ yards<br>\r\nCircumference $= C = \\pi d = \\frac{22}{7}\\times8.4 = 26.4$ yards<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"3\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">5<\/span><h3 class=\"sqp_question_text\">If the diameter is doubled, then the circumference will ____.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">become half<\/div><div class=\"spq_answer_block\" data-value=\"1\">stay the same<\/div><div class=\"spq_answer_block\" data-value=\"2\">triple<\/div><div class=\"spq_answer_block\" data-value=\"3\">double<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: double<br\/>Let the new diameter be $2d$.<br>\r\nNew Circumference $= \\pi \\times 2d = 2d$.<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">6<\/span><h3 class=\"sqp_question_text\">Find diameter in terms of Pi using circumference. 6 inch circumference to diameter $=$ ?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$6 \\pi$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$\\frac{6}{\\pi}$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$\\frac{\\pi}{6}$<\/div><div class=\"spq_answer_block\" data-value=\"3\">$3 \\pi$<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $\\frac{6}{\\pi}$<br\/>Diameter $(d) = C \\pi$<br>\r\nDiameter $(d) = 6 \\pi$ <\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  \"beginner\",\n        \"assesses\" : \"Attend this quiz & Test your knowledge.\",\n        \"educationalAlignment\": [\n              {\n                \"@type\": \"AlignmentObject\",\n                \"alignmentType\": \"educationalSubject\",\n                \"targetName\": \"Math\"\n              }] ,\n        \"name\": \"Circumference to Diameter: Conversion, Formula, Meaning, Example\",        \n        \"about\": {\n                \"@type\": \"Thing\",\n                \"name\": \"Circumference to Diameter\"\n        },  \n        \"hasPart\": [{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"Find the circumference of painting the circular wall of radius 31.5 yards?\",\n                    \"text\": \"Find the circumference of painting the circular wall of radius 31.5 yards?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Radius $$(r) = 31.5$$ yards<br>\r\nDiameter $$= 2r = 23 \\\\times 1.5 = 63$$ yards<br>\r\n$$C = \\\\pi d = \\\\frac{22}{7} \\\\times 63 = 462$$ yards\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"231 yards\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 31.5$$ yards<br>\r\nDiameter $$= 2r = 23 \\\\times 1.5 = 63$$ yards<br>\r\n$$C = \\\\pi d = \\\\frac{22}{7} \\\\times 63 = 462$$ yards\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"461 yards\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 31.5$$ yards<br>\r\nDiameter $$= 2r = 23 \\\\times 1.5 = 63$$ yards<br>\r\n$$C = \\\\pi d = \\\\frac{22}{7} \\\\times 63 = 462$$ yards\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"472 yards\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 31.5$$ yards<br>\r\nDiameter $$= 2r = 23 \\\\times 1.5 = 63$$ yards<br>\r\n$$C = \\\\pi d = \\\\frac{22}{7} \\\\times 63 = 462$$ yards\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"462 yards\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Radius $$(r) = 31.5$$ yards<br>\r\nDiameter $$= 2r = 23 \\\\times 1.5 = 63$$ yards<br>\r\n$$C = \\\\pi d = \\\\frac{22}{7} \\\\times 63 = 462$$ yards\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Radius $$(r) = 31.5$$ yards<br>\r\nDiameter $$= 2r = 23 \\\\times 1.5 = 63$$ yards<br>\r\n$$C = \\\\pi d = \\\\frac{22}{7} \\\\times 63 = 462$$ yards\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"What will be the radius of the circle whose circumference is 242 feet?\",\n                    \"text\": \"What will be the radius of the circle whose circumference is 242 feet?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"$$C = 242$$ feet<br>\r\n$$\\\\pi d = 242$$<br>\r\n$$\\\\frac{22d}{7} = 242$$<br>\r\n$$d = \\\\frac{242 \\\\times 7}{22} = 77$$ feet<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{77}{2} = 38.5$$ feet\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"42 feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$C = 242$$ feet<br>\r\n$$\\\\pi d = 242$$<br>\r\n$$\\\\frac{22d}{7} = 242$$<br>\r\n$$d = \\\\frac{242 \\\\times 7}{22} = 77$$ feet<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{77}{2} = 38.5$$ feet\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"63 feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$C = 242$$ feet<br>\r\n$$\\\\pi d = 242$$<br>\r\n$$\\\\frac{22d}{7} = 242$$<br>\r\n$$d = \\\\frac{242 \\\\times 7}{22} = 77$$ feet<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{77}{2} = 38.5$$ feet\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"77 feet\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$C = 242$$ feet<br>\r\n$$\\\\pi d = 242$$<br>\r\n$$\\\\frac{22d}{7} = 242$$<br>\r\n$$d = \\\\frac{242 \\\\times 7}{22} = 77$$ feet<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{77}{2} = 38.5$$ feet\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 3,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"38.5 feet\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"$$C = 242$$ feet<br>\r\n$$\\\\pi d = 242$$<br>\r\n$$\\\\frac{22d}{7} = 242$$<br>\r\n$$d = \\\\frac{242 \\\\times 7}{22} = 77$$ feet<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{77}{2} = 38.5$$ feet\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"$$C = 242$$ feet<br>\r\n$$\\\\pi d = 242$$<br>\r\n$$\\\\frac{22d}{7} = 242$$<br>\r\n$$d = \\\\frac{242 \\\\times 7}{22} = 77$$ feet<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{77}{2} = 38.5$$ feet\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"What will be the area of the circle whose circumference is 44 square inches?\",\n                    \"text\": \"What will be the area of the circle whose circumference is 44 square inches?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"$$C = 44$$ square inches<br>\r\n$$d = 44$$<br>\r\n$$\\\\frac{22d}{7} = 44$$<br>\r\n$$d = \\\\frac{44 \\\\times 7}{22} = 14$$ inches<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{14}{2} = 7$$ inches<br>\r\nArea $$= \\\\pi r^2 = \\\\frac{22}{7}\\\\times7\\\\times7 = 154$$ square inches\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"77 square inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$C = 44$$ square inches<br>\r\n$$d = 44$$<br>\r\n$$\\\\frac{22d}{7} = 44$$<br>\r\n$$d = \\\\frac{44 \\\\times 7}{22} = 14$$ inches<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{14}{2} = 7$$ inches<br>\r\nArea $$= \\\\pi r^2 = \\\\frac{22}{7}\\\\times7\\\\times7 = 154$$ square inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"308 square inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$C = 44$$ square inches<br>\r\n$$d = 44$$<br>\r\n$$\\\\frac{22d}{7} = 44$$<br>\r\n$$d = \\\\frac{44 \\\\times 7}{22} = 14$$ inches<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{14}{2} = 7$$ inches<br>\r\nArea $$= \\\\pi r^2 = \\\\frac{22}{7}\\\\times7\\\\times7 = 154$$ square inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"38.5 square inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$C = 44$$ square inches<br>\r\n$$d = 44$$<br>\r\n$$\\\\frac{22d}{7} = 44$$<br>\r\n$$d = \\\\frac{44 \\\\times 7}{22} = 14$$ inches<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{14}{2} = 7$$ inches<br>\r\nArea $$= \\\\pi r^2 = \\\\frac{22}{7}\\\\times7\\\\times7 = 154$$ square inches\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"154 square inches\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"$$C = 44$$ square inches<br>\r\n$$d = 44$$<br>\r\n$$\\\\frac{22d}{7} = 44$$<br>\r\n$$d = \\\\frac{44 \\\\times 7}{22} = 14$$ inches<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{14}{2} = 7$$ inches<br>\r\nArea $$= \\\\pi r^2 = \\\\frac{22}{7}\\\\times7\\\\times7 = 154$$ square inches\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"$$C = 44$$ square inches<br>\r\n$$d = 44$$<br>\r\n$$\\\\frac{22d}{7} = 44$$<br>\r\n$$d = \\\\frac{44 \\\\times 7}{22} = 14$$ inches<br>\r\n$$r = \\\\frac{d}{2} = \\\\frac{14}{2} = 7$$ inches<br>\r\nArea $$= \\\\pi r^2 = \\\\frac{22}{7}\\\\times7\\\\times7 = 154$$ square inches\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"Find the circumference of the circle whose diameter is 8.4 yards?\",\n                    \"text\": \"Find the circumference of the circle whose diameter is 8.4 yards?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"$$d = 8.4$$ yards<br>\r\nCircumference $$= C = \\\\pi d = \\\\frac{22}{7}\\\\times8.4 = 26.4$$ yards\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"27 yards\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$d = 8.4$$ yards<br>\r\nCircumference $$= C = \\\\pi d = \\\\frac{22}{7}\\\\times8.4 = 26.4$$ yards\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"25.6 yards\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$d = 8.4$$ yards<br>\r\nCircumference $$= C = \\\\pi d = \\\\frac{22}{7}\\\\times8.4 = 26.4$$ yards\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"36.2 yards\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$d = 8.4$$ yards<br>\r\nCircumference $$= C = \\\\pi d = \\\\frac{22}{7}\\\\times8.4 = 26.4$$ yards\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"26.4 yards\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"$$d = 8.4$$ yards<br>\r\nCircumference $$= C = \\\\pi d = \\\\frac{22}{7}\\\\times8.4 = 26.4$$ yards\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"$$d = 8.4$$ yards<br>\r\nCircumference $$= C = \\\\pi d = \\\\frac{22}{7}\\\\times8.4 = 26.4$$ yards\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"If the diameter is doubled, then the circumference will ____.\",\n                    \"text\": \"If the diameter is doubled, then the circumference will ____.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Let the new diameter be $$2d$$.<br>\r\nNew Circumference $$= \\\\pi \\\\times 2d = 2d$$.\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"become half\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Let the new diameter be $$2d$$.<br>\r\nNew Circumference $$= \\\\pi \\\\times 2d = 2d$$.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"stay the same\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Let the new diameter be $$2d$$.<br>\r\nNew Circumference $$= \\\\pi \\\\times 2d = 2d$$.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"triple\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Let the new diameter be $$2d$$.<br>\r\nNew Circumference $$= \\\\pi \\\\times 2d = 2d$$.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 3,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"double\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Let the new diameter be $$2d$$.<br>\r\nNew Circumference $$= \\\\pi \\\\times 2d = 2d$$.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Let the new diameter be $$2d$$.<br>\r\nNew Circumference $$= \\\\pi \\\\times 2d = 2d$$.\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"Find diameter in terms of Pi using circumference. 6 inch circumference to diameter $$=$$ ?\",\n                    \"text\": \"Find diameter in terms of Pi using circumference. 6 inch circumference to diameter $$=$$ ?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Diameter $$(d) = C \\\\pi$$<br>\r\nDiameter $$(d) = 6 \\\\pi$$ \"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$6 \\\\pi$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter $$(d) = C \\\\pi$$<br>\r\nDiameter $$(d) = 6 \\\\pi$$ \"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\frac{\\\\pi}{6}$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter $$(d) = C \\\\pi$$<br>\r\nDiameter $$(d) = 6 \\\\pi$$ \"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$3 \\\\pi$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Diameter $$(d) = C \\\\pi$$<br>\r\nDiameter $$(d) = 6 \\\\pi$$ \"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$\\\\frac{6}{\\\\pi}$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Diameter $$(d) = C \\\\pi$$<br>\r\nDiameter $$(d) = 6 \\\\pi$$ \"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Diameter $$(d) = C \\\\pi$$<br>\r\nDiameter $$(d) = 6 \\\\pi$$ \"\n                      }\n                    } \n\n                    }]}<\/script><\/p>\n\n\n\n<h2 class=\"wp-block-heading eplus-wrapper\" id=\"9-frequently-asked-questions-on-circumference-to-diameter\">Frequently Asked Questions on Circumference to Diameter<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-a1037315-4ed1-4617-9acb-131f331f4f5d\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-a1037315-4ed1-4617-9acb-131f331f4f5d\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a1037315-4ed1-4617-9acb-131f331f4f5d\"><strong>Is the diameter half of the circumference of a circle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-a1037315-4ed1-4617-9acb-131f331f4f5d\">\n\n<p class=\"eplus-wrapper\">No, the diameter is not half of a circle\u2019s circumference. The diameter is twice the radius of a circle.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-a1037315-4ed1-4617-9acb-131f331f4f5d\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a1037315-4ed1-4617-9acb-131f331f4f5d\"><strong>How many diameters make a circumference?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-a1037315-4ed1-4617-9acb-131f331f4f5d\">\n\n<p class=\"eplus-wrapper\">The circumference of a circle is equal to pi $(\\pi = 3.14159\u2026)$ times the diameter.<\/p>\n\n\n\n<p class=\"eplus-wrapper\">Circumference is said to be about three times (little more than 3 times) the diameter of a circle.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-a1037315-4ed1-4617-9acb-131f331f4f5d\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a1037315-4ed1-4617-9acb-131f331f4f5d\"><strong>How does the diameter affect the circumference of the circle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-a1037315-4ed1-4617-9acb-131f331f4f5d\">\n\n<p class=\"eplus-wrapper\">There is a direct relation between the diameter of a circle and the circumference of that same circle. As the diameter increases, the circumference of the circle also increases. As the diameter decreases, the circumference of the circle also decreases.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-3-a1037315-4ed1-4617-9acb-131f331f4f5d\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a1037315-4ed1-4617-9acb-131f331f4f5d\"><strong>Can the circumference and diameter of a circle be the same?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-3-a1037315-4ed1-4617-9acb-131f331f4f5d\">\n\n<p class=\"eplus-wrapper\">The circumference and diameter can never be the same no matter what the diameter of the circle is.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-4-a1037315-4ed1-4617-9acb-131f331f4f5d\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a1037315-4ed1-4617-9acb-131f331f4f5d\"><strong>Which is longer\u2014circumference or diameter?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-4-a1037315-4ed1-4617-9acb-131f331f4f5d\">\n\n<p class=\"eplus-wrapper\">The diameter of a circle is always smaller than its circumference.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-5-a1037315-4ed1-4617-9acb-131f331f4f5d\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-a1037315-4ed1-4617-9acb-131f331f4f5d\"><strong>Is the ratio of circumference to the diameter of a circle always constant?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-5-a1037315-4ed1-4617-9acb-131f331f4f5d\">\n\n<p class=\"eplus-wrapper\">Yes, it is given by pi ().<\/p>\n\n<\/div><\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>What Is the Circumference to Diameter Calculator? The circumference to diameter calculator is used to find the value of the diameter of a circle for a given value of circumference. To use the calculator, simply enter the measurement of the circumference and click on \u201cCalculate\u201d to get the result. What is the circumference of a &#8230; <a title=\"Circumference to Diameter: Conversion, Formula, Meaning, Example\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-to-diameter\" aria-label=\"More on Circumference to Diameter: Conversion, Formula, Meaning, Example\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-28365","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/28365","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=28365"}],"version-history":[{"count":16,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/28365\/revisions"}],"predecessor-version":[{"id":39866,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/28365\/revisions\/39866"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=28365"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=28365"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=28365"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}