{"id":31625,"date":"2023-07-07T17:51:37","date_gmt":"2023-07-07T17:51:37","guid":{"rendered":"https:\/\/www.splashlearn.com\/math-vocabulary\/?page_id=31625"},"modified":"2023-07-09T17:05:33","modified_gmt":"2023-07-09T17:05:33","slug":"perimeter-of-a-semicircle-definition-formula-examples-facts","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle","title":{"rendered":"Perimeter of a Semicircle &#8211; Definition, Formula, Examples, Facts"},"content":{"rendered":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-ac778db9-dd3b-4c37-b3a8-f5f55ba9b358\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle#0-what-is-the-perimeter-of-a-semicircle>What Is the Perimeter of a Semicircle?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle#1-perimeter-of-a-semicircle-formula>Perimeter of a Semicircle Formula<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle#2-how-to-find-the-perimeter-of-a-semicircle>How to Find the Perimeter of a Semicircle<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle#6-solved-examples-on-perimeter-of-a-semicircle>Solved Examples on Perimeter of a Semicircle<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle#7-practice-problems-on-perimeter-of-a-semicircle>Practice Problems on Perimeter of a Semicircle<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle#8-frequently-asked-questions-about-the-perimeter-of-a-semicircle>Frequently Asked Questions about the Perimeter of a Semicircle<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"wp-block-heading\" id=\"0-what-is-the-perimeter-of-a-semicircle\">What Is the Perimeter of a Semicircle?<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of a <a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/half-circle\">semicircle<\/a> is the total length of its boundary, which is composed of half of the circumference of the circle and the length of the diameter.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of a semicircle $= \\pi r + 2r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>What is a semicircle?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">When a circle is divided into two equal halves by the diameter, each half is called a semicircle. A semicircle is simply a half circle.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"309\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/semicircle-perimeter.png\" alt=\"Semicircle is half of a circle\" class=\"wp-image-31657\" title=\"Semicircle is half of a circle\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/semicircle-perimeter.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/semicircle-perimeter-300x150.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>What is the perimeter?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The <a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/perimeter\">perimeter<\/a> describes the total length of the boundary of a 2D figure. The perimeter of a <a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/circle\">circle<\/a> is known as its circumference.<\/p>\n\n\n\n<div id=\"recommended-games-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Games<\/h4><div class=\"recommended-games-container-slides\"><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/determine-the-perimeter\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_peri_with_missing_side_2_pt.png\" alt=\"Determine the Perimeter Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Determine the Perimeter Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/determine-the-perimeter-of-regular-shapes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_peri_with_missing_side_1_pt.png\" alt=\"Determine the Perimeter of Regular Shapes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Determine the Perimeter of Regular Shapes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-perimeter-of-irregular-shapes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_monsters_in_city_6_gm.png\" alt=\"Find Perimeter of Irregular Shapes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Perimeter of Irregular Shapes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-perimeter-of-regular-shapes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_monsters_in_city_7_gm.png\" alt=\"Find Perimeter of Regular Shapes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Perimeter of Regular Shapes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-perimeter-using-side-lengths\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_monsters_in_city_5_gm.png\" alt=\"Find Perimeter using side lengths Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Perimeter using side lengths Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-perimeter-of-irregular-shapes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_peri_irregular_pt.png\" alt=\"Find the Perimeter of Irregular Shapes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Perimeter of Irregular Shapes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-perimeter-of-polygons\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_peri_rectangle_1_pt.png\" alt=\"FInd the Perimeter of Polygons Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">FInd the Perimeter of Polygons Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-perimeter-of-regular-shapes\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_peri_regular_pt.png\" alt=\"Find the Perimeter of Regular Shapes Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Perimeter of Regular Shapes Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-perimeter-of-the-quadrilaterals\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_peri_rectangle_3_pt.png\" alt=\"Find the Perimeter of the Quadrilaterals Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Perimeter of the Quadrilaterals Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-the-perimeter-of-the-shapes-using-grids\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_peri_unit_length_pt.png\" alt=\"Find the Perimeter of the Shapes Using Grids Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find the Perimeter of the Shapes Using Grids Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/games\">More Games<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-games-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".game-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading\" id=\"1-perimeter-of-a-semicircle-formula\">Perimeter of a Semicircle Formula<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of a semicircle $=$ half of the circumference of the circle $+$ diameter\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of a semicircle $= \\pi r + d$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of a semicircle $= \\pi r + 2r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">where \u201cr\u201d is the radius of the circle.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"317\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/perimeter-of-a-semicircle.png\" alt=\"Semicircle\" class=\"wp-image-31659\" title=\"Semicircle\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/perimeter-of-a-semicircle.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/perimeter-of-a-semicircle-300x153.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"2-how-to-find-the-perimeter-of-a-semicircle\">How to Find the Perimeter of a Semicircle<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Let\u2019s understand how to find the perimeter of a half circle.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 1:<\/strong> Find the half the perimeter (circumference of the circle).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 2:<\/strong> Find the length of the diameter.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 3: <\/strong>Add the values obtained in step 1 and step 2.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Step 4: <\/strong>Give the appropriate unit based on the unit of the radius.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"3-perimeter-of-a-semicircle-is-not-half-the-perimeter-of-the-circle\">Perimeter of a Semicircle Is Not Half the Perimeter of the Circle<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Semicircle is half of a circle, but the perimeter of a semicircle is not half of the perimeter of the circle.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Half the perimeter of a circle only represents the curved part of the semicircle.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of a circle $= 2\\pi r$.\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Half the perimeter of the circle $= \\frac{1}{2} \\times 2\\pi r = \\pi r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The semicircle also has diameter as part of its boundary. We need to add the length of the diameter to get the total perimeter of the semicircle.<br><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Length of the diameter $= d = 2r$\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 d is the diameter, r is the radius<\/p>\n\n\n<div class=\"ub-styled-box ub-notification-box\" id=\"ub-styled-box-e2acf285-4ae4-4291-826e-1657d3784ba3\">\n\n\n<ul class=\"wp-block-list\">\n<li>Perimeter of the semicircle $= \\pi r + d$\u00a0<\/li>\n\n\n\n<li>Perimeter of the semicircle $= \\pi r + 2r$<\/li>\n\n\n\n<li>Perimeter of the semicircle $= r (\\pi + 2)$<\/li>\n<\/ul>\n\n\n<\/div>\n\n\n<p class=\"wp-block-paragraph\">Let\u2019s visualize this to get a better idea!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"334\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/understanding-perimeter-of-semicircle-formula.png\" alt=\"Circumference of a semicircle formula visual\" class=\"wp-image-31660\" title=\"Circumference of a semicircle formula visual\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/understanding-perimeter-of-semicircle-formula.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/understanding-perimeter-of-semicircle-formula-300x162.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"4-finding-the-perimeter-of-a-semicircle-when-area-is-given\">Finding the Perimeter of a Semicircle When Area Is Given<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Area of a circle $= \\pi r^{2}$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Semicircle is half the circle.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">So, area of semicircle $= \\frac{1}{2} \\times \\pi r^{2}$ \u2026.(1)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Suppose the area of the semicircle is 77 square inches.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">We will find the radius using the formula (1).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">So, $= \\frac{1}{2} \\times \\pi r^{2} = 77$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$\\pi r^{2} = 154$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$\\frac{22}{7} \\times r \\times r = 154$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r = 7$ inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Substitute $r = 7$ in the formula of perimeter of a semicircle.\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In this case, we get&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of semicircle $= \\pi r + 2r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of semicircle $= \\frac{22}{7} \\times 7 + 2 \\times 7$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of semicircle $= 22 + 14$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of semicircle $= 36$ inches<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"5-facts-about-perimeter-of-a-semicircle\">Facts about Perimeter of a Semicircle<\/h2>\n\n\n\n<div style=\"color:#0369a1;background-color:#e0f2fe\" class=\"wp-block-roelmagdaleno-callout-block has-text-color has-background is-layout-flex wp-container-roelmagdaleno-callout-block-is-layout-4fc3f8e1 wp-block-roelmagdaleno-callout-block-is-layout-flex\"><div>\n<ul class=\"wp-block-list\">\n<li>Area of a circle is half the area of a circle, but that\u2019s not the case with the perimeter (circumference) of a semicircle.<\/li>\n\n\n\n<li>Perimeter of a quarter circle $=$ One fourth of the circumference of the circle $+$ twice the radius.<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"6-solved-examples-on-perimeter-of-a-semicircle\">Solved Examples on Perimeter of a Semicircle<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>1. Find the perimeter of the given semicircle.&nbsp;&nbsp;<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"179\" height=\"112\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/07\/semicircle-example.png\" alt=\"Semicircle with radius 0.7 in\" class=\"wp-image-31661\" title=\"Semicircle with radius 0.7 in\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Radius $(r) = 0.7$ inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= \\pi r + 2r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= \\frac{22}{7} \\times 0.7 + 2 \\times 0.7$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= 2.2 + 1.4$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= 3.6$ inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>2. What is the perimeter of a semicircle with diameter 21 inches?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Diameter $= 21$ inches\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Radius $(r) = \\frac{Diameter}{2} = 10.5$ inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= \\pi r + d$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= \\frac{22}{7} \\times 10.5 + 21$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= 33 + 21$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter $= 43$ inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>3. If the perimeter of the semicircle is 7.2 feet, then find the radius of the circle.&nbsp;<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of the semicircle $= 7.2$ feet<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Let the radius of the semicircle be r feet.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r(\\pi + 2) = 7.2$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r(\\frac{22}{7} + 2) = 7.2$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r(\\frac{22 + 14}{7}) = 7.2$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r \\times \\frac{36}{7} = 7.2$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r = \\frac{7.2 \\times 7}{36}$\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r = 1.4$<em> <\/em>feet<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>4. If the perimeter of the semicircle is 28.8 inches, find the diameter of the circle.<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Perimeter of the semicircle $= 28.8$ inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Let the radius of the semicircle be r inches and diameter be d inches.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r (\\pi + 2) = 28.8$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r (\\frac{22}{7} + 2) = 28.8$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r (\\frac{22 + 14}{7}) = 28.8$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r\\times \\frac{36}{7} = 28.8$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r = \\frac{28.8 \\times 7}{36} = 5.6$<em> <\/em>inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">We know that<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$d = 2r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$\\Rightarrow d = 2 \\times 5.6 = 11.2$ inches<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>5. If the area of the circle is 7546 square units, what is the perimeter of the semicircle?<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Area of the circle $= \\pi r^{2}$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$7546 = \\pi r^{2}$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$7546 = \\frac{22}{7} \\times r \\times r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$\\frac{7546 \\times 7}{22} = r \\times r$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$2401 = r^{2}$<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">$r = 49$ units<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"7-practice-problems-on-perimeter-of-a-semicircle\">Practice Problems on Perimeter of a Semicircle<\/h2>\n\n\n\n<p class=\"wp-block-paragraph\"><div class=\"spq_wrapper\"><h2 style=\"display:none;\">Perimeter of a Semicircle - Definition, Formula, Examples, Facts<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">The perimeter of a half circle is given by<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$r (\\pi + 2)$ units<\/div><div class=\"spq_answer_block\" data-value=\"1\">$2r( \\pi + 2)$ units<\/div><div class=\"spq_answer_block\" data-value=\"2\">$d(\\pi + 4)$ units<\/div><div class=\"spq_answer_block\" data-value=\"3\">$d(\\pi + 1)$ units<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $r (\\pi + 2)$ units<br\/>Perimeter of the semicircle $= \\pi r + 2r = r (\\pi + 2)$ <\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"0\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">If the radius of the circle is 3.5 inches, which of the following is the perimeter of the semicircle?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">18 inches<\/div><div class=\"spq_answer_block\" data-value=\"1\">20 inches<\/div><div class=\"spq_answer_block\" data-value=\"2\">36 inches<\/div><div class=\"spq_answer_block\" data-value=\"3\">14.5 inches<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 18 inches<br\/>Radius $(r) = 3.5$ inches<br>\r\nPerimeter of the semicircle $= \\pi r + 2r$<br>\r\nPerimeter of the semicircle $= (\\frac{22}{7} \\times 3.5) + (2 \\times 3.5)$<br>\r\nPerimeter of the semicircle $= 11 + 7 = 18$ inches<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">What is the perimeter of a semicircle with diameter 10 feet $(\\pi = 3.14)$?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">41.4 inches<\/div><div class=\"spq_answer_block\" data-value=\"1\">51.4 inches<\/div><div class=\"spq_answer_block\" data-value=\"2\">55.4 inches<\/div><div class=\"spq_answer_block\" data-value=\"3\">63.8 inches<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 51.4 inches<br\/>Radius $(r) = 3.5$ inches<br>\r\nPerimeter of the semicircle $= \\pi r + 2r$<br>\r\nPerimeter of the semicircle $= 3 \\times .14 \\times 10 + 2 \\times 10$<br>\r\nPerimeter of the semicircle $=31.4 + 20 = 51.4$ inches<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"3\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">4<\/span><h3 class=\"sqp_question_text\">If the perimeter of the semicircle is 10.8 feet, find the radius of the semicircle.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">5.6 inches<\/div><div class=\"spq_answer_block\" data-value=\"1\">4.2 inches<\/div><div class=\"spq_answer_block\" data-value=\"2\">3.7 inches<\/div><div class=\"spq_answer_block\" data-value=\"3\">2.1 inches<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 2.1 inches<br\/>Perimeter of the semicircle $= 10.8$ inches<br>\r\nLet the radius of the semicircle be r inches.<br>\r\n$r ( \\pi + 2) = 10.8$<br>\r\n$r (\\frac{22}{7} + 2) = 10.8$<br>\r\n$r ( \\frac{22 + 14}{7}) = 10.8$<br>\r\n$r \\times \\frac{36}{7} = 10.8$<br>\r\n$r = \\frac{10.8 \\times  7}{36} = 2.1$ inches<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">5<\/span><h3 class=\"sqp_question_text\">The perimeter of the semicircle with radius 1 unit is _____.<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$\\pi$ units<\/div><div class=\"spq_answer_block\" data-value=\"1\">$2(\\pi + 2)$ units<\/div><div class=\"spq_answer_block\" data-value=\"2\">$(\\pi + 2)$ units<\/div><div class=\"spq_answer_block\" data-value=\"3\">$(\\pi + 4)$ units<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $(\\pi + 2)$ units<br\/>Perimeter of the semicircle $= r(\\pi + 2)$<br>\r\nIf $r = 1$, the perimeter $= (\\pi + 2)$ unit<\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  \"beginner\",\n        \"assesses\" : \"Attend this quiz & Test your knowledge.\",\n        \"educationalAlignment\": [\n              {\n                \"@type\": \"AlignmentObject\",\n                \"alignmentType\": \"educationalSubject\",\n                \"targetName\": \"Math\"\n              }] ,\n        \"name\": \"Perimeter of a Semicircle - Definition, Formula, Examples, Facts\",        \n        \"about\": {\n                \"@type\": \"Thing\",\n                \"name\": \"Perimeter of a Semicircle\"\n        },  \n        \"hasPart\": [{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    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{\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$d(\\\\pi + 4)$$ units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= \\\\pi r + 2r = r (\\\\pi + 2)$$ \"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$d(\\\\pi + 1)$$ units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= \\\\pi r + 2r = r (\\\\pi + 2)$$ \"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$r (\\\\pi + 2)$$ units\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Perimeter of the semicircle $$= \\\\pi r + 2r = r (\\\\pi + 2)$$ \"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Perimeter of the semicircle $$= \\\\pi r + 2r = r (\\\\pi + 2)$$ \"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    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              \"text\": \"20 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= (\\\\frac{22}{7} \\\\times 3.5) + (2 \\\\times 3.5)$$<br>\r\nPerimeter of the semicircle $$= 11 + 7 = 18$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"36 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= (\\\\frac{22}{7} \\\\times 3.5) + (2 \\\\times 3.5)$$<br>\r\nPerimeter of the semicircle $$= 11 + 7 = 18$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"14.5 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= (\\\\frac{22}{7} \\\\times 3.5) + (2 \\\\times 3.5)$$<br>\r\nPerimeter of the semicircle $$= 11 + 7 = 18$$ inches\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 0,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"18 inches\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= (\\\\frac{22}{7} \\\\times 3.5) + (2 \\\\times 3.5)$$<br>\r\nPerimeter of the semicircle $$= 11 + 7 = 18$$ inches\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= (\\\\frac{22}{7} \\\\times 3.5) + (2 \\\\times 3.5)$$<br>\r\nPerimeter of the semicircle $$= 11 + 7 = 18$$ inches\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"What is the perimeter of a semicircle with diameter 10 feet $$(\\\\pi = 3.14)$$?\",\n                    \"text\": \"What is the perimeter of a semicircle with diameter 10 feet $$(\\\\pi = 3.14)$$?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= 3 \\\\times .14 \\\\times 10 + 2 \\\\times 10$$<br>\r\nPerimeter of the semicircle $$=31.4 + 20 = 51.4$$ inches\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"41.4 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= 3 \\\\times .14 \\\\times 10 + 2 \\\\times 10$$<br>\r\nPerimeter of the semicircle $$=31.4 + 20 = 51.4$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"55.4 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= 3 \\\\times .14 \\\\times 10 + 2 \\\\times 10$$<br>\r\nPerimeter of the semicircle $$=31.4 + 20 = 51.4$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"63.8 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= 3 \\\\times .14 \\\\times 10 + 2 \\\\times 10$$<br>\r\nPerimeter of the semicircle $$=31.4 + 20 = 51.4$$ inches\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"51.4 inches\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= 3 \\\\times .14 \\\\times 10 + 2 \\\\times 10$$<br>\r\nPerimeter of the semicircle $$=31.4 + 20 = 51.4$$ inches\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Radius $$(r) = 3.5$$ inches<br>\r\nPerimeter of the semicircle $$= \\\\pi r + 2r$$<br>\r\nPerimeter of the semicircle $$= 3 \\\\times .14 \\\\times 10 + 2 \\\\times 10$$<br>\r\nPerimeter of the semicircle $$=31.4 + 20 = 51.4$$ inches\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"If the perimeter of the semicircle is 10.8 feet, find the radius of the semicircle.\",\n                    \"text\": \"If the perimeter of the semicircle is 10.8 feet, find the radius of the semicircle.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Perimeter of the semicircle $$= 10.8$$ inches<br>\r\nLet the radius of the semicircle be r inches.<br>\r\n$$r ( \\\\pi + 2) = 10.8$$<br>\r\n$$r (\\\\frac{22}{7} + 2) = 10.8$$<br>\r\n$$r ( \\\\frac{22 + 14}{7}) = 10.8$$<br>\r\n$$r \\\\times \\\\frac{36}{7} = 10.8$$<br>\r\n$$r = \\\\frac{10.8 \\\\times  7}{36} = 2.1$$ inches\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"5.6 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= 10.8$$ inches<br>\r\nLet the radius of the semicircle be r inches.<br>\r\n$$r ( \\\\pi + 2) = 10.8$$<br>\r\n$$r (\\\\frac{22}{7} + 2) = 10.8$$<br>\r\n$$r ( \\\\frac{22 + 14}{7}) = 10.8$$<br>\r\n$$r \\\\times \\\\frac{36}{7} = 10.8$$<br>\r\n$$r = \\\\frac{10.8 \\\\times  7}{36} = 2.1$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"4.2 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= 10.8$$ inches<br>\r\nLet the radius of the semicircle be r inches.<br>\r\n$$r ( \\\\pi + 2) = 10.8$$<br>\r\n$$r (\\\\frac{22}{7} + 2) = 10.8$$<br>\r\n$$r ( \\\\frac{22 + 14}{7}) = 10.8$$<br>\r\n$$r \\\\times \\\\frac{36}{7} = 10.8$$<br>\r\n$$r = \\\\frac{10.8 \\\\times  7}{36} = 2.1$$ inches\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"3.7 inches\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= 10.8$$ inches<br>\r\nLet the radius of the semicircle be r inches.<br>\r\n$$r ( \\\\pi + 2) = 10.8$$<br>\r\n$$r (\\\\frac{22}{7} + 2) = 10.8$$<br>\r\n$$r ( \\\\frac{22 + 14}{7}) = 10.8$$<br>\r\n$$r \\\\times \\\\frac{36}{7} = 10.8$$<br>\r\n$$r = \\\\frac{10.8 \\\\times  7}{36} = 2.1$$ inches\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 3,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"2.1 inches\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Perimeter of the semicircle $$= 10.8$$ inches<br>\r\nLet the radius of the semicircle be r inches.<br>\r\n$$r ( \\\\pi + 2) = 10.8$$<br>\r\n$$r (\\\\frac{22}{7} + 2) = 10.8$$<br>\r\n$$r ( \\\\frac{22 + 14}{7}) = 10.8$$<br>\r\n$$r \\\\times \\\\frac{36}{7} = 10.8$$<br>\r\n$$r = \\\\frac{10.8 \\\\times  7}{36} = 2.1$$ inches\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Perimeter of the semicircle $$= 10.8$$ inches<br>\r\nLet the radius of the semicircle be r inches.<br>\r\n$$r ( \\\\pi + 2) = 10.8$$<br>\r\n$$r (\\\\frac{22}{7} + 2) = 10.8$$<br>\r\n$$r ( \\\\frac{22 + 14}{7}) = 10.8$$<br>\r\n$$r \\\\times \\\\frac{36}{7} = 10.8$$<br>\r\n$$r = \\\\frac{10.8 \\\\times  7}{36} = 2.1$$ inches\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"The perimeter of the semicircle with radius 1 unit is _____.\",\n                    \"text\": \"The perimeter of the semicircle with radius 1 unit is _____.\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"Perimeter of the semicircle $$= r(\\\\pi + 2)$$<br>\r\nIf $$r = 1$$, the perimeter $$= (\\\\pi + 2)$$ unit\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\pi$$ units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= r(\\\\pi + 2)$$<br>\r\nIf $$r = 1$$, the perimeter $$= (\\\\pi + 2)$$ unit\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$2(\\\\pi + 2)$$ units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= r(\\\\pi + 2)$$<br>\r\nIf $$r = 1$$, the perimeter $$= (\\\\pi + 2)$$ unit\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$(\\\\pi + 4)$$ units\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"Perimeter of the semicircle $$= r(\\\\pi + 2)$$<br>\r\nIf $$r = 1$$, the perimeter $$= (\\\\pi + 2)$$ unit\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$(\\\\pi + 2)$$ units\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"Perimeter of the semicircle $$= r(\\\\pi + 2)$$<br>\r\nIf $$r = 1$$, the perimeter $$= (\\\\pi + 2)$$ unit\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"Perimeter of the semicircle $$= r(\\\\pi + 2)$$<br>\r\nIf $$r = 1$$, the perimeter $$= (\\\\pi + 2)$$ unit\"\n                      }\n                    } \n\n                    }]}<\/script><\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"8-frequently-asked-questions-about-the-perimeter-of-a-semicircle\">Frequently Asked Questions about the Perimeter of a Semicircle<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-0d6ca2c7-de42-47e8-9767-29219484a913\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-0d6ca2c7-de42-47e8-9767-29219484a913\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-0d6ca2c7-de42-47e8-9767-29219484a913\"><strong>What is the difference between area and perimeter?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-0d6ca2c7-de42-47e8-9767-29219484a913\">\n\n<p class=\"wp-block-paragraph\">Perimeter for a <a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/geometry\/2-dimensional\">2-dimensional shape<\/a> is the total distance around the respective shape whereas the area for a 2-dimensional shape is the region enclosed within the perimeter of the given shape.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-0d6ca2c7-de42-47e8-9767-29219484a913\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-0d6ca2c7-de42-47e8-9767-29219484a913\"><strong>What is the formula for the area of the circle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-0d6ca2c7-de42-47e8-9767-29219484a913\">\n\n<p class=\"wp-block-paragraph\">Area of the circle with radius r units $=\\pi r^{2}$ square units<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-0d6ca2c7-de42-47e8-9767-29219484a913\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-0d6ca2c7-de42-47e8-9767-29219484a913\"><strong>Is the angle in a semicircle equal to <\/strong>$180^{\\circ}$<strong>?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-0d6ca2c7-de42-47e8-9767-29219484a913\">\n\n<p class=\"wp-block-paragraph\">Yes. The angle in a semicircle is $180^{\\circ}$ as the semicircle is half a circle and the angle in a circle is $360^{\\circ}$.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-3-0d6ca2c7-de42-47e8-9767-29219484a913\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-0d6ca2c7-de42-47e8-9767-29219484a913\"><strong>What is half the semicircle called?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-3-0d6ca2c7-de42-47e8-9767-29219484a913\">\n\n<p class=\"wp-block-paragraph\">Half the semicircle is known as a quadrant or the quarter of a circle.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-4-0d6ca2c7-de42-47e8-9767-29219484a913\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-0d6ca2c7-de42-47e8-9767-29219484a913\"><strong>Is a semicircle a polygon?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-4-0d6ca2c7-de42-47e8-9767-29219484a913\">\n\n<p class=\"wp-block-paragraph\">No. A semicircle is made up of one curved and one straight line segment, but a polygon is made of only straight line segments.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-5-0d6ca2c7-de42-47e8-9767-29219484a913\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-0d6ca2c7-de42-47e8-9767-29219484a913\"><strong>How do you find the perimeter of a semicircle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-5-0d6ca2c7-de42-47e8-9767-29219484a913\">\n\n<p class=\"wp-block-paragraph\">Perimeter of a semicircle $= \\pi r + 2r$, where r is the radius of the circle.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-6-0d6ca2c7-de42-47e8-9767-29219484a913\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-0d6ca2c7-de42-47e8-9767-29219484a913\"><strong>Is the circumference of a semicircle half the circumference of the circle?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-6-0d6ca2c7-de42-47e8-9767-29219484a913\">\n\n<p class=\"wp-block-paragraph\">No. The circumference of a semicircle is not half the <a href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/circumference-of-a-circle\">circumference of the circle<\/a>.<\/p>\n\n<\/div><\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>What Is the Perimeter of a Semicircle? Perimeter of a semicircle is the total length of its boundary, which is composed of half of the circumference of the circle and the length of the diameter. Perimeter of a semicircle $= \\pi r + 2r$ What is a semicircle? When a circle is divided into two &#8230; <a title=\"Perimeter of a Semicircle &#8211; Definition, Formula, Examples, Facts\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/perimeter-of-a-semicircle\" aria-label=\"More on Perimeter of a Semicircle &#8211; Definition, Formula, Examples, Facts\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-31625","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/31625","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=31625"}],"version-history":[{"count":11,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/31625\/revisions"}],"predecessor-version":[{"id":31676,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/31625\/revisions\/31676"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=31625"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=31625"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=31625"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}