{"id":33193,"date":"2023-08-18T18:09:03","date_gmt":"2023-08-18T18:09:03","guid":{"rendered":"https:\/\/www.splashlearn.com\/math-vocabulary\/?page_id=33193"},"modified":"2023-08-19T18:39:24","modified_gmt":"2023-08-19T18:39:24","slug":"average-speed-formula-definition-examples-facts-faqs","status":"publish","type":"post","link":"https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula","title":{"rendered":"Average Speed Formula: Definition, Examples, Facts,\u00a0 FAQs"},"content":{"rendered":"<div class=\"aioseo-breadcrumbs\"><span class=\"aioseo-breadcrumb\">\n\tMath-Vocabulary\n<\/span><\/div>\n\n<div class=\"ub_table-of-contents\" data-showtext=\"show\" data-hidetext=\"hide\" data-scrolltype=\"auto\" id=\"ub_table-of-contents-72fb4363-d91c-4520-afa4-3ad3a68771db\" data-initiallyhideonmobile=\"false\"\n                    data-initiallyshow=\"true\"><div class=\"ub_table-of-contents-extra-container\"><div class=\"ub_table-of-contents-container ub_table-of-contents-1-column \"><ul><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula#0-what-is-the-average-speed-formula>What Is the Average Speed Formula?<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula#1-average-speed-formula>Average Speed Formula<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula#2-how-to-find-average-speed>How to Find Average Speed<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula#5-solved-examples-on-average-speed-formula>Solved Examples on Average Speed Formula<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula#6-practice-problems-for-average-speed>Practice Problems for Average Speed<\/a><\/li><li><a href=https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula#7-frequently-asked-questions-on-average-speed-formula>Frequently Asked Questions on Average Speed Formula<\/a><\/li><\/ul><\/div><\/div><\/div>\n\n\n<h2 class=\"wp-block-heading\" id=\"0-what-is-the-average-speed-formula\">What Is the Average Speed Formula?<\/h2>\n\n\n\n<p><strong>The average speed formula is given by the total distance traveled divided by the time taken to cover that distance.<\/strong><\/p>\n\n\n\n<p>The formula to find average speed is<\/p>\n\n\n\n<p>Average speed $= \\frac{Total \\;distance}{Time}$<\/p>\n\n\n\n<p>Observe the car in the given image. The distance it covers in the different time intervals is different. The speed of the car is not constant.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"285\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/journey-of-a-car-with-different-speeds.png\" alt=\"Journey of a car with different speeds\" class=\"wp-image-33214\" title=\"Journey of a car with different speeds\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/journey-of-a-car-with-different-speeds.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/journey-of-a-car-with-different-speeds-300x138.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p>When you travel from one place to another by some vehicle, the speed changes from time to time. You do not travel with the same speed throughout the journey. The average speed, as the name itself suggests, gives us the mean value or the average value of the speed at which you traveled.&nbsp;<\/p>\n\n\n\n<p>It is kind of an estimate to understand the speed by which an object finishes its journey. It provides insights into how fast an object is moving over a given distance and time. Calculating average speed allows us to estimate travel times and make comparisons between different routes or means of transportation.<\/p>\n\n\n\n<div id=\"recommended-games-container-id\" class=\"recommended-games-container\"><h4 class=\"recommended-games-container-headline\">Recommended Games<\/h4><div class=\"recommended-games-container-slides\"><div class=\"game-card-container-outer\">\r\n\t<a href=\"https:\/\/www.splashlearn.com\/s\/math-games\/find-volume-using-the-formula\" data-vars-ga-category=\"splashlearn_vocab\" data-vars-ga-action=\"games_recommendations\" data-vars-ga-label=\"post_widget\">\r\n\t\t<div class=\"game-card-container-inner-block\">\r\n\t\t\t<img decoding=\"async\" class=\"game-card-container-inner-img\" src=\"https:\/\/cdn.splashmath.com\/curriculum_uploads\/images\/playables\/geo_meas_vol_formula_pt.png\" alt=\"Find Volume using the Formula Game\">\r\n\t\t<\/div>\r\n\t\r\n\t\t<div class=\"game-card-container-inner\">\r\n\t\t\t<div class=\"game-card-container-inner-name\">Find Volume using the Formula Game<\/div>\r\n\t\t\t<span class=\"game-card-container-inner-cta\">Play<\/span>\r\n\t\t<\/div>\r\n\t<\/a>\r\n<\/div><\/div><p class=\"recommended-games-container-desc\"><a href=\"https:\/\/www.splashlearn.com\/games\">More Games<\/a><\/p><button class=\"scroll-right-arrow\"><\/button><\/div><script type=\"text\/javascript\">\n        document.addEventListener(\"DOMContentLoaded\", function() {\n            const container = document.querySelector(\"#recommended-games-container-id\");\n            const slidesContainer = container.querySelector(\".recommended-games-container-slides\");\n            const cards = slidesContainer.querySelectorAll(\".game-card-container-outer\");\n            const scrollRightArrow = container.querySelector(\".scroll-right-arrow\");\n\n            function adjustContainerStyles() {\n                const numCards = cards.length;\n\n                if (numCards === 1) {\n                    container.style.maxWidth = \"30%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 2) {\n                    container.style.maxWidth = \"50%\";\n                    container.style.textAlign = \"center\";\n                } else if (numCards === 3) {\n                    container.style.maxWidth = \"75%\";\n                    container.style.textAlign = \"center\";\n                } else {\n                    container.style.maxWidth = \"\";\n                    container.style.textAlign = \"\";\n                }\n            }\n\n            function checkScrollPosition() {\n                const maxScrollLeft = slidesContainer.scrollWidth - slidesContainer.clientWidth;\n                if ((slidesContainer.scrollLeft + 10) >= maxScrollLeft) {\n                    scrollRightArrow.style.display = \"none\"; \/\/ Hide the arrow if fully scrolled\n                } else {\n                    scrollRightArrow.style.display = \"block\"; \/\/ Show the arrow if not fully scrolled\n                }\n            }\n\n            scrollRightArrow.addEventListener(\"click\", function() {\n                const scrollAmount = 300; \/\/ Adjust based on the container's width and your needs\n                slidesContainer.scrollLeft += scrollAmount;\n                setTimeout(checkScrollPosition, 100); \/\/ Delay to allow scroll update\n            });\n\n            adjustContainerStyles();\n            checkScrollPosition();\n            slidesContainer.addEventListener(\"scroll\", checkScrollPosition);\n        });\n    <\/script><h2 class=\"wp-block-heading\" id=\"1-average-speed-formula\">Average Speed Formula<\/h2>\n\n\n\n<p>The average speed formula can be given by&nbsp;<\/p>\n\n\n\n<p>Average Speed $=$ Total distance covered $\\div$ Total time taken<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"292\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/formula-for-average-speed.png\" alt=\"Formula for Average Speed\" class=\"wp-image-33208\" title=\"Formula for Average Speed\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/formula-for-average-speed.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/formula-for-average-speed-300x141.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p><strong>Average speed formula for a round trip<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"620\" height=\"315\" src=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/average-speed-formula-for-the-round-journey.png\" alt=\"Average speed formula for the round journey\" class=\"wp-image-33210\" title=\"Average speed formula for the round journey\" srcset=\"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/average-speed-formula-for-the-round-journey.png 620w, https:\/\/www.splashlearn.com\/math-vocabulary\/wp-content\/uploads\/2023\/08\/average-speed-formula-for-the-round-journey-300x152.png 300w\" sizes=\"auto, (max-width: 620px) 100vw, 620px\" \/><\/figure>\n\n\n\n<p><em>Alt tag: Average speed formula for the round journey<\/em><\/p>\n\n\n\n<p><strong>Derivation:<\/strong><\/p>\n\n\n\n<p>Suppose you travel a distance \u201cd\u201d from A to B with the speed of x miles per hour and the distance from B to A with the speed of y miles per hour. In this case, the same distance is covered (both ways) but with the different speeds. In this case, the average speed is given by<\/p>\n\n\n\n<p>Total distance traveled $= d + d = 2d$<\/p>\n\n\n\n<p>Time taken to go from A to B $= \\frac{Distance}{Speed} = dx$<\/p>\n\n\n\n<p>Time taken to go from B to A $= \\frac{Distance}{Speed} = dy$<\/p>\n\n\n\n<p>Total time taken $= \\frac{d}{x} + \\frac{d}{y} = \\frac{d(x + y)}{xy}$<\/p>\n\n\n\n<p>Average speed $=$ Total distance covered $\u00f7$ Total time taken<\/p>\n\n\n\n<p>Thus, the average speed equation becomes<\/p>\n\n\n\n<p>\u00a0Average speed $= \\frac{2d}{\\frac{d(x + y)}{xy}} = \\frac{2xy}{x + y}$<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"2-how-to-find-average-speed\">How to Find Average Speed<\/h2>\n\n\n\n<p>Let\u2019s understand steps to <strong>calculate average speed of an object<\/strong>. Let&#8217;s examine the procedure in more detail:<\/p>\n\n\n\n<p><strong>Step 1: <\/strong>Calculate the total distance traveled. If the two different speeds of the given journey are given, calculate the two distances separately using the formula: distance = Speed \u00d7 time.<\/p>\n\n\n\n<p><strong>Step 2: <\/strong>Calculate the time taken to travel the total distance.<\/p>\n\n\n\n<p><strong>Step 3:<\/strong> Divide the total distance by total time taken to find the average speed. Assign the unit depending on the units of distance and time. For example, if the distance is given in miles and the time is in hours, the average speed will be measured in miles per hour (written as miles\/hr).<\/p>\n\n\n\n<p><strong>Example 1: Joy travels the distance of 42 miles in 3 hours and 26 miles in 2 hours. Find his average speed.<\/strong><\/p>\n\n\n\n<p>Total distance traveled $= 42 + 26 = 68$ miles<\/p>\n\n\n\n<p>Total time taken $= 3 + 2 = 5$ hours<\/p>\n\n\n\n<p>Average speed $= \\farc{68}{5} = 13.6$ miles\/hr<\/p>\n\n\n\n<p><strong>Example 2: A bus travels the first 3 hours of journey with the speed of 20 miles\/hour and the next 2 hours of the journey with the speed of 25 miles per hour. Find its average speed.<\/strong><\/p>\n\n\n\n<p>Distance $=$ Speed $\\times$ time<\/p>\n\n\n\n<p>The distance traveled in the first 3 hours with the speed of 20 mph $= 20 \\times 3 = 60$ miles<\/p>\n\n\n\n<p>The distance traveled in the next 2 hours with the speed of 25 mph $= 25 \\times 2 = 50$ miles<\/p>\n\n\n\n<p>Total distance traveled $= 60 + 50 = 110$ miles<\/p>\n\n\n\n<p>Total time taken $= 3 + 2 = 5$ hours<\/p>\n\n\n\n<p>Average speed $= \\frac{110}{5} = 22$ miles\/hour<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"3-facts-about-average-speed-formula\">Facts about Average Speed Formula<\/h2>\n\n\n\n<div style=\"color:#0369a1;background-color:#e0f2fe\" class=\"wp-block-roelmagdaleno-callout-block has-text-color has-background is-layout-flex wp-container-roelmagdaleno-callout-block-is-layout-8cf370e7 wp-block-roelmagdaleno-callout-block-is-layout-flex\"><div>\n<ul class=\"wp-block-list\">\n<li>Average speed is a scalar quantity, which can only be represented by magnitude. It has no direction.<\/li>\n\n\n\n<li>Average speed is independent of the direction of travel; it only depends on the total distance and time.<\/li>\n\n\n\n<li>It is essential to differentiate average speed from average velocity. Average velocity is a vector quantity that considers both magnitude and direction.<\/li>\n<\/ul>\n<\/div><\/div>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"4-conclusion\">Conclusion<\/h2>\n\n\n\n<p>The <strong>average speed formula<\/strong> is calculated by dividing the total distance covered by the total time taken. In this article, we explored the concept of average speed, its formulas with different cases, and examples. Let\u2019s solve a few examples and practice problems based on these concepts.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"5-solved-examples-on-average-speed-formula\">Solved Examples on Average Speed Formula<\/h2>\n\n\n\n<p><strong>1.<\/strong> <strong>John walks a distance of 5 miles in 2 hours. Calculate his average speed.<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong>&nbsp;<\/p>\n\n\n\n<p>Using the<strong> average speed formula<\/strong>, we get<\/p>\n\n\n\n<p>Average speed $= \\frac{Total \\;Distance}{Total \\;Time}$<\/p>\n\n\n\n<p>Average speed $= \\frac{5 \\;miles}{2 \\;hours}$<\/p>\n\n\n\n<p>Average Speed $= 2.5$ miles\/hour<\/p>\n\n\n\n<p><strong>2. A car travels at a speed of&nbsp; 24 miles\/hr for 2 hours and then decides to slow down to 18 miles\/hr for the next 2 hours. What is the average speed?<\/strong><\/p>\n\n\n\n<p><strong>Solution:<\/strong><\/p>\n\n\n\n<p>Distance $=$ Speed $\\times$ time<\/p>\n\n\n\n<p>The distance traveled in the first 2 hours with the speed of 24 mph $= 24 \\times 2 = 48$ miles<\/p>\n\n\n\n<p>The distance traveled in the next 2 hours with the speed of 18 mph $= 18 \\times 2 = 36$ miles<\/p>\n\n\n\n<p>Total distance traveled $= 48 + 36 = 84$ miles<\/p>\n\n\n\n<p>Total time taken$ = 2 + 2 = 4$ hours<\/p>\n\n\n\n<p>Average speed $= \\frac{84}{4} = 21$ miles\/hour<\/p>\n\n\n\n<p><strong>3. Walter<\/strong> <strong>drives at a speed of 60 mph from his house to his office every day. He returns from work at the speed of 45 mph. What\u2019s his average speed for the round trip?<\/strong><\/p>\n\n\n\n<p><strong>Solution:&nbsp;<\/strong><\/p>\n\n\n\n<p>Walter travels the same distance (both ways) with different speeds. We will use the average speed formula for the round trip.<\/p>\n\n\n\n<p>$x = 60$                             mph speed with which Walter travels from home to office<\/p>\n\n\n\n<p>$y =  45$                            mph speed with which Walter travels back to home from office<\/p>\n\n\n\n<p>Average speed $= \\frac{2xy}{x + y} = \\frac{2\\times 60 \\times45}{60 + 45} = \\frac{210}{105} = 51.42$ miles\/hour<\/p>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"6-practice-problems-for-average-speed\">Practice Problems for Average Speed<\/h2>\n\n\n\n<div class=\"spq_wrapper\"><h2 style=\"display:none;\">Average Speed Formula: Definition, Examples, Facts,\u00a0 FAQs<\/h2><p style=\"display:none;\">Attend this quiz & Test your knowledge.<\/p><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">1<\/span><h3 class=\"sqp_question_text\">A kid walks a distance of 5 miles in 3 hours. What is the average speed?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">1.27 mi\/h<\/div><div class=\"spq_answer_block\" data-value=\"1\">1.67 mi\/h<\/div><div class=\"spq_answer_block\" data-value=\"2\">1.76 mi\/h<\/div><div class=\"spq_answer_block\" data-value=\"3\">1.87 mi\/h<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 1.67 mi\/h<br\/>To find the average speed, we divide the total distance covered (30 miles) by the total time (2 hours). Therefore, Average Speed $= \\frac{5}{3} = 1.67$ mph.<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"2\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">2<\/span><h3 class=\"sqp_question_text\">A runner completes the first 1.5 hours of a race with the speed of 9 miles per hour and the next 1 hour with the speed of 10 miles per hour. What is the runner's average speed?<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">9.7 mph<\/div><div class=\"spq_answer_block\" data-value=\"1\">8.9 mph<\/div><div class=\"spq_answer_block\" data-value=\"2\">9.4 mph<\/div><div class=\"spq_answer_block\" data-value=\"3\">4.9 mph<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: 9.4 mph<br\/>$D_{1} = 9 \\times 1.5 = 13.5$ miles<br>\r\n$D_{2} = 10 \\times 1 = 10$ miles<br>\r\nTotal distance $= 23.5$ miles<br>\r\nTotal time $= 2.5$ hours<br>\r\nAverage Speed $= \\frac{23.5\\; miles}{2.5\\; hours} = 9.4$ mph<\/span><\/div><\/div><\/div><div class=\"spq_question_wrapper\" data-answer=\"1\"><span class=\"spq_question_header\"><span class=\"sqp_question_number\">3<\/span><h3 class=\"sqp_question_text\">If a car covers distances $D_{1},\\; D_{2}$, and $D_{3}$ for time intervals $T_{1},\\; T{_2}$, and $T_{3}$ respectively, the average speed is<\/h3><\/span><div class=\"spq_answer_block\" data-value=\"0\">$\\frac{T_{1} + T_{2} + T_{3}}{D_{1} + D_{2} + D_{3}}$<\/div><div class=\"spq_answer_block\" data-value=\"1\">$\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$<\/div><div class=\"spq_answer_block\" data-value=\"2\">$\\frac{D_{1} \\times D_{2} \\times D_{3}}{T_{1} + T_{2} + T_{3}}$<\/div><div class=\"spq_answer_block\" data-value=\"3\">$\\frac{T_{1} + T_{2} + T_{3}}{D_{1} + D_{2} + D_{3}}$<\/div><div class=\"sqp_question_hint\"><div class=\"sqp_question_hint__header\"><span class=\"spq_correct\">Correct<\/span><span class=\"spq_incorrect\">Incorrect<\/span><\/div><div class=\"sqp_question_hint__content\"><span>Correct answer is: $\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$<br\/>If a car covers distances $D_{1},\\; D_{2}$, and $D_{3}$ for time intervals $T_{1},\\; T_{2}$, and $T_{3}$ respectively, the average speed is total distance divided by the total time.<br>\r\nAverage speed $= \\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$<\/span><\/div><\/div><\/div><\/div>  <script type=\"application\/ld+json\">{\n        \"@context\": \"https:\/\/schema.org\/\", \n        \"@type\": \"Quiz\", \n        \"typicalAgeRange\": \"3-11\",\n        \"educationalLevel\":  \"beginner\",\n        \"assesses\" : \"Attend this quiz & Test your knowledge.\",\n        \"educationalAlignment\": [\n              {\n                \"@type\": \"AlignmentObject\",\n                \"alignmentType\": \"educationalSubject\",\n                \"targetName\": \"Math\"\n              }] ,\n        \"name\": \"Average Speed Formula: Definition, Examples, Facts,\u00a0 FAQs\",        \n        \"about\": {\n                \"@type\": \"Thing\",\n                \"name\": \"Average Speed Formula\"\n        },  \n        \"hasPart\": [{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"A kid walks a distance of 5 miles in 3 hours. 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Therefore, Average Speed $$= \\\\frac{5}{3} = 1.67$$ mph.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"1.76 mi\/h\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"To find the average speed, we divide the total distance covered (30 miles) by the total time (2 hours). Therefore, Average Speed $$= \\\\frac{5}{3} = 1.67$$ mph.\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"1.87 mi\/h\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"To find the average speed, we divide the total distance covered (30 miles) by the total time (2 hours). Therefore, Average Speed $$= \\\\frac{5}{3} = 1.67$$ mph.\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"1.67 mi\/h\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"To find the average speed, we divide the total distance covered (30 miles) by the total time (2 hours). Therefore, Average Speed $$= \\\\frac{5}{3} = 1.67$$ mph.\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"To find the average speed, we divide the total distance covered (30 miles) by the total time (2 hours). Therefore, Average Speed $$= \\\\frac{5}{3} = 1.67$$ mph.\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"A runner completes the first 1.5 hours of a race with the speed of 9 miles per hour and the next 1 hour with the speed of 10 miles per hour. What is the runner's average speed?\",\n                    \"text\": \"A runner completes the first 1.5 hours of a race with the speed of 9 miles per hour and the next 1 hour with the speed of 10 miles per hour. What is the runner's average speed?\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"$$D_{1} = 9 \\\\times 1.5 = 13.5$$ miles<br>\r\n$$D_{2} = 10 \\\\times 1 = 10$$ miles<br>\r\nTotal distance $$= 23.5$$ miles<br>\r\nTotal time $$= 2.5$$ hours<br>\r\nAverage Speed $$= \\\\frac{23.5\\\\; miles}{2.5\\\\; hours} = 9.4$$ mph\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"9.7 mph\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$D_{1} = 9 \\\\times 1.5 = 13.5$$ miles<br>\r\n$$D_{2} = 10 \\\\times 1 = 10$$ miles<br>\r\nTotal distance $$= 23.5$$ miles<br>\r\nTotal time $$= 2.5$$ hours<br>\r\nAverage Speed $$= \\\\frac{23.5\\\\; miles}{2.5\\\\; hours} = 9.4$$ mph\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 1,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"8.9 mph\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$D_{1} = 9 \\\\times 1.5 = 13.5$$ miles<br>\r\n$$D_{2} = 10 \\\\times 1 = 10$$ miles<br>\r\nTotal distance $$= 23.5$$ miles<br>\r\nTotal time $$= 2.5$$ hours<br>\r\nAverage Speed $$= \\\\frac{23.5\\\\; miles}{2.5\\\\; hours} = 9.4$$ mph\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"4.9 mph\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"$$D_{1} = 9 \\\\times 1.5 = 13.5$$ miles<br>\r\n$$D_{2} = 10 \\\\times 1 = 10$$ miles<br>\r\nTotal distance $$= 23.5$$ miles<br>\r\nTotal time $$= 2.5$$ hours<br>\r\nAverage Speed $$= \\\\frac{23.5\\\\; miles}{2.5\\\\; hours} = 9.4$$ mph\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 2,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"9.4 mph\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"$$D_{1} = 9 \\\\times 1.5 = 13.5$$ miles<br>\r\n$$D_{2} = 10 \\\\times 1 = 10$$ miles<br>\r\nTotal distance $$= 23.5$$ miles<br>\r\nTotal time $$= 2.5$$ hours<br>\r\nAverage Speed $$= \\\\frac{23.5\\\\; miles}{2.5\\\\; hours} = 9.4$$ mph\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"$$D_{1} = 9 \\\\times 1.5 = 13.5$$ miles<br>\r\n$$D_{2} = 10 \\\\times 1 = 10$$ miles<br>\r\nTotal distance $$= 23.5$$ miles<br>\r\nTotal time $$= 2.5$$ hours<br>\r\nAverage Speed $$= \\\\frac{23.5\\\\; miles}{2.5\\\\; hours} = 9.4$$ mph\"\n                      }\n                    } \n\n                    },{\n                    \"@type\": \"Question\",   \n                    \"eduQuestionType\": \"Multiple choice\",\n                    \"learningResourceType\": \"Practice problem\",\n                    \"name\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T{_2}$$, and $$T_{3}$$ respectively, the average speed is\",\n                    \"text\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T{_2}$$, and $$T_{3}$$ respectively, the average speed is\",\n                    \"comment\": {\n                      \"@type\": \"Comment\",\n                      \"text\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T_{2}$$, and $$T_{3}$$ respectively, the average speed is total distance divided by the total time.<br>\r\nAverage speed $$= \\\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$$\"\n                    },\n                    \"encodingFormat\": \"text\/html\",\n                    \"suggestedAnswer\": [ {\n                                \"@type\": \"Answer\",\n                                \"position\": 0,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\frac{T_{1} + T_{2} + T_{3}}{D_{1} + D_{2} + D_{3}}$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T_{2}$$, and $$T_{3}$$ respectively, the average speed is total distance divided by the total time.<br>\r\nAverage speed $$= \\\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 2,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\frac{D_{1} \\\\times D_{2} \\\\times D_{3}}{T_{1} + T_{2} + T_{3}}$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T_{2}$$, and $$T_{3}$$ respectively, the average speed is total distance divided by the total time.<br>\r\nAverage speed $$= \\\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$$\"\n                                    }\n                                }, {\n                                \"@type\": \"Answer\",\n                                \"position\": 3,\n                                \"encodingFormat\": \"text\/html\",\n                                \"text\": \"$$\\\\frac{T_{1} + T_{2} + T_{3}}{D_{1} + D_{2} + D_{3}}$$\",\n                                \"comment\": {\n                                    \"@type\": \"Comment\",\n                                    \"text\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T_{2}$$, and $$T_{3}$$ respectively, the average speed is total distance divided by the total time.<br>\r\nAverage speed $$= \\\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$$\"\n                                    }\n                                }],\n                    \"acceptedAnswer\": {\n                      \"@type\": \"Answer\",\n                      \"position\": 1,\n                      \"encodingFormat\": \"text\/html\",\n                      \"text\": \"$$\\\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$$\",\n                      \"comment\": {\n                          \"@type\": \"Comment\",\n                          \"text\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T_{2}$$, and $$T_{3}$$ respectively, the average speed is total distance divided by the total time.<br>\r\nAverage speed $$= \\\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$$\"\n                        },\n                      \"answerExplanation\": {\n                        \"@type\": \"Comment\",\n                        \"text\": \"If a car covers distances $$D_{1},\\\\; D_{2}$$, and $$D_{3}$$ for time intervals $$T_{1},\\\\; T_{2}$$, and $$T_{3}$$ respectively, the average speed is total distance divided by the total time.<br>\r\nAverage speed $$= \\\\frac{D_{1} + D_{2} + D_{3}}{T_{1} + T_{2} + T_{3}}$$\"\n                      }\n                    } \n\n                    }]}<\/script>\n\n\n\n<h2 class=\"wp-block-heading\" id=\"7-frequently-asked-questions-on-average-speed-formula\">Frequently Asked Questions on Average Speed Formula<\/h2>\n\n\n<div class=\"wp-block-ub-content-toggle\" id=\"ub-content-toggle-d574d3a1-56ec-457d-ab44-f730a12bd438\" data-mobilecollapse=\"true\" data-desktopcollapse=\"true\">\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-0-d574d3a1-56ec-457d-ab44-f730a12bd438\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d574d3a1-56ec-457d-ab44-f730a12bd438\"><strong>What is the average speed calculation formula?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-0-d574d3a1-56ec-457d-ab44-f730a12bd438\">\n\n<p>Average Speed $=$ Total Distance \/ Total Time is the<strong> average speed equation<\/strong>.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-1-d574d3a1-56ec-457d-ab44-f730a12bd438\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d574d3a1-56ec-457d-ab44-f730a12bd438\"><strong>What distinguishes average speed from average velocity?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-1-d574d3a1-56ec-457d-ab44-f730a12bd438\">\n\n<p>While average velocity accounts for both magnitude and direction, average speed solely takes into consideration the amplitude of motion.<\/p>\n\n<\/div><\/div>\n\n<div class=\"wp-block-ub-content-toggle-accordion\">\n                <div class=\"wp-block-ub-content-toggle-accordion-title-wrap\" aria-expanded=\"false\" aria-controls=\"ub-content-toggle-panel-2-d574d3a1-56ec-457d-ab44-f730a12bd438\" tabindex=\"0\">\n                    <p class=\"wp-block-ub-content-toggle-accordion-title ub-content-toggle-title-d574d3a1-56ec-457d-ab44-f730a12bd438\"><strong>Can average speed be negative?<\/strong><\/p><div class=\"wp-block-ub-content-toggle-accordion-toggle-wrap right\"><span class=\"wp-block-ub-content-toggle-accordion-state-indicator wp-block-ub-chevron-down\"><\/span>\n                    <\/div><\/div><div role=\"region\" class=\"wp-block-ub-content-toggle-accordion-content-wrap ub-hide\" id=\"ub-content-toggle-panel-2-d574d3a1-56ec-457d-ab44-f730a12bd438\">\n\n<p>Average speed does not have direction and it can only be positive or zero.<\/p>\n\n<\/div><\/div>\n<\/div>","protected":false},"excerpt":{"rendered":"<p>What Is the Average Speed Formula? The average speed formula is given by the total distance traveled divided by the time taken to cover that distance. The formula to find average speed is Average speed $= \\frac{Total \\;distance}{Time}$ Observe the car in the given image. The distance it covers in the different time intervals is &#8230; <a title=\"Average Speed Formula: Definition, Examples, Facts,\u00a0 FAQs\" class=\"read-more\" href=\"https:\/\/www.splashlearn.com\/math-vocabulary\/average-speed-formula\" aria-label=\"More on Average Speed Formula: Definition, Examples, Facts,\u00a0 FAQs\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"ub_ctt_via":"","footnotes":""},"categories":[1],"tags":[],"class_list":["post-33193","post","type-post","status-publish","format-standard","hentry","category-all"],"featured_image_src":null,"author_info":{"display_name":"Mithun Jhawar","author_link":"https:\/\/www.splashlearn.com\/math-vocabulary\/author\/mithun-jhawarsplashlearn-com\/"},"acf":[],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/33193","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/comments?post=33193"}],"version-history":[{"count":9,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/33193\/revisions"}],"predecessor-version":[{"id":33219,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/posts\/33193\/revisions\/33219"}],"wp:attachment":[{"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/media?parent=33193"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/categories?post=33193"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.splashlearn.com\/math-vocabulary\/wp-json\/wp\/v2\/tags?post=33193"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}